Official Quant thread for CAT 2013

@gyrodceite said:
The domain of the function f(x) = log7{log3(log5(20x €“ x^2 €“ 91))} ?
well yaeh we can find the domain from the definition of log>0 but i just want to point here such questions can be dealt fast with options. we just have to find a point that just lies in one interval of the options and put it in the fn. to chk which is the correct one. it is the fastest and easiest way i think. works for all problems
Little Pika who is five and half years old has just learnt addition. However, he does not know how to carry. For example, he can add 14 and 5, but he does not know how to add 14 and 7. How many pairs of consecutive integers between 1000 and 2000 (both 1000 and 2000 included) can Little Pika add?
A. 150 B. 155 C. 156 D. 258 E. None of the above
@gyrodceite said:
A 25 ft long ladder is placed against the wall with its base 7 ft the wall. The base of the ladder is drawn out so that the top comes down by half the distance that the base is drawn out. This distance is in the range:A. (2, 7) B. (5, 8) C. (9, 10)D. (3, 7 ) E. None of the above__/\__ Pranam Bhai @vijay_chandola
25 ki ladder...
7 ft on floor..7 24 25 pyta...so 24 is height on wall
now top comes half the distance..means 12 ft ...so foot of ladder..21. xx
so 21.xx - 7 = 14.xx
none of the above?
@gyrodceite said:
The domain of the function f(x) = log7{log3(log5(20x €“ x^2 €“ 91))} ?
log3(log5(20x-x^2-91)>0
log5(20x-x^2-91)>1
20x-x^2-91>5
x^2-20x+96
x(8,12)

EDITED
@gyrodceite said:
The domain of the function f(x) = log7{log3(log5(20x €“ x^2 €“ 91))} ?
log function is defined only for +ve values

=>log3(log5(20x-x^2-91) > 0
=>log5(20x-x^2-91) >1
=>(20x-x^2-91) >5
=>x^2-20x+96
=>(x-12)(x-8)

=> 8

ATDH.
There are four machines in a factory. At exactly 8 pm, when the mechanic is about to leave the factory, he is informed that two of the four machines are not working properly. The mechanic is in a hurry, and decides that he will identify the two faulty machines before going home, and repair them next morning. It takes him twenty minutes to walk to the bus stop. The last bus leaves at 8 :32 pm. If it takes six minutes to identify whether a machine is defective or not, and if he decides to check the machines at random, what is the probability that the mechanic will be able to catch the last bus?
A. 0
B. 1/6
C. 1/4
D. 1/3
E. 1
@gyrodceite said:
A 25 ft long ladder is placed against the wall with its base 7 ft the wall. The base of the ladder is drawn out so that the top comes down by half the distance that the base is drawn out. This distance is in the range:A. (2, 7) B. (5, 8) C. (9, 10)D. (3, 7 ) E. None of the above__/\__ Pranam Bhai @vijay_chandola
(5,8)?
@pankaj1988 said:
20x-x^2-91>0(x-7)(x-13)x is (8,12)
(x-7)*(x-13)

How come (8,12)?

ATDH.
@gyrodceite said:
A 25 ft long ladder is placed against the wall with its base 7 ft the wall. The base of the ladder is drawn out so that the top comes down by half the distance that the base is drawn out. This distance is in the range:A. (2, 7) B. (5, 8) C. (9, 10)D. (3, 7 ) E. None of the above__/\__ Pranam Bhai @vijay_chandola
let the height drawn out be x

==> (7+2x)^2+(24-x)^2=25^2
==> 5*x^2-20*x=0
==> x=0, 4 (0 not possible)

=> distance of base drawn out=2*4=8
Option b mai small bracket h to answer should be (5) :splat:

@anytomdickandhary said:
(x-7)*(x-13) How come (8,12)?ATDH.
Sir at x=7 and x=13 quantity inside log will be 0
@pussu01 said:
well yaeh we can find the domain from the definition of log>0 but i just want to point here such questions can be dealt fast with options. we just have to find a point that just lies in one interval of the options and put it in the fn. to chk which is the correct one. it is the fastest and easiest way i think. works for all problems
This should be your back up option for the exams. You cannot always rely on these techniques while preparing for XAT. Paper is highly conceptual and one of the toughest MBA entrance exam! :)
@gyrodceite said:
There are four machines in a factory. At exactly 8 pm, when the mechanic is about to leave the factory, he is informed that two of the four machines are not working properly. The mechanic is in a hurry, and decides that he will identify the two faulty machines before going home, and repair them next morning. It takes him twenty minutes to walk to the bus stop. The last bus leaves at 8 :32 pm. If it takes six minutes to identify whether a machine is defective or not, and if he decides to check the machines at random, what is the probability that the mechanic will be able to catch the last bus?A. 0 B. 1/6C. 1/4D. 1/3E. 1
1/6

Edited.. calc mistake
@gyrodceite said:
Little Pika who is five and half years old has just learnt addition. However, he does not know how to carry. For example, he can add 14 and 5, but he does not know how to add 14 and 7. How many pairs of consecutive integers between 1000 and 2000 (both 1000 and 2000 included) can Little Pika add?A. 150 B. 155 C. 156 D. 258 E. None of the above
i think it should be 258 or none of these feeling lazy to calculate exactly 9and 0 wala cases :P
@gyrodceite said:
There are four machines in a factory. At exactly 8 pm, when the mechanic is about to leave the factory, he is informed that two of the four machines are not working properly. The mechanic is in a hurry, and decides that he will identify the two faulty machines before going home, and repair them next morning. It takes him twenty minutes to walk to the bus stop. The last bus leaves at 8 :32 pm. If it takes six minutes to identify whether a machine is defective or not, and if he decides to check the machines at random, what is the probability that the mechanic will be able to catch the last bus?A. 0 B. 1/6C. 1/4D. 1/3E. 1
there are 4!/(2!2!) =6 possible ways to arrange (N,N,D,D)
there are two cases in which mechanic will be able to catch the bus. i.e NNDD and DDNN

hence 2/6 = 1/3.
@gs4890
Thanks... but
@milestogo3 Nam myoho ho rengey kyo..!!! I didn't you too from SGI..


Could you please explain the step..
I am not aware about the correct steps required for approximation...


@pankaj1988 said:
Sir at x=7 and x=13 quantity inside log will be 0
understand that! but using (x-7)*(x-13)

ATDH.
@gyrodceite said:
There are four machines in a factory. At exactly 8 pm, when the mechanic is about to leave the factory, he is informed that two of the four machines are not working properly. The mechanic is in a hurry, and decides that he will identify the two faulty machines before going home, and repair them next morning. It takes him twenty minutes to walk to the bus stop. The last bus leaves at 8 :32 pm. If it takes six minutes to identify whether a machine is defective or not, and if he decides to check the machines at random, what is the probability that the mechanic will be able to catch the last bus?A. 0 B. 1/6C. 1/4D. 1/3E. 1
selection of 2 machines can be done in 4C2=6 ways
now, when first 2 machine selected will be faulty, he will be able to catch the bus.
Alternatively, when first 2 machines he selected will be okay, he can still catch the bus (rest 2 will be faulty)

==> probability=2/4C2=1/3
@anytomdickandhary said:
understand that! but using (x-7)*(x-13) ATDH.
Oh sorry sir....sabke ans dekh kar mai biased ho gaya tha...I thought its integers falling in that region...Thanks for pointing.
Thanks again
@soumitrabengeri said:
I am guessing that N stands for not defective and D stands for defective..For the case NNDD..won't it take him 24 mins to check all the machines? How will he be able to catch the bus then?Please correct me if i am wrong
If first 2 are non defective means rest of the 2 machines are defective toh 12 mins hi lagenge..:)
1/2 x 1/3 + 1/2 x 1/3 = 1/3
@gyrodceite said:
If first 2 are non defective means rest of the 2 machines are defective toh 12 mins hi lagenge..
yeah..got that after i posted..so deleted my post asap..thanks for explaining..