@gs4890 said:@maddy2807@Brooklyn@sumeet1489@vijay_chandolaPFA Cat qstnFind ratio of - (area under red / area under blue)
(4-pi) : (pi-2)
side of bigger square=a
radius=a/2
smaller square=a/sqrt 2
@Brooklyn said:@gs4890 :: wats outer shape??? rectangle or square?? n same for inside
@sumeet1489 said:(4-pi)pi-2)
square,circle,square respectively
@Brooklyn said:@gs4890 :: wats outer shape??? rectangle or square?? n same for inside
a rectangle can't touch an inscribed circle on all sides if it does then it is a square I think
but inside one can be rectangle
but inside one can be rectangle
@gs4890 said:@maddy2807@Brooklyn@sumeet1489@vijay_chandolaPFA Cat qstnFind ratio of - (area under red / area under blue)
( 4-pi): (pi -2) ???
@gs4890 said:options were in percentages.These were the options -100%50%25%150%@deedeedudu@Brooklyn
75% aa rha hai mera to :/
@gs4890 said:@maddy2807@Brooklyn@sumeet1489@vijay_chandolaPFA Cat qstnFind ratio of - (area under red / area under blue)
Assuming it is a circle:
Take the radius of circle = r
Area in red = 4r^2 - pi *r^2
Area in blue = pi * r^2 - (r*sqrt(2))^2
Ratio = (4 - pi)/(pi - 2)
Take the radius of circle = r
Area in red = 4r^2 - pi *r^2
Area in blue = pi * r^2 - (r*sqrt(2))^2
Ratio = (4 - pi)/(pi - 2)
@gs4890 said:options were in percentages.These were the options -100%50%25%150%@deedeedudu@Brooklyn
4 - pi = 6/7
pi - 2 = 8/7
Ratio = 6/8 = 75%
Are you sure about the question?
pi - 2 = 8/7
Ratio = 6/8 = 75%
Are you sure about the question?
@Brooklyn bhaad mein jaaye fir :P
talked to a friend yesterday who appeared for CAT he said there was a geometry question in which it was asked to find out the shaded area but there was no shading in the figure :P
talked to a friend yesterday who appeared for CAT he said there was a geometry question in which it was asked to find out the shaded area but there was no shading in the figure :P
@nick_baba said:Let there be two lines AC and BC such that angle ACB=90. We draw circles C1,C2, ..Cn with radii R1,R2, ..Rn, (Ri > Rj , if i > j). Allthese circles are tangent to the lines AC and BC, and any two circlesCp,Cp+1(1
d)(sqrt2 +1)RN?
@nick_baba said:but hw u approached??...u r having a near miss i guess..
just a guess
i'm getting a g.p with r=(3+2root2) , but this is increasing so maybe there is a simplification, is this correct?
i'm getting a g.p with r=(3+2root2) , but this is increasing so maybe there is a simplification, is this correct?
posting again for all fellas who missed this..(post lunch sessions are too sleepy..here's a wake-up call)..
a)[(sqrt2 +1)/2]R1 b)(sqrt2 +1)R1 c)[(sqrt2 +1)/2]RN d)(sqrt2 +1)RN
Let there be two lines AC and BC such that angle ACB=90. We draw circles C1,C2, ..Cn with radii R1,R2, ..Rn, (Ri > Rj , if i > j). All these circles are tangent to the lines AC and BC, and any two circles Cp,Cp+1(1
a)[(sqrt2 +1)/2]R1 b)(sqrt2 +1)R1 c)[(sqrt2 +1)/2]RN d)(sqrt2 +1)RN
18?
@krum said:just a guessi'm getting a g.p with r=(3+2root2) , but this is increasing so maybe there is a simplification, is this correct?
we'll get a GP. n then we have to extend it for infinite one...there u'll get a relation between Ri and Ri+1...and ans is not d)
sab goemetry ke piche pade ho :banghead:
ye lo
Ten tickets are numbered 1,2,3.........10. six tickets are selected at random one at a time with replacement. what is the prob that largest no. appearing on the selected ticket is 7 is ??