In a certain town, every girl is acquainted with more boys then girls.Furthermore, all the girls acquainted with a given boy are also acquaintedwith each other.Thena) The number of boys is always greater than the number of girls.b) The number of girls is always greater than the number of boys .c) There are at least as many boys as girls in the town .d) There are at least as many girls as boys in the town.P.S.-- a dream town for all guys..
every prime number is of the from 6k+-1p^2 + 3p − 1=>(6k+1)^2+18k+2=>36k^2+30k+3or=>(6k-1)^2+18k-4=>36k^2+6k-3as both are multiples of 3, only p=3 will give a prime numberb)1 i expanded [(b − c)^2 + (c − a)^2 + (d − b)^2]=>b^2+c^2-2bc+c^2+a^2-2ac+d^2+b^2-2dbas a,b,c,d are in g.p =>b^2=ac, c^2=bd=>b^2+c^2-2bc+c^2+a^2-2b^2+b^2+d^2-2c^2=>a^2+d^2-2bc=>a^2+a^2r^6-2ar^3=>(a-ar^3)^2=>(a-d)^2
In a certain town, every girl is acquainted with more boys then girls.Furthermore, all the girls acquainted with a given boy are also acquaintedwith each other.Thena) The number of boys is always greater than the number of girls.b) The number of girls is always greater than the number of boys .c) There are at least as many boys as girls in the town .d) There are at least as many girls as boys in the town.P.S.-- a dream town for all guys..
bhai 1?? sirf 3??pahele tho option dala But here is my approachall prime numbers are of the form 6K+-1exception being 2 and 3so first tested with these 2 values and got only 3 satisfying Now prime numbers are of the form 3k+-1 (not all though)so substititing 3k+1 in pwe get 9K^2+12k+3in these 9K^2 can never be of the form 6k+-1 similarly 12k ab 3 tho 3 hi hoga... in all d cases it is not a prime.same holds true for 3k-1 case.
Suppose K be the number of integers n such that (1+2^n)/n^2 is also an integer.Then K isa) 0 b) 1 c) 2 d) 3also, what will be the sol to this.and whether there will be an even solution or not??
Suppose K be the number of integers n such that (1+2^n)/n^2 is also an integer.Then K isa) 0 b) 1 c) 2 d) 3also, what will be the sol to this.and whether there will be an even solution or not??
..u got it right this time..
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