@grkkrg sir explain in detail i didnot get ur approach
no sir
Each of the boys has to have unique number of berries. (to minimize same number of berries with the boys) Start with boy1 getting 1 berry, boy2 getting 2 berries and so on.. The closest summation less than 80 is from 1 to 12 12 * 13/2 = 78 So boys 1 to 12 get 1 to 12 berries. Now 2 berries are left out and 2 boys are left out. Distribute one berry to each boy. Boy1,boy13 and boy14 will have 1 berry each.
14 boys went to collect berries and returned wd total of 80 berries among themselves. Every boy collected at least 1 berry each then what is the minimum no. of students who have collected same number of berries?
in a bag, there are total 150 coins of 1rs, 50ps, 25ps. if the total value of the coins is 150rs, then how many rs can be constituted by 50ps coins?162028none of theseapproach plz
only one possible condition is that all 150 coins are of Rs.1
@bullseyes i understand the concept you're using here but in the case of 18 wouldnt i still have to find the 13th factor, which itself is difficult. am i right or am i missing something?
Which of the following statement is definitely true? 1) The above equation has no integer solutions for x, y, z. 2) The above equation has finitely many distinct integer solutions for x, y, z. 3) The above equation has 2 distinct integer solutions for x, y, z. 4) The above has infinitely many integer solution for x, y, z.