Official Quant thread for CAT 2013

@sauravd2001 said:
@grkkrg sir explain in detail i didnot get ur approach
no sir

Each of the boys has to have unique number of berries. (to minimize same number of berries with the boys)
Start with boy1 getting 1 berry, boy2 getting 2 berries and so on..
The closest summation less than 80 is from 1 to 12
12 * 13/2 = 78
So boys 1 to 12 get 1 to 12 berries.
Now 2 berries are left out and 2 boys are left out.
Distribute one berry to each boy.
Boy1,boy13 and boy14 will have 1 berry each.

@bullseyes said:
14 boys went to collect berries and returned wd total of 80 berries among themselves. Every boy collected at least 1 berry each then what is the minimum no. of students who have collected same number of berries?
3 people will have 1 berry each

rest will have diff no's of berries

So, 3 ?
@krum i dont have the options oranswers to this.. can u please elaborate on your approach
@realslimshady 18is 45? and 26 is 180
@realslimshady said:
If all factors of 720 are written in increasing order then which factors occupy the 18 and 26 position?

1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 30 36 40 45 48 60 72 80 90 120 144 180 240 360 720
Have i missed out any?
I think the answer should be 40 and 144
@realslimshady said:
If all factors of 720 are written in increasing order then which factors occupy the 18 and 26 position?
45 and 145?
@audiq7 said:
in a bag, there are total 150 coins of 1rs, 50ps, 25ps. if the total value of the coins is 150rs, then how many rs can be constituted by 50ps coins?162028none of theseapproach plz
:splat: only one possible condition is that all 150 coins are of Rs.1

NOT
@realslimshady said:
@krum i dont have the options oranswers to this.. can u please elaborate on your approach
26th we can backtrack
30th-720
29th-360
28th-240
27th-180
26th-144

@soumitrabengeri said:
1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 30 36 40 45 48 60 72 80 90 120 144 180 240 360 720Have i missed out any?I think the answer should be 40 and 144
Isn't it a very time saving approach 😛 :splat:
@gs4890 said:
Isn't it a very time saving approach
:P
I know of no other approach..did it orally..so didn't take a lot of time for me actually..took a lot of time to type though..
@gs4890 26 is 144 and 18 is 40
@krum even i considered bactracking. but it becomes useless in case of
18
@maddy2807 as i said,sorry but i dnt have the answers. :/

in these questions option play a big big role

@realslimshady said:
If all factors of 720 are written in increasing order then which factors occupy the 18 and 26 position?
for finding this.. remember the concept of placement of factors..

for 26.. all u need to find is the 5th factor. which is 5.. hence 720/5 = 144
same wd 18.
@bullseyes yesh thats the best way out if u have confusing options
@sauravd2001 said:
@bullseyes yesh thats the best way out if u have confusing options
no need of looking into options in this case.. remember, that product of first and last, second and second last and so on result in the number itself.
@bullseyes i understand the concept you're using here but in the case of 18 wouldnt i still have to find the 13th factor, which itself is difficult. am i right or am i missing something?
@realslimshady thats why i said options but he didnot agree
Consider the following equation;

x^2 + y^2 + z^2 = (x €“ y)(y €“ z)(z €“ x)

Which of the following statement is definitely true?

1) The above equation has no integer solutions for x, y, z.
2) The above equation has finitely many distinct integer solutions for x, y, z.
3) The above equation has 2 distinct integer solutions for x, y, z.
4) The above has infinitely many integer solution for x, y, z.