@sujamait said:0 apples walo ka kuch lena dena hee nhn hai .they are out of picture.
kyu bhai, jab 8 mein se 5 children ko 5 apples de diye to bache hue 3 children ko 0 apples meil gaue naa ? becuause isme at max 1 apple bola hai :(
@Torque024 said:
no idea how to geenralise it...may be using AP..
@rachit_28 said:kyu bhai, jab 8 mein se 5 children ko 5 apples de diye to bache hue 3 children ko 0 apples meil gaue naa ? becuause isme at max 1 apple bola hai
han toh..0 mile but uska abhi Q mein kya effect ? hamein toh 5 mein distribute karne hein..
baaki 3 se kya matlab ? thats what i meant.
In how many ways can we choose a black and a white square on a chess board if the two squares do not belong to the same row or column?
@rachit_28 said:In how many ways can we choose a black and a white square on a chess board if the two squares do not belong to the same row or column?
32*24
@rachit_28 said:In how many ways can we choose a black and a white square on a chess board if the two squares do not belong to the same row or column?
32*24 ways
How many integers between 100 and 500 have their digits in the increasing order ?
With approach :)
any fast way !!
@rachit_28 said:In how many ways can we choose a black and a white square on a chess board if the two squares do not belong to the same row or column?
32*24 ways
see for example select white square in 32 ways
now in that row you'll have 4 black sqs
and in that col you'll have 4 black sqs
so from the 32 black squares remove 8 =32-8=24
therefore 32*24
@rachit_28 said:How many integers between 100 and 500 have their digits in the increasing order ?With approach
ans = 74
reply with confirmation pls
@sujamait said:any fast way !!
can't think of doing it in any other way than manually..a similar question had appeared in my CAT paper..
@rachit_28 said:How many integers between 100 and 500 have their digits in the increasing order ?With approach
first place 1 =>8*7/2=28
first place 2 =>7*6/2=21
first place 3 =>6*5/2=15
first place 4 =>5*4/2=10
so 74
first place 2 =>7*6/2=21
first place 3 =>6*5/2=15
first place 4 =>5*4/2=10
so 74
@rachit_28 said:How many integers between 100 and 500 have their digits in the increasing order ?With approach
1,2,3,4,5
start wid 1
8c2
start with 2
7C2
...
8c2+7c2+...+4c2
@rachit_28 said:In how many ways can we choose a black and a white square on a chess board if the two squares do not belong to the same row or column?
if i am ryt...this was a cat 2002 quetion
@soumitrabengeri said:can't think of doing it in any other way than manually..a similar question had appeared in my CAT paper..
I had one too..but not this scary calc...they shall allow calculators too in exam..I dont see any use of calculating w/o calculator.even GMAT has calc..dats y americans are smart in a way..they use wat is best available..in this case a calc..
@sujamait said:I had one too..but not this scary calc...they shall allow calculators too in exam..I dont see any use of calculating w/o calculator.even GMAT has calc..dats y americans are smart in a way..they use wat is best available..in this case a calc..
couldn't have agreed more with what you said..
There are 7 distinct coins which r 2 b distributed randomly into 5 distinct pots in a row. Any pot can receive any no. of coins. All coins need to b distributed.
In how many ways can these coins b distributed so that no pot is empty?
In how many ways can these coins b distributed so that no pot is empty?
I approached like this:
First I distributed 1 coin in each of the pots as no pot can remain empty which can be done in 5! ways, now the remaining 2 coins can be distributed in 5*5(25) ways, so total ways = 25*5! ways. Please point out the mistake.
@rachit_28 said:There are 7 distinct coins which r 2 b distributed randomly into 5 distinct pots in a row. Any pot can receive any no. of coins. All coins need to b distributed.In how many ways can these coins b distributed so that no pot is empty?I approached like this:First I distributed 1 coin in each of the pots as no pot can remain empty which can be done in 5! ways, now the remaining 2 coins can be distributed in 5*5(25) ways, so total ways = 25*5! ways. Please point out the mistake.@soumitrabengeri@sujamait@krum
7c5*5!*5^2
@rachit_28 u need to select 5 coins out of the 7 distinct coins. so i guess ans will be 21*5!*25
correct me if wrng?
@rachit_28 said:There are 7 distinct coins which r 2 b distributed randomly into 5 distinct pots in a row. Any pot can receive any no. of coins. All coins need to b distributed.In how many ways can these coins b distributed so that no pot is empty?I approached like this:First I distributed 1 coin in each of the pots as no pot can remain empty which can be done in 5! ways, now the remaining 2 coins can be distributed in 5*5(25) ways, so total ways = 25*5! ways. Please point out the mistake.@soumitrabengeri@sujamait@krum
there will be 2 cases:
(1,1,1,1,3)=(5!/3!) * 4!
(1,1,1,2,2)=(5!/2!*2!) * 3! * 2!
Total =840
@rachit_28 said:There are 7 distinct coins which r 2 b distributed randomly into 5 distinct pots in a row. Any pot can receive any no. of coins. All coins need to b distributed.In how many ways can these coins b distributed so that no pot is empty?I approached like this:First I distributed 1 coin in each of the pots as no pot can remain empty which can be done in 5! ways, now the remaining 2 coins can be distributed in 5*5(25) ways, so total ways = 25*5! ways. Please point out the mistake.@soumitrabengeri@sujamait@krum
You were on the right track..you just forgot to multiply by 7C5...