@sauravd2001 said:@rkshtsurana bhai yeh toh samjh mein aya ki pue/4 pe max n min kaise hoga 4^(1/root2)+4^(1/root2)=2^(1+root2)?????yeh samjha
4 ^ 1/rt2 = 2^rt2
so 2^rt2 + 2^rt2 = 2* 2^rt2 = 2^ (1+rt2)
@sauravd2001 said:@rkshtsurana apne question ke option de
1. -2+sqrt(2) or -2+sqrt(3)
2 2+/-sqrt(2) or 2+/-sqrt(3)
3, -2+/-sqrt(2) or -2+/-sqrt(3)
4 -2-sqrt(2) or -2-sqrt(3)
5 + 3 =28
9 + 1 = 810
8 + 6 = 214
then 7+5 = ?
@sauravd2001 said:@rkshtsurana bhai yeh bich ke do optiob samjha kya hai yeh
2+ rt3 , 2-rt3 , 2+rt2 , 2 -rt 2....matlab + and - dono he
@rkshtsurana said:appraoch sahit plz
x(x+4)(x+1)(x+3)+2=0
(x^2+4x)(x^2+4x+3)+2=0
(x2+4x)^2+3(x2+4x)+2=0 is a quadratic
x2+4x=-1 and -2
solve,x2+4x+1=0=>x=-2+-sqrt3
and x2+4x+2=0=>x=-2+-sqrt2
@rkshtsurana said:5 + 3 =289 + 1 = 8108 + 6 = 214then 7+5 = ?
7 + 5 = 12 (last 2 digits ) 7 - 5 = 2 (1st digit)
number = 212
@rkshtsurana said:5 + 3 =289 + 1 = 8108 + 6 = 214then 7+5 = ?
easy hai bhai
212 :D
5+3 = 2(5-3) 8(5+3)
9+1 = 8(9-1) 10(9+1)
8+6 = 2(8-6) 14(8+6)
@rkshtsurana said:bhai kya aadmi ho tum..koi aesa ques he jo tum se nhi hta
bhau kabhi milna, mere jaisa lazy aur clumpy banda nai dekha hoga :p
main toh salla squrare aur sab dhondh raha tha
find the sum of squares and cubes of the root of eqaution x^3-2x^2+x-3?