5 students out of total of 3 students each from 3 different states are to be chosen for national integration camp.If each state is to have at least one representation,in how many ways van the selection be made?
India and pakistan play a series of 7 one-day matches.Each match can be won,lost or drawn.If we are to forecast the results of these matches,then how many different forecasts will contain exactly 5 correct results
Yea it was a mis-print.. Expand (1+2)^7 and see the term with 2^2. i.e. the answer. Here we have expanded 3^n , we have three options to do with 7 matches these are won, lost or drawn. n i s the number of matches. so 3^7 is the total number of possible cases. out of which.. 7C2 X 2^2 is the required term.. :) hope u got it..
hey thankuuu so much, I gt ur point...bt is there any other way of doing this question.. or can you explain it a little more,i mean some generalised concept..
hey thankuuu so much, I gt ur point...bt is there any other way of doing this question.. or can you explain it a little more,i mean some generalised concept..
If you find binomial theorem approach difficult, you can try this: You can select 5 matches out of 7 in 7C5 ways, whereas the wrong ones can be further arranged in 4 ways, say if the 6th and 7th match are won by India, you can predict, a (draw,draw),(loss,draw), (draw,loss), (loss,loss)
5 students out of total of 3 students each from 3 different states are to be chosen for national integration camp.If each state is to have at least one representation,in how many ways van the selection be made?
hi puys!! plz tell what's wrong in my approach...
First of all we can choose 3 people from each state:-3c1*3c1*3c1 the rest two can be from any state which can be choosen from rest 6 people in 6c2 ways... so answer come out to be 3c1*3c1*3c1*6c2=27*15=405
Hi, A small confusion.. While arranging N letters to make different possible words ... what shall we assume, does it mean that we have to make N lettered words OR all possible words ? Mentioning below questions for reference.
Q.1) How many words,with or without meaning,can be formed using ROCKET ?
Q.2) How many words, with or without meaning, without repetition, can be formed using TRIANGLE, where words should start with 'T' & end with 'E' ?
Hi, A small confusion.. While arranging N letters to make different possible words ... what shall we assume, does it mean that we have to make N lettered words OR all possible words ? Mentioning below questions for reference.
Q.1) How many words,with or without meaning,can be formed using ROCKET ?
Q.2) How many words, with or without meaning, without repetition, can be formed using TRIANGLE, where words should start with 'T' & end with 'E' ?
I think you should check options. If both the answers are there, then you should pick one in which number of all the possible words are found
1) For ROCKET, if all letters are used, then 6!, else 6 + 6^2 + 6^3 + .. + 6^6 (if repetition is allowed) Else, 6! + C(6, 5)*5! + C(6, 4)*4! + C(6, 3)*3! + C(6, 2)*2! + 6
2) here TE are fixed, so 6!, if all letters are used, else Same as in previous case, except that in both the cases their will be addition of 1 when their is no letter between T and E
Hi Puys,
Can someone please explain the method for solving below problems!
1) No. of ways of distributing 'n' similar objects into 'r' similar groups.
2) No. of ways of distributing 'n' distinct objects into 'r' similar groups.
Thanks in adv. Anupam
I think there is no general formula for that, if you have some specific question in mind, then you can ask that.
12 villages in a district are divided into 3 zones wid 4 villages per zone.The telephone dept. tends to connect the villages with tellephone lines ssuch that every two villages in the same zone are connected wid 3 direct lines and every 2 villages belonging to different zones are connected wid 2 direct lines.How many direct lines are required?????