Quant by Arun Sharma

asima · August 20, 2007, 2:54pm

The ans will be a)
The final value she will have to pay is = 1.07*2568 = 2748(after rounding off)
After the reduction she will have to pay = 2568...

Diff = 2748 - 2568 = 180...

i have a doubt ..plzz clarify..
if we take the approach as let the reduced cost of the radio =x;
then 1.07 * x = 2568
=> x= 2400
diff. = 2568-2400= 168
whats wrong in this approach??

jigar_desai · August 20, 2007, 6:28pm

My answer for this one comes out to (c). But Arun SHarma it's given as (a)

Percentages LOD II

Ques 35. Reema goes to a shop to buy a radio costing Rs.2568. The rate of sales tax is 7% and the final value is rounded off to the next higher integer. She tells the shopkeeper to reduce the price of the radio so that she has to pay Rs. 2568 inclusive of sales tax. Find the reduction needed in the price of the radio.
(a)Rs. 180 (b)Rs.210 (c)Rs.168 (d)None of these

Read the whole question properly this time... The ans will be c) as per asima's approach...

@asima... Thanks for correcting me..

@SeriousSam... I did a double check in the book....Thats a printing mistake there bcoz if u see the solution they have given in the Hints & Solutions Section....their ans also comes to 168... Hence c) is correct....

serioussam · August 23, 2007, 3:13pm

few more

Percentages LOD III
Ques 7. A clock is set right at 12 noon on Monday. It loses % on the correct time in the first week but gains % on the time during the second week. The time shown on Monday after two weeks will be
(a) 12:25:12 (b)11:34:48 (c)12:50:24 (d)None of these
Two friends Shayam and kailash own two versions of a car. Shayam owns the diesel version of the car, while kailash owns the petrol version.
Kailash's car gives an average that is 20% higher than Shayam's (in terms of litres per kilometre). It is known that petrol costs 60% of its price higher than diesel.
Ques 13. The ratio of the cost per kilometer of Kailash's car to Shayam's car is
(a) 3:1 (b) 1:3 (c) 1.92:1 (d)Can't be determined

answer should be (c) for this but it's given as (a) in Arun Agarwal

LOD II
Ques 33. Price of a commodity is first increased by x% and then decreased by x%. If the new price is K/100, find the original price.
(a)(x-100)100/K (b)(x^2 - 100^2)100/K (c)(100-x)100/K (d)100K/(100^2-x^2)

crack_this_time · August 26, 2007, 8:18am

hi there i found this difficult to crack:

Q)In a bag there are 150 coins of Re 1, 50p, 25p denominations. If the total value of coins is Rs150, then find how many rupees can be constituted by 50p coins.

Its in Averages chapter of Arun Sharma. Q84 LOD I

cheers

gaurishankar · August 26, 2007, 8:42am

hi there i found this difficult to crack:

Q)In a bag there are 150 coins of Re 1, 50p, 25p denominations. If the total value of coins is Rs150, then find how many rupees can be constituted by 50p coins.

Its in Averages chapter of Arun Sharma. Q84 LOD I

cheers

it is zero for 50p coins & 25 paise coins
no 50paise & 25 paise coins

ansi · August 26, 2007, 12:43pm

few more

LOD II
Ques 33. Price of a commodity is first increased by x% and then decreased by x%. If the new price is K/100, find the original price.
(a)(x-100)100/K (b)(x^2 100^2)100/K (c)(100-x)100/K (d)100K/(100^2-x^2)

Assume the original price to be 100.
Now after the increment the price will become (100 + x).
After the decrement the price will be (100 + x) - (100 + x)x/100
ie (100^2 - x^2)/100.
This is equal to K/100 ie K = 100^2 - x^2.
Subsitute in the options u will get the answer as (d).

ansi · August 26, 2007, 12:53pm

Mr. A is a Computer programmer. He is assigned with three jobs for which the time alloted is in the ratio of 5:4:2(jobs are needed to be done individually). but due to some technical snag 10% of the time alloted to each job is wasted. thereafter, owing to lack of interest, he invests only 40%, 30%, 20% of the hours of what was actually alotted to do the three jobs individually. Find how much % of the total time allotted is the time invested by A?
a)38.33%
b)39.4545%
c)41.23%
d)Cannot be determined.

My answer comes as 32.72%. Any ideas?

prashanturm · August 26, 2007, 1:18pm

let it be 50;40 &20 hrs.=100hrs
10% wasted mean 45;36 &18
now 45*40%=18
36*30%=10.8
18*20%=3.6
---------------------
total time = 32.4
total time alloted =100
i think the answer is 32.4%

ansi · August 26, 2007, 1:34pm

let it be 50;40 &20 hrs.=100hrs
10% wasted mean 45;36 &18
now 45*40%=18
36*30%=10.8
18*20%=3.6
---------------------
total time = 32.4
total time alloted =100
i think the answer is 32.4%

I think u will find tht 50+40+20 is 110 and not 100.
Also the wasted time has no significance here.
My method was:
50*40% = 20
40*30% = 12
20*20% = 4

Total time invested = 36hrs
Total time allotted = 110hrs
ie 32.72%

cloudsonfire · August 27, 2007, 5:40am

hi there i found this difficult to crack:

Q)In a bag there are 150 coins of Re 1, 50p, 25p denominations. If the total value of coins is Rs150, then find how many rupees can be constituted by 50p coins.

Its in Averages chapter of Arun Sharma. Q84 LOD I

cheers

wats the answer ?? here r v to find the max limit of 50p. ??

cloudsonfire · August 27, 2007, 6:05am

Mr. A is a Computer programmer. He is assigned with three jobs for which the time alloted is in the ratio of 5:4:2(jobs are needed to be done individually). but due to some technical snag 10% of the time alloted to each job is wasted. thereafter, owing to lack of interest, he invests only 40%, 30%, 20% of the hours of what was actually alotted to do the three jobs individually. Find how much % of the total time allotted is the time invested by A?
a)38.33%
b)39.4545%
c)41.23%
d)Cannot be determined.

My answer comes as 32.72%. Any ideas?

Total hrs alloted = 50+40+20 = 110

10% wasted in all .Thereore utillized hrs
45,36,18

utillization after lack of intrest

40% = 180/10 hrs
30% = 108/10 hrs
20% = 36/10 hrs

Therefore %age time utillized by A =*100 = 29.454 %

cymba · August 27, 2007, 6:38am

cloudsonfire
Q)In a bag there are 150 coins of Re 1, 50p, 25p denominations. If the total value of coins is Rs150, then find how many rupees can be constituted by 50p coins.
a) 16 b) 20 c) 28 d) None of the above.

Answer: d) None of the above

Look at the ques carefully. It says there are 150 coins and value of those coins is 150. i.e all coins have to be of Re.1 denomination.
Hence, there are no 50p or 25p coins in the bag.

cloudsonfire · August 27, 2007, 6:55am

Answer: d) None of the above

Look at the ques carefully. It says there are 150 coins and value of those coins is 150. i.e all coins have to be of Re.1 denomination.
Hence, there are no 50p or 25p coins in the bag.

oops !!!! 😃 Thanks Cymba

smilingtears · August 28, 2007, 11:39pm

Hey,

Has anybody done the chapter on Inequalities from the book..?
It seems to me, it has many wrong answers.. especially in one particular section, where we should take the intersection of the results, they have calculated the answers taking union. If anybody has solved that particular chapter, please post. There are some places where I could use help. Thanks.

bawa_2007 · August 29, 2007, 2:25pm

cloudsonfire Says
oops !!!! 😃 Thanks Cymba

Hi All

I have just joined in this forum its a great effort put in by u all guys.
Please help me out to solve these problems of Arun sharma Topic Sequence and series page 70 LOD2

Que1 If a times ath term of an AP is equal to b times bth term of, them find the (a+b)th term

0
a2-b2
a-b
1
a2+b2

Que2.If xbe the first term and y be the nth term and p be the product of nth terms of GP then the value of P2 will be .

(xy)n-1
(xy)n
(xy)1-n
(xy)n/2
None of this

Please help me to answer these questions. Thanx in adcance

:

crack_this_time · August 29, 2007, 6:08pm

Permutation & combinations question:

28C2r:24C(2r-4) =225:11, find r.

asima · August 29, 2007, 10:45pm

1) let the 1st term=x
ath term= x+(a-1)d
bth term = x+(b-1)d

a{x+(a-1)d} = b{ x+(b-1)d }..on solving we get...

=> (a-b){x+(a+b-1)d}=0
since a is not equal to b;

x+(a+b-1)d=0 ..which is the (a+b)th term

2) p= x*xr* xrr*.........xr^n-1
where r is the common ratio
on solving we get...
we get p^2= x^2n * r ^(n*n-1)

where r= (y/x)^ (1/n-1)...
thus ans. = xy^n

Hi All

I have just joined in this forum its a great effort put in by u all guys.
Please help me out to solve these problems of Arun sharma Topic Sequence and series page 70 LOD2

Que1 If a times ath term of an AP is equal to b times bth term of, them find the (a+b)th term
0
a2-b2
a-b
1
a2+b2
Que2.If xbe the first term and y be the nth term and p be the product of nth terms of GP then the value of P2 will be .
(xy)n-1
(xy)n
(xy)1-n
(xy)n/2
None of this
Please help me to answer these questions. Thanx in adcance:

mejogi · August 31, 2007, 5:07am

Permutation & combinations question:

28C2r:24C(2r-4) =225:11, find r.

After reducing the expression we get

2r(2r-1)(2r-2)(2r-3)=(11*28*27*26*25)/225

2r(2r-1)(2r-2)(2r-3)=11*7*4*3*13*2 rearranging R.H.S by keeping in mind 4 terms and in which 11 and 13 are prime and very close to each other
2r(2r-1)(2r-2)(2r-3)=14*13*12*11
Hence 2r=14 => r=7 Ans.

regards
mejogi

bawa_2007 · August 31, 2007, 9:45am

1) let the 1st term=x
ath term= x+(a-1)d
bth term = x+(b-1)d

a{x+(a-1)d} = b{ x+(b-1)d }..on solving we get...

=> (a-b){x+(a+b-1)d}=0
since a is not equal to b;

x+(a+b-1)d=0 ..which is the (a+b)th term

2) p= x*xr* xrr*.........xr^n-1
where r is the common ratio
on solving we get...
we get p^2= x^2n * r ^(n*n-1)

where r= (y/x)^ (1/n-1)...
thus ans. = xy^n

Thanx alot asima for helping me out.

mejogi · August 31, 2007, 5:16pm

Hey,

Has anybody done the chapter on Inequalities from the book..?
It seems to me, it has many wrong answers.. especially in one particular section, where we should take the intersection of the results, they have calculated the answers taking union. If anybody has solved that particular chapter, please post. There are some places where I could use help. Thanks.

I m also goin through inequalities and will post if required and u can do the same.I m also trying to correct the Question or the Ans !!!!

regards
mejogi