Was there something wrong in my method? The reasons I am asking this are:
1. I also used the same condition operators as you have used. I just didn't cut the common part from both sides in both cases. 2. The reason I didn't cut the common part is that in some questions, (Solved examples especially) I noticed that you dont get the correct answer if you cut the common terms on both sides.
So how to find out when to cancel the common terms and when not to do that??? ??:
It is right to cut the common parts, If u r sure that the common part is +ve then the inequality operator doesn't changes its sense or direction or If u r sure the common part is -ve then the inequality operator changes its sense. In this case (explained by Nikolai) both the cases in case 2.. (x-4) is +ve so no change of sense of the operator.
You can ALWAYS cut out common sections.... just remember to consider two cases, and REVERSE the comparison operator in the appropriate one...
2. Let me clarify a concept Assume a this means two cases Case1 a 0
Case 2 a > b if (a-b)>0
*what you did wrong was not change the direction of the comparison operator in case 2 and thats why your answer came up wrong...
Thanks for the concept... but I DID change the operator in case 2.
I wrote this equation... x^2-7x+12 > -(x-4) and you wrote... (x-4)(x-3) > -(x-4)
So there was no difference in the equations...I just didn't cancel the common parts and I am quite confused about it... Anyway I appreciate your help... thanks buddy....
I didn't understand ur explanation. Better write the co ordinates of the 3 squares considering a 2 dimensional figure.
regards mejogi
when the two points r adjacent coordinates of other two points sre (1,1) (2,1) & (1,-1) , (2,-1) side length =1 when they r opposite coordinate is (3/2,1/2) & (3/2,-1/2) sidelength 1/2^1/2.
i've a doubt in a geometry problem of arun sharma. cant solveit. pl reply if u can do it. the problem is :If ABC is a quarter circle and a circle is inscribed in it, and if AB = 1 cm, find the radius of the smaller circle. a. 2 - 1b. (2 + 1) / 2c. 2 - d. 1 - 22Correct answer : (a)
i've a doubt in a geometry problem of arun sharma. cant solveit. pl reply if u can do it. the problem is :If ABC is a quarter circle and a circle is inscribed in it, and if AB = 1 cm, find the radius of the smaller circle. a. 2 - 1b. (2 + 1) / 2c. 2 - d. 1 - 22Correct answer : (a)
if the rad of smaller circle is r, then, r+2r=1 hence, option a
i've a doubt in a geometry problem of arun sharma. cant solveit. pl reply if u can do it. the problem is :If ABC is a quarter circle and a circle is inscribed in it, and if AB = 1 cm, find the radius of the smaller circle. a. 2 - 1b. (2 + 1) / 2c. 2 - d. 1 - 22Correct answer : (a)
let the radii of bigger and smaller circles be R and r respectively. from the centre of the smaller circle,draw 2 lines perpendicular to the radii of bigger circle to form a square. join the two centres and extend it to meet the bigger circle. distance between the two centres=rv2. so R=rv2+r =>R/r=(1+v2)/1
I saw this prob in arun sharma in probability...two hits are required to destroy a target the likeness of hitting the target is same as not hitting in each try.find the number of tries required to cause a damage of atleast 81.25%..someone post the complete problem..i dont remember it completely.. thank u
when the two points r adjacent coordinates of other two points sre (1,1) (2,1) & (1,-1) , (2,-1) side length =1 when they r opposite coordinate is (3/2,1/2) & (3/2,-1/2) sidelength 1/2^1/2.
Thanx, It was really out of mind. Actually didn't read the Q carefully. Will try not to Repeat this kind of silly mistakes.
Q.49 The base of a pyramid is a rectangle of sides 18m*26m and its slant height to the shorter side of the base is 24 m. Find its volume. (LOD I pg.206,Q49)
a) 156(407)^0.5 b)78(407)^0.5 c)312(407)^0.5 d)Data Insufficient.
Q.49 The base of a pyramid is a rectangle of sides 18m*26m and its slant height to the shorter side of the base is 24 m. Find its volume. (LOD I pg.206,Q49)
a) 156(407)^0.5 b)78(407)^0.5 c)312(407)^0.5 d)Data Insufficient.
I m getting 1560(10)^0.5 !!!
If I m wrong plz post the correct solution.
regards mejogi
ITS SHOULD BE A)156(407)^0.5 (height)^2=(24)^2-(13)^2 height h=(407)^0.5 volume of a pyramid=1/3Bh B= base area h=height volume=1/3*18*26*(407)^0.5=156(407)^0.5
Q.17(LOD I,Time and Work,Pg.146) Raju can do a piece of work in 10 days, Vicky in 12 days and Tinku in 15 days. They all start the work together, but Raju leaves after 2days and Vickey leaves 3 days before the work is completed. In how many days is the work completed? a.5 b.6 c.7 d.8
I m getting 8 days,but the ans in book is 7days !
But the Q is very simple...2 days all 3 worked....for x days only vickey and Tinku worked......for last 3 days only Tinku worked. So 2+x+3 is ans (after solving for x putting in this) "Vickey leaves 3 days before the work is completed" is not at all means any other thing than I thought. What say guys?
Q.17(LOD I,Time and Work,Pg.146) Raju can do a piece of work in 10 days, Vicky in 12 days and Tinku in 15 days. They all start the work together, but Raju leaves after 2days and Vickey leaves 3 days before the work is completed. In how many days is the work completed? a.5 b.6 c.7 d.8
Try to solve these questions using the Percentage values ... Since there individual contribution to doing each days work is 10%, 8,33% and 6.66%..
If they all do it together for 2 days half of the work is done ...then if tinku is doing 20% in the last 3 days then 30% work which is left will be done by both vicky and tinku in 2 days
Total Number of days : - 2 + 2 + 3 = 7 (The required answer...)
hi..dis pagalguy.com is actually a blessing. . awesome thread... Q37. find the power of 45 that will exactly divide 123! is? options: a)29 b)30 c)31 d)59 (lod2 number systems)
d irony is m gettin 28 as answer.... 3*3 wud b constraint rather than 5..
The answer to the question below is indeed 7 ................................................... Total Number of days : - 2 + 2 + 3 = 7 (The required answer...)
Vikas
Sorry,I did some calculation mistake. Though I didn't did it in % approach. But understand both the approach. Both the approach gives 7 as ans. Thanx for correcting.
hi..dis pagalguy.com is actually a blessing. . awesome thread... Q37. find the power of 45 that will exactly divide 123! is? options: a)29 b)30 c)31 d)59 (lod2 number systems)
d irony is m gettin 28 as answer.... 3*3 wud b constraint rather than 5..
pls post d correct solution..
me too getting 28 as ans !! Anybody there with different ans ?
me too getting 28 as ans !! Anybody there with different ans ?
the ans given is 29.... we get the power of 5 as 28..and the power of 3 as 59....but wat v want is the power of 9 so v divide 59 by 2....we get 29....still the ans shud be 28 and not 29.....it says the lower value among these will be the ans....so the lower value is 5^28.....
thanks people clearing my doubt.. 4 last my post m here again wid another ques... Number systems.. lod 3 ques 20: Q. the remainder obtained wen (43^101)+(23^101) is divided by 66 is options: a) 2 b)10 c)5 d)0
lod3 ques 21 Q. the last three digits of the 12345*54321 wil b? options: a) 865 b)745 c)845 d)945
A1: (a^n)+(b^n) is always divisible by (a+b); hence (43^101)+(23^101) will always be divisible by 43+23 = 66; hence remainder is 0
A2: last 3 digits of 12345*54321 is the same as last three digits of 345*321; multiply them both the usual way and stop when u have the last 3 digits = 745
A1: (a^n)+(b^n) is always divisible by (a+b); hence (43^101)+(23^101) will always be divisible by 43+23 = 66; hence remainder is 0
A2: last 3 digits of 12345*54321 is the same as last three digits of 345*321; multiply them both the usual way and stop when u have the last 3 digits = 745
just a small correction: (a^n)+(b^n) is always divisible by (a+b) only if n is odd. however a^n-b^n is always divisible by a-b for all n.
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