Quant by Arun Sharma

The ans for 1st Q is 20

Let n is the number of trucks initially planned
T.f. Avg. Weight taken by each truck= (60-n*0.5)/n=(n*0.5)/4

(60-n*0.5)/n=(n*0.5)/4..........1


Going through options it satisfies for n=20
(Otherwise solve the Quadratic eqn. ,If possible can be reduced in non Quadratic form)

Sorry same solution repeated twice due to some computer handling problem!! . So erased it.
Ignore this post.

Solved the 2nd Q in the below post
For the 2nd Q

Let x ( Avg. Production from 1st collective farm land)
and y ( Avg. Production from 2st collective farm land)

x=21 and y =25

Second farm Harvest 300 tons of wheat more than first.( From options all satisfies this condition)
Second farm had less 12 acres land than 1st
Going through options

=3150/21 - 3450/25
=150 - 138
=12
Hence option(a )is ans

Solve for x
3^x=7
The book says the answer is 1/log7(3) while there is another option log3(7).
Aren't both the same?
:confused:

(0.01)^x=2
Book says -2 log 2.
Shouldn't it be -(log2)/2 :confused:

Solve for x
3^x=7
The book says the answer is 1/log7(3) while there is another option log3(7).
Aren't both the same?
:confused:

(0.01)^x=2
Book says -2 log 2.
Shouldn't it be -(log2)/2 :confused:


Sorry there is no option log3(7) in the book and the ans for the Q shud be log3(7) or 1/log7(3) , as 1/log7(3) is there in option (a) hence ans

And fro the 2nd Q : U r right.The ans given in book is wrong.

Hey Pavan a sincere advice, dont take the anwers of this book too seriously...........its extremely error prone. Do this book for its questions and not fr its solutions.........

Take it frm a guy who almost did this book thrice befor takin CAT for 3 years.........dnt get bogged dwn by wrng answers!

ATB

A shipping clerk has five boxes of different but unknown weights each weighing less than 100 kg. The clerk weighs the boxes in pairs. The weights obtained are 110,112,113,114,115,116,117,118,120 and 121 kg. What is the weight of the heaviest box ?a. 60 kgb. 62 kgc. 64 kgd. Cannot be determinedThe total expense of a boarding house is partly fixed and partly varying linearly with the number of boarders. The average expense per boarder is Rs. 700 when there are 25 boarders and Rs. 600 when there are 50 boarders. What is the average expense per boarder if the no. of boarders is 100 ?a. 550 b. 580 c. 540 d. 570Answers 1.) b.2.) a

what's the remainder when 12345678910111213............................47484950 is divided by 16?.......................plz. help!

MsGOODY_2_SHOES Says
what's the remainder when 12345678910111213............................47484950 is divided by 16?.......................plz. help!


16 = 2^4.

Hence, we need to chk the last four digits of the above no. which are 4950.

Hence, it becomes: 4950 mod 16 = 6

Hope this helps. 😃

i'd like to add to the above post...

for divisibility by 2, check the last 1 digit for remainder; all the other digits are irrelevant to two (since 10, 20, 30... are all div by 2)
for divisibility by 4, check the last 1 digit for remainder; all the other digits are irrelevant to 4 (since 100, 200, 300... are all div by 4)
for 8, last 3 digits... (since 1000, 2000, 3000... are all div by

for 16, last 4 digits, (since 10000, 20000, 30000... are all div by 16)
etc...

the newspaper had arun sharma asking about div by 32 which would mean we would have to consider the last 5 digits and divide them by 32...

Anyone knows how to solve this problem

The following is known about three real nubers,x,y, and z
-4
a)-16b)-16c)-8d)-4

This is from Arun Sharma's quant book Chapter 1 LOD 1 Q:78

is the option 'a' the answer?

Anyone knows how to solve this problem

The following is known about three real nubers,x,y, and z
-4
a)-16b)-16c)-8d)-4
This is from Arun Sharma's quant book Chapter 1 LOD 1 Q:78


I would go for option a).
M= xz/y
x = -4 and z = -8 and y = 2 yields you a value of 16

while

x = 4 and z = -8 and y = 2 will give you a value of -16

------------
But as y has a range of -8 to 2 we can take y as 1 in M= xz/y that will give a range of -32 to 32 for M.

So opting for closest option i.e. -16 to 16
I would go for option a).
M= xz/y
x = -4 and z = -8 and y = 2 yields you a value of 16

while

x = 4 and z = -8 and y = 2 will give you a value of -16

------------
But as y has a range of -8 to 2 we can take y as 1 in M= xz/y that will give a range of -32 to 32 for M.

So opting for closest option i.e. -16 to 16

The answer given in the text is a.

I also tried using same approach.... but since the answer i got was -32 to 32 i got confused....

thanks for the repy...
Anyone knows how to solve this problem

The following is known about three real nubers,x,y, and z
-4
a)-16b)-16c)-8d)-4

This is from Arun Sharma's quant book Chapter 1 LOD 1 Q:78

xz range :
xz/y range :

answer option A
in 1 sec the bullet can travel 330 mtrs
1 sec=330 m
12 mins=330*12*60

and 30 secs =330*30

thus shyam approached vinay with a speed of 330*30(24-1)/30

=330*23m/s

@cloudsonfire :- Ur train has got a competetor :D


ans should be 330/23 m/s

ques: In a race of 600 metres,Ajay beats vijay by 60 meters and in a race of 500 meters Vijay beats Anjay by 25 meters.By how many margins will Ajay beat Anjay in 400 meters race? a. 48m b. 52m c. 56m d. 58m picked frm pg 278 ques 74

flanker Says
ques: In a race of 600 metres,Ajay beats vijay by 60 meters and in a race of 500 meters Vijay beats Anjay by 25 meters.By how many margins will Ajay beat Anjay in 400 meters race? a. 48m b. 52m c. 56m d. 58m picked frm pg 278 ques 74

answer is option 'd'.
let Ajay be represented by 'p', vijay by 'q' n anjay by 'r'.
p/q=600/540=200/180
q/r=500/475=180/171
so p/r=200/171.
therefore when ajay completes 200 mts anjay completes 171 mts.
so when ajay finishes 400 mtr race anjay as finished only 342 mts.
so the margin is 58m.
I guess this is a very traditional approach. if ne one knows a better n shorter method please post...
The answer given in the text is a.

I also tried using same approach.... but since the answer i got was -32 to 32 i got confused....

thanks for the repy...

some questions given in Arun Sharma are wrong n some explanations r not very satisfactory:sleepy:. however its a very good book if u wanna clear ur fundas.
flanker Says
ques: In a race of 600 metres,Ajay beats vijay by 60 meters and in a race of 500 meters Vijay beats Anjay by 25 meters.By how many margins will Ajay beat Anjay in 400 meters race? a. 48m b. 52m c. 56m d. 58m picked frm pg 278 ques 74

# In a race of 400mts when Ajay is at finishing line(end) then Vijay is at 360mts.

## So when Vijay is at 360mts Anjay should be at 342mts which is 58 mts from finishing line, so Ajay beats Anjay by 58mts.

Option D
-----------------------
# Vijay lags Ajay by 10mts per 100 mts.
## Anjay lags Vijay by 5 mts per 100 mts.