In a survey of political preference,78% of those asked were in favoured of at least one of the proposals: I, II and III. 50% of those asked favored proposal III. If 50% of those asked favoured all three of the proposals, what percentage of those asked favoured more than one of the 3 proposals.
a) 10
b) 12
c) 17
d) 22
In a survey of political preference,78% of those asked were in favoured of at least one of the proposals: I, II and III. 50% of those asked favored proposal III. If 50% of those asked favoured all three of the proposals, what percentage of those asked favoured more than one of the 3 proposals.
a) 10
b) 12
c) 17
d) 22
any thing missing here ?
no..nothing is missing...ths is the ques..
In a survey of political preferences, 78% of those asked were in favour of at least one of the proposals: I, II and III, 50% of those asked favoured proposal I, 30% favoured proposal II and 20% favoured proposal II. If 5% of those asked favoured all three of the proposals, what percentage of those asked favoured more than one of the three proposals?
(a)10 (b) 12 (c) 17 (d) 22
chk if the ans is 17??
today v solved this in quant thread
I +II + III = 78
I = 50
II = 30
III = 20
I-intersection- II = x+5
II- intersection - III = y+5
I- intersection - III =z+5
I-intersection- II- intersection - III = 5
so, u knw formula ...
78 = 50+20+30 -(x+5) -(y+5) - (z+5) + 5
so,x+y+z = 12
so more thn one of the three = x+y+z+5 = 17
(a)10 (b) 12 (c) 17 (d) 22
chk if the ans is 17??
today v solved this in quant thread
I +II + III = 78
I = 50
II = 30
III = 20
I-intersection- II = x+5
II- intersection - III = y+5
I- intersection - III =z+5
I-intersection- II- intersection - III = 5
so, u knw formula ...
78 = 50+20+30 -(x+5) -(y+5) - (z+5) + 5
so,x+y+z = 12
so more thn one of the three = x+y+z+5 = 17
divyaakanksha Saysno..nothing is missing...ths is the ques..
i didnt get u....
kanikakapur Saysi didnt get u....
whr ?? thts formula...wait vil upload pic
In a survey of political preferences, 78% of those asked were in favour of at least one of the proposals: I, II and III, 50% of those asked favoured proposal I, 30% favoured proposal II and 20% favoured proposal II. If 5% of those asked favoured all three of the proposals, what percentage of those asked favoured more than one of the three proposals?
(a)10 (b) 12 (c) 17 (d) 22
hey u've written ths ques..ths has significant amount of data..d one which i posted was
In a survey of political preference,78% of those asked were in favoured of at least one of the proposals: I, II and III. 50% of those asked favored proposal III. If 50% of those asked favoured all three of the proposals, what percentage of those asked favoured more than one of the 3 proposals.
its nt having tht much info..how to do ths..got ths ques on vidyacenter.com..
hey u've written ths ques..ths has significant amount of data..d one which i posted was
In a survey of political preference,78% of those asked were in favoured of at least one of the proposals: I, II and III. 50% of those asked favored proposal III. If 50% of those asked favoured all three of the proposals, what percentage of those asked favoured more than one of the 3 proposals.
its nt having tht much info..how to do ths..got ths ques on vidyacenter.com..
do yu knw the answer for the same ?
yup...ans is 17..
- M is a 2 digit number which has the property that: the product of factorial of its digits>sum of factorial of its digits. How many values of M exist???
Ans : 63
- Find the 28383rd term of the series 1234567891011121314.??
- if u form a subset of integers chosen from between 1 to 3000 such that no integer add up to multiple of 9, what can be the max. no of elements in the subset???
- the series of the no. (1,1/2,1/3,1/1972)is taken. Now 2 no r taken 4m dis series(the 1st 2) say x & y. then the operation x+y+xy is performed to get a consolidated no. The process is repeated. What will be the val of set aftr all the no are consoladadet to a single no.???
5 K is a 3 digit no such thT RATIO OF NUMBET TO THE SUM OF DIGITS IS LEAST. For how many values of K will the ratio be highest??
Ans : 9
- a triangular no is defnd as a no which can be expressed as a sum of consecutive natural no starting 4m 1. How mant triangular no below 1000 can be expressed as the diff of 2 consecutive natural no.?
- find the remainder when the no represented by 22334 raised to power (1^2 + 2^2 +3^2+.+66^2) is divided by 5
7.what is the remainder when (1!)2 + (2!)^2 + (3!)^2+.(1152!)^2 is divided by 1152???
Ans : 225
8.find remainder when (10^3 + 9^3)^752 is divided by 12^3
ans : 1
9.A,B & C have 80 coins.A triples no of coin with the others by giving them some coin 4m his own collection.After this B repeats the same process.After this B has 20 coins. Find the no of coins he had initially?
Ans : 10
10. What is the remainder when 2*(8!)-21*(6!) divides 14*(7!)+14*(13!)?
Ans : 7!
11. What is the rightmost digit preceding the zeros in (20)^53???
Ans : 2
12. How many integer value of x & y are there such that 4x+7y=3, while x
ans : 143
13. a supercomputer take input of no N & X where X is factor of N.In case N=83p796161q & X is equal to 11 where o
Ans : 9
14. A has a certain no of chocolates such that if he sistributes them among 10 children then 9 is left, if among 9 children the 8 is left n so on until if he distributes among 5 children 4 is left.What is the second highest no of toffees he cud have??:shock:
15. A candidate takes a test n attempts all 100 ques. While any correct ques fetches 1 marks, Wrong attempts have penalty as follows:
one tenth of ques carry 1/10 ve marks,1/5th carry 1/5 ve marks & rest carry -ve marks.Unattempted cary no marks.What is the diff between max & min he can score???
Ans : 140..:sarcasm:
ok.. i gt.. thanx.
i had given a list of questions which i am unable to solve............plz help me with them.......
Ans : 63
- M is a 2 digit number which has the property that: the product of factorial of its digits>sum of factorial of its digits. How many values of M exist???
ans : 9
- Find the 28383rd term of the series 1234567891011121314.??
ans : 1333
- if u form a subset of integers chosen from between 1 to 3000 such that no integer add up to multiple of 9, what can be the max. no of elements in the subset???
ans: 1972
- the series of the no. (1,1/2,1/3,1/1972)is taken. Now 2 no r taken 4m dis series(the 1st 2) say x & y. then the operation x+y+xy is performed to get a consolidated no. The process is repeated. What will be the val of set aftr all the no are consoladadet to a single no.???
5 K is a 3 digit no such thT RATIO OF NUMBET TO THE SUM OF DIGITS IS LEAST. For how many values of K will the ratio be highest??
Ans : 9ans : 22
- a triangular no is defnd as a no which can be expressed as a sum of consecutive natural no starting 4m 1. How mant triangular no below 1000 can be expressed as the diff of 2 consecutive natural no.?
ans : 4
- find the remainder when the no represented by 22334 raised to power (1^2 + 2^2 +3^2+.+66^2) is divided by 5
7.what is the remainder when (1!)2 + (2!)^2 + (3!)^2+.(1152!)^2 is divided by 1152???
Ans : 225
8.find remainder when (10^3 + 9^3)^752 is divided by 12^3
ans : 1
9.A,B & C have 80 coins.A triples no of coin with the others by giving them some coin 4m his own collection.After this B repeats the same process.After this B has 20 coins. Find the no of coins he had initially?
Ans : 10
10. What is the remainder when 2*(8!)-21*(6!) divides 14*(7!)+14*(13!)?
Ans : 7!
11. What is the rightmost digit preceding the zeros in (20)^53???
Ans : 2
12. How many integer value of x & y are there such that 4x+7y=3, while x
ans : 143
13. a supercomputer take input of no N & X where X is factor of N.In case N=83p796161q & X is equal to 11 where o
Ans : 9
14. A has a certain no of chocolates such that if he sistributes them among 10 children then 9 is left, if among 9 children the 8 is left n so on until if he distributes among 5 children 4 is left.What is the second highest no of toffees he cud have??:shock:
15. A candidate takes a test n attempts all 100 ques. While any correct ques fetches 1 marks, Wrong attempts have penalty as follows:
one tenth of ques carry 1/10 -ve marks,1/5th carry 1/5 -ve marks & rest carry -ve marks.Unattempted cary no marks.What is the diff between max & min he can score???
Ans : 140..:sarcasm:
Here are solutions to 4 of the problems.
- M is a 2 digit number which has the property that: the product of factorial of its digits>sum of factorial of its digits. How many values of M exist???
Can be solved using a crude counting way.
From 11 to 20 - 0
21-30 - 23 to 29 - 7 numbers
31-39 - 32 to 39 - 8 numbers
Similarly for numbers till 99, for each ten numbers, we will have 8 of them satisfying the condition. 8*7 + 7 = 63.
- the series of the no. (1,1/2,1/3,1/1972)is taken. Now 2 no r taken 4m dis series(the 1st 2) say x & y. then the operation x+y+xy is performed to get a consolidated no. The process is repeated. What will be the val of set aftr all the no are consoladadet to a single no.???
This is also can be solved on the basis of generalization.
Take the first 2 numbers. 1,1/2. Apply the operation i.e. 1+1/2 + (1*1/2) = 3/2 + = 2.
Repeat. 2, 1/3 -> 2+1/3 + 2*1/3 = 7/3 + 2/3 = 3
You can clearly see, when we took the first two terms, we got the next digit. So if we repeat the process, the last pair of numbers left will be 1971, 1/1972, If we apply the same operation to this pair, we will get the answer as 1972.
- the series of the no. (1,1/2,1/3,1/1972)is taken. Now 2 no r taken 4m dis series(the 1st 2) say x & y. then the operation x+y+xy is performed to get a consolidated no. The process is repeated. What will be the val of set aftr all the no are consoladadet to a single no.???
This is also can be solved on the basis of generalization.
Take the first 2 numbers. 1,1/2. Apply the operation i.e. 1+1/2 + (1*1/2) = 3/2 + = 2.
Repeat. 2, 1/3 -> 2+1/3 + 2*1/3 = 7/3 + 2/3 = 3
You can clearly see, when we took the first two terms, we got the next digit. So if we repeat the process, the last pair of numbers left will be 1971, 1/1972, If we apply the same operation to this pair, we will get the answer as 1972.
15. A candidate takes a test n attempts all 100 ques. While any correct ques fetches 1 marks, Wrong attempts have penalty as follows:
one tenth of ques carry 1/10 -ve marks,1/5th carry 1/5 -ve marks & rest carry -ve marks.Unattempted cary no marks.What is the diff between max & min he can score???
Ans : 140..
In this case the maximum marks the candidate can obtain is 100.
The lowest marks will be when he gets all 100 questions wrong. The score in this case will be :
Since 1/10th questions carry -ve 1/10 marks, the score for the 10 questions(100/10) will be -10/10 = -1 mark.
1/5th questions carry -ve 1/5marks, the score for these 20 questions will be -20/5 = -4 marks.
Rest questions carry -1/2 marks i.e. -(100-10-20 questions)/2 = -35 marks.
Adding all these we get, -1 -4 -35 = -40
Diff. betn max and min = 100 - (-40)= 140
11. What is the rightmost digit preceding the zeros in (20)^53???
Ans : 2
Soln - 20^53 = (2*10)^53
= 2^53 + 53(........) + 10^53
= 2^53 (cycle of 4) gives u 2 as the last digit.
The remaing two in the equation have the last digit as 0..
Hence 2..
Have sum work right now.. will get back with all the solutions in a while..
Cheerz
u applied binomial here ..man hows it possible.....its not (x+y)^n instead it is 2^53*10^ 53 if v ignore 10^53 v r left wid 2^53 now (2^10)^5 *2^3
(2^10)^odd always have 24 as last two digits so 4*8 so last digit is 2
Q1)M is a 2 digit number which has the property that: the product of factorial of its digits>sum of factorial of its digits. How many values of M exist???
let the number be ab. For a!*b! > a!+b!
This is possible if both a and b are greater than 1.
Since its a 2 digit no a can take 9 values and b can take 10 values. Total we have 90 2 digit nos.
The given conditions will not be satisfied for following scenarios.
1) a=1 , b=any value; 10 digits
2)a>1, b= 0 or 1; 16 values
3)a=2,b=2; 1 value
Hence total values for which the condition is satisfies is 90-27 = 63
hey i didnt get u... can u xplain once again....
kanikakapur Sayshey i didnt get u... can u xplain once again....
Consider a 2 digit no 1b(b is any digit)
then the conditions 1!(1) * b!
Consider no a0 then a! * 0!(1)
Lastly consider 22. 2!*2! = 2! +2!
Hope that its now clear
Hi guys...I am finding some trouble in solving Arun Sharma, Quant.... there are lot of questions with no explanation....can u tell me from where to get ans..... thnks
here are 2 ques.
Ques.1- N=202*20002*200000002*2-----(15 zero)2*2---(31 zero)2.
total sum of digit in this multiplication will be???
a) 112, b) 160 c) 144, cant be determine.
ques 2- 10^n -(5+(17)^1/2) is divisible by 2^(n+2) for what whole no value of n??
a) 2 b)3, c) 7 ,d) 8 ,e) none of these
here are 2 ques.
Ques.1- N=202*20002*200000002*2-----(15 zero)2*2---(31 zero)2.
total sum of digit in this multiplication will be???
a) 112, b) 160 c) 144, cant be determine.
ques 2- 10^n -(5+(17)^1/2) is divisible by 2^(n+2) for what whole no value of n??
a) 2 b)3, c) 7 ,d) 8 ,e) none of these
N = 202 x 20002 x 200000002 x 2..(15 zeros)..2 x 2 ...(31 zeros) ...2 sum of the digits in this multiplication is
Individual digit sum = 4
4^5 = 1024. = 7 check from options...160 has a digit sum of 7 so the answer or else u can go by traditional way
= (202*20002) = 4040404 = 16
so going by the tresnd the answwer willl be 160
for second question check the terms i think u have committed the typo eerror