Quant by Arun Sharma

MBA CAT 2022
954

definitely cannot be determined

955
let,questions right be x
questions wrong y
not attempted z
x+y+z=80
x-0.5y-0.25z=34.5
1.5y+1.25z=45.5
6y+5z=182----(1)
6x+z=298-----(2)
5x-y=218-----(3)
if x=45,y=7,z=28
if x=48,y=22,z=10
if x=54,y=52=>not possible
as you can see from the options too,2 cases are possible,and also,as there are 2 equations for 3 variables.i think,it cannot be determined.

what does the original solution say??


Hi
They dont have solution, but our answer is right. 😃 thanks buddy
956

Some uestions from BLock 1 Number systems LOD 2

26 . greatest integer value just below X and {x} its fractional value.
the sum of ^2 and {x}^1 is 25.16 find X.

  1. 5.16
  2. -4.84
  3. both 1,2
  4. 4.84
  5. Can't be determined.

48. If we divide a two digit number by sum of its digit, we get 4 quotient and 3 as a remainder. If we divide the two digit number by the product of its digits, we get 3 as quotient and 5 as a remainder. Find the two digit number.

No option.


70. A triangular number is defined as a number which has property of being expressed as sum of consecutive natural numbers starting with 1. How many triangular numbers less than 1000, have property that they are the difference of square of two consecutive natural numbers.


  1. 20
  2. 21
  3. 22
  4. 23


Thanks in advance.
Please reply ASAP.
:)
957
Some uestions from BLock 1 Number systems LOD 2

26 . greatest integer value just below X and {x} its fractional value.
the sum of ^2 and {x}^1 is 25.16 find X.

  1. 5.16
  2. -4.84
  3. both 1,2
  4. 4.84
  5. Can't be determined.
48. If we divide a two digit number by sum of its digit, we get 4 quotient and 3 as a remainder. If we divide the two digit number by the product of its digits, we get 3 as quotient and 5 as a remainder. Find the two digit number.

No option.


70. A triangular number is defined as a number which has property of being expressed as sum of consecutive natural numbers starting with 1. How many triangular numbers less than 1000, have property that they are the difference of square of two consecutive natural numbers.


  1. 20
  2. 21
  3. 22
  4. 23

Thanks in advance.
Please reply ASAP.
:)



26 . greatest integer value just below X and {x} its fractional value.
the sum of ^2 and {x}^1 is 25.16 find X.

  1. 5.16
  2. -4.84
  3. both 1,2
  4. 4.84
  5. Can't be determined
if we take option 1 then 5^2+0.16=25.16 means satisfy
option 2 then -4.84 means value=-5 so -5^2+0.84=25-0.84


i am not sure for option 1 and 3 becaseu for -4.84 fraction value for -5 may be 0.16 so possiblem ans option 2 also

so ans may be 1 or 3 option
958
26 . greatest integer value just below X and {x} its fractional value.
the sum of ^2 and {x}^1 is 25.16 find X.

  1. 5.16
  2. -4.84
  3. both 1,2
  4. 4.84
  5. Can't be determined
if we take option 1 then 5^2+0.16=25.16 means satisfy
option 2 then -4.84 means value=-5 so -5^2+0.84=25-0.84


i am not sure for option 1 and 3 becaseu for -4.84 fraction value for -5 may be 0.16 so possiblem ans option 2 also

so ans may be 1 or 3 option



48. If we divide a two digit number by sum of its digit, we get 4 quotient and 3 as a remainder. If we divide the two digit number by the product of its digits, we get 3 as quotient and 5 as a remainder. Find the two digit number.

here if two digit number is 10a+b

then 4(a+b)+3=3ab+5

means 4(a+b)=3ab+2

now take (a+b)=5 so ab=6 so possible number is 32 or 23

but only 23 satisfy condition

so ans is 23
959
48. If we divide a two digit number by sum of its digit, we get 4 quotient and 3 as a remainder. If we divide the two digit number by the product of its digits, we get 3 as quotient and 5 as a remainder. Find the two digit number.

here if two digit number is 10a+b

then 4(a+b)+3=3ab+5

means 4(a+b)=3ab+2

now take (a+b)=5 so ab=6 so possible number is 32 or 23

but only 23 satisfy condition

so ans is 23



Hi Jigar,
How did you pluged in a+b =5? It was just guess or any other trick?
960
Hi Jigar,
How did you pluged in a+b =5? It was just guess or any other trick?


firts if u take a+b=1 then

LHS =4 and RHS=5

a+b=2 then LHS=8 RHS =8 now a+b=2 ab=2 not a=b=1 but not satisfy ab=2

now a+b=3 and 4 not satisfy for LHS & RHS

so finally got at 5
961
Some uestions from BLock 1 Number systems LOD 2

70. A triangular number is defined as a number which has property of being expressed as sum of consecutive natural numbers starting with 1. How many triangular numbers less than 1000, have property that they are the difference of square of two consecutive natural numbers.


  1. 20
  2. 21
  3. 22
  4. 23

Thanks in advance.
Please reply ASAP.
:)


the triangular numbers are 1,3,6,10,15,21,28,36,45,55...990=>45 terms

2a+1=n(n+1)/2

now,lhs=3,5,7,...all odd terms except 1

now,odd terms are found,as 2 odd:2 even....so,23 odd and 22 even.now,1 is not included,so,22 numbers.

option (3)
962

LOD 2 : Speed time and distance
Question number : 33
Ravi , who lives in the country side caught a train for home earlier than usual yester day.His wife normally drives to the station to meet him.But yesterday he set out on foot
From the station ot meet his wife on the way.He reached home 12 min earlier than he would have done had he waited at the station for his wife.
The car travels at uniform speed,which is 5 times ravis speed on foot.Ravi reached home at exactly 6 o clock.At what time would he have reached home if his wife,forewarned
Of his plan had met him on the station?
a) 5:48
b) 5:24
c) 5:00
d) 5:36

963
LOD 2 : Speed time and distance
Question number : 33
Ravi , who lives in the country side caught a train for home earlier than usual yester day.His wife normally drives to the station to meet him.But yesterday he set out on foot
From the station ot meet his wife on the way.He reached home 12 min earlier than he would have done had he waited at the station for his wife.
The car travels at uniform speed,which is 5 times ravis speed on foot.Ravi reached home at exactly 6 o clock.At what time would he have reached home if his wife,forewarned
Of his plan had met him on the station?
a) 5:48
b) 5:24
c) 5:00
d) 5:36


he reached home 12 min before,what he would have normally reached on car.
let time taken by foot be t1,by car be t2

x(t1)=5x(t2)
t1=5t2

but,

t1-t2=12

t2=3 min
t1=15 min

so,he reached station at 5.45 pm

so,by car,he would have reached at 5.48 pm

so,option (A)

is that correct?
964
LOD 2 : Speed time and distance
Question number : 33
Ravi , who lives in the country side caught a train for home earlier than usual yester day.His wife normally drives to the station to meet him.But yesterday he set out on foot
From the station ot meet his wife on the way.He reached home 12 min earlier than he would have done had he waited at the station for his wife.
The car travels at uniform speed,which is 5 times ravis speed on foot.Ravi reached home at exactly 6 o clock.At what time would he have reached home if his wife,forewarned
Of his plan had met him on the station?
a) 5:48
b) 5:24
c) 5:00
d) 5:36


My answer is 5:36
Explanation:

He reached 12 min before means he met somewhere at a place where it take another 6 min for the car( and 30 min to Ravi) to reach the station.

So if his wife forewarned then he would have saved (30-6) min while going from station to home. So in that case he will reach by (6:00 - 00:24) = 5:36.
965

can we sub divide this thread by Chapter wise. So it would be easy to find and post relevent questions pertaining to that particular chapter.

Does this make sense?

Thanks.

966

Two normal dices r thrown.Given taht sum of dice is less than or equal to 4 , find probability that only one dice shows two....ANSWER is 1/3.
plz someone solve the question.

967
Two normal dices r thrown.Given taht sum of dice is less than or equal to 4 , find probability that only one dice shows two....ANSWER is 1/3.
plz someone solve the question.


please see the other thread,where you have posted the same query

http://www.pagalguy.com/forum/quantitative-questions-and-answers/14041-quant-marathon-82.html#post1378158

hope that helps.
968

Plz try this Find the sum of series 1/1X5+1/5X9+1/9X13 .......+1/221X225

969
Amit31 Says
Plz try this Find the sum of series 1/1X5+1/5X9+1/9X13 .......+1/221X225


you mean

1/(1.5)+1/(5.9)+1/(9.13)+....+1/(221.225),right?

it comes out to be

1/4(1-1/5+1/5-1/9+.....1/221-1/225)

1/4(224/225)

56/225.

hope that helps.
970

arun , bikas and chetkar have a total of 80 coins among them. arun triples coins with others by giving them some coins from his oown collection,bikas repeats same process . now bikas has 20 coins fin number of coins he had at beginning??

971
Amit31 Says
arun , bikas and chetkar have a total of 80 coins among them. arun triples coins with others by giving them some coins from his oown collection,bikas repeats same process . now bikas has 20 coins fin number of coins he had at beginning??


So they have a, b and c number of coins.
Given, a + b + c = 80 or 2a + 2b + 2c = 160............ (I)
Now let the no. of coins distributed by 'a' be x
Then x = 2(b + c)..................(II)
Thus the no. of coins with them now are a - x, 3b, 3c respectively.
Now let 'b' distribute t coins between a and c.
Then t = 2(a - x + 3c)............(III)
And the no. of coins with them is 3(a - x), 3b - t, 9c
Given that 3b - t = 20..............(IV)
From (III) we get 3b - t = 3b - 2(a - x + 3c)
From (II) and (IV) we get, 20 = 3b - 2a + 4b + 4c - 6c
or 7b - 2a - 2c = 20.............(V)
Solving (I) and (V), we get 9b = 180, or b = 20.....
972

Hi,please help me in number systems doubt

1. Find the remainder when 73 x 75 x 78 x 57 x 197 is divided by 34

my solution : 5 x 7 x 10 x 23 x 27/34

35 x 10 x 23 x 27/34

26 x 27/34

702/34

remainder = 22, but book answer is 32

973
Hi,please help me in number systems doubt

1. Find the remainder when 73 x 75 x 78 x 57 x 197 is divided by 34

my solution : 5 x 7 x 10 x 23 x 27/34

35 x 10 x 23 x 27/34

26 x 27/34

702/34

remainder = 22, but book answer is 32


ya u r absolutely right and arun sharma absolutely wrong

i checked it and ans is 22