a) 96% b) 51.1% c) 90% d) none
Vicky's salary is 3/4(75%)th more than Ashu's salary. So it will be easier to solve the problem if we take Ashus salary as a multiple of 4.
So we take their salary as:
Ashu Vicky
Original
salary 40 40 + 3/4*40 = 70
( 3/4 th of 40)
New salary 40*125/100 = 50 70*140/100 = 98
Hence we find that Vicky's salary is more than Ashu's saalry by (98-50) 48
So percentage will be 48/50*100 = 96%
Hence option (a) alone follows.
I ahve tried to explain the problem , in case of any doubts plz Reply.
Actually I am also going through theis chapter and I am facing some doubts too. I will be posting them in a few days.
hii...
i juz came across this thread. this is a gr8 initiative.
for your first question, i dont really hav a clear cut methodology of solving, but one can do this question be observation:
put x=1, we get f(1).f(1)=2.f(1)
from here we get f(1) to be 0 or 2
put x=4 and let f(1/4) be a
65a=65+a
a=65/64
Now u can c a trend that f(4)=65= (4)^3+1
f(1)=2= 1^3+1
f(1/4)=65/64=(1/4)^3+1
So, then f(x)= x^3+1
therefore, f(6)=6^3+1=217 (Though this is just a jugaadoo solution and not a scientific method of approch)
Question2:
term inside log shudnt be equal to zero and should be >0
(5x-x^2)/4 is not equal to 0=> x is not equal to 0 or 5
(5x-x^2)/4>0 => x lies between 0 and 5
Therefore, x shud lie between 0 and 5, excluding 0 and 5, so i think the first choice shud be (0,4], otherwise nthin else fits
Question 3:
here too x^3-x is not equal to 0 and >0 => x is not equal to -1,1,0 nd lies between (-1,0)U(1, infinity)
4-x^2 is not equal to 0 => x is not equal to 2,-2. Therefore the answer shud be (c)
for this i thin ans should be 37
for f(x)=1+x^2 ( for x=even)
otherwise (1+x^2)
g(x)= (x-1)^2 (for x=prime)
other wise x^2-1
based on the above formula
solve and we get answer as 37
Q.The height of triangle increased by 40%.What can be the maximum increase in length of the base, so that the increase in area is restricted to a maximum of 60%
(a) 50 (b)20 (c) 35 (d)25
Q. 4/5th of the voters in Barrely promised to vote for Sonia gandhi and the rest promised to vote for Sushma Swaraj . Of these voters 10% of the voters who had promised to vote for Sonia Gandhi , did not vote on the election day.What is the total no. of votes polled if Sonia Gandhi got 216 votes ?
(a) 200 (b)300 (c) 264 (d) 100
Q. Maya has Rs M with her and her friend Chanda has Rs C with her . maya spends 12 % of her money and Chanda also spends the same amount as Maya did .What percentage of her money did Chanda spend ?
(a) 18M/C (b) 18C/M (c) 12M/C (d) 12C/M
Q. In a village consisting of P persons , X% can raed as well as write .Of the males alone y% and of the females alone only z% can raed as well as write ,Find the nomber of males in the village?
(a) p(x-y)/(x+y-z) (b) p(x-z)/(y+x-2z) (c) p(y-x)/(x-z) (d) p(x-z)/(y-z)
Q. Australia scored a total of x runs in 50 overs . India tied the scores in 20 overs less. If India's average run rate ad been 33.33% higher the scores would have been tied10 overs earlier.
Find how many runs were scored by Australia?
(a) 250 (b) 240 (c) 200 (c) can not be determined
(a) 200 (b)300 (c) 264 (d) 100
Let the total no of votes be 100.
4/5th votes out of 100 is 80
out of these 10% people were not voted means 10% of 80 is 72,
so If total votes are 100 sonia got 72 votes,
if total are 300 then sonia will get 216 votes(cross method)
hope it was correct.
I think u will find tht 50+40+20 is 110 and not 100.
Also the wasted time has no significance here.
My method was:
50*40% = 20
40*30% = 12
20*20% = 4
Total time invested = 36hrs
Total time allotted = 110hrs
ie 32.72%
little bit confusion i think some other method must be there for this is any one there help me out for this particula question on page21
Q. 4/5th of the voters in Barrely promised to vote for Sonia gandhi and the rest promised to vote for Sushma Swaraj . Of these voters 10% of the voters who had promised to vote for Sonia Gandhi , did not vote on the election day.What is the total no. of votes polled if Sonia Gandhi got 216 votes ?
(a) 200 (b)300 (c) 264 (d) 100
Let the total no of votes be 100.
4/5th votes out of 100 is 80
out of these 10% people were not voted means 10% of 80 is 72,
so If total votes are 100 sonia got 72 votes,
if total are 300 then sonia will get 216 votes(cross method)
hope it was correct.
total vote =x
4/5 for sonia but in during election 4/5*0.90x=216
so x=300:tongue:
Great!!!!!!!!! Can someone plz explain the other 4 questions?
@jigar_p_civil
The answer you arrived at is valid ,had the question been what is total no. of voters in barrely instead of total no. of votes polled.
Correct me if I ma wrong.
Yeah u r absolutely right !!!!!!
The answer to the question is option (c) 216 can anyone plz explain?
:tellme:
3) 3rd Question ans :Maya spends :12M
chaya spends the same amount ie 12M
Hence 12M is what % of Chaya's Money C is given by 12M =C (%)
hence % =12M/C
Ans (c)
4)
Total People in village :P
Let Number of males be M
Let number of Females be :F
Total people who can read and write :XP
Males who can read and write :yM
Females who can read and write :z(P-M)
Hence XP=yM+zP-zM
XP-zP=(y-z)M
M= P(X-z)/(y-z)
Ans (d)
5)Australias run rate is x/50
India's run rate is x/30 ,i.e 20 overs less
had it been 33.33% more i.e 4/3 of x/30
then India would complete scores in 10 overs less i.e total of 20 overs
equation is 4/3* (x/30)=x/20
Hence due to x on both sides ,
ans is (d) cannot be determined
Hi,Please help me in getting the solution for the below mentioned question.
A team of miners planned to mine 1800 tons of ore during a certain number of days.Due to technical difficulties in one-third of the planned number of days,the team was able to achieve an output of 20 tons of ore less than the planned output.To make up for this,the team overachieved for the rest of the days by 20 tons.The end result was that the team completed the task one day ahead of time.How many tons of ore did the team initially plan to ore per day?
Ans- 100 tons.
This question is from Arun Sharma (Averages- LOD III ,ques 29).
Thanks in advance!
Hi,Please help me in getting the solution for the below mentioned question.
A team of miners planned to mine 1800 tons of ore during a certain number of days.Due to technical difficulties in one-third of the planned number of days,the team was able to achieve an output of 20 tons of ore less than the planned output.To make up for this,the team overachieved for the rest of the days by 20 tons.The end result was that the team completed the task one day ahead of time.How many tons of ore did the team initially plan to ore per day?
Ans- 100 tons.
This question is from Arun Sharma (Averages- LOD III ,ques 29).
Thanks in advance!
let number of planned days be d
work per day be w
wd=1800
(w-20)d/3+(w+20)2d/3=1800+w+20
20d=3w+60
36000=3w^2+60w
on solving,
w=-120 or w=100
as work done is positive,
w=100 tonnes
This is a caselet from Averages, Arun Sharma , page 111.
I am looking for the method to solve the 48th question pertaining to the case on page 112. Have reproduced some facts of the case.
Runs scored / over in diff styles : D- defensive, N - normal, A - aggressive
D N A
Tendulkar 4 6 8
Ganguly 3 4 5
Kumble 2 3 4
harbhajan3 4 5
Srinath 3 4 5
Yohanna 2 3 4
India has to score 360 runs on last day of test match having 90 overs to win the match. They are chasing a score of 411/7 declared by opponents.
Assume that tendulkar walks in after fall of 5th wicket and shares partnerships with the players (below him in the order in which they are listed in the table) who have batted normally (n) , defensively(d), d, d, d, and d respectively in the order of players listed after tendulkar. Sachin has played normally(n) with ganguly and agressively with others .
Sachin's partnerships with Ganguly , Kumble, Bhajji, Sri and Yohannan lasted for 12, 10, 8 , 5 and 10 overs respectively. He has shared strike equally with ganguly and kept 2/3 strike in other 4 partnerships.
If India proceeded to win the match, based on runs scored in last 5 partnerships, assuming tht last wicket pair was unbeaten, whats the max score at which sachin could have come to bat
Options: 103/5 97/5 100/5 104/5
Thanx ..
x^2-2x-3
Please solve the inequality. This is a question from quant by arun sharma.
options:
1. 1
4.2
x^2-2x-3
Please solve the inequality. This is a question from quant by arun sharma.
options:
1. 12.-2 3. x>5
4.2
Two cases:
i) x2-2x-3>0 =>(x-3)(x+1)>0=>x>3 and x>-1=>x>3 OR xx
which makes the inequality as:
x2-2x-3x2-5x x(x-5)0
Now take intersection of (1) and (2),
This gives us 3
ii) x2-2x-3(x-3)(x+1)-1
which makes the inequality as
x2-2x-3>3x-3 =>x2-5x>0=> x(x-5)>0=> x>5 OR x
Now take intersection of (1) and (2),
This gives us -1
Hence from 1 and 2,
Gives the solution set as:
3
Two cases:
i) x2-2x-3>0 =>(x-3)(x+1)>0=>x>3 and x>-1=>x>3 OR xx
which makes the inequality as:
x2-2x-3x2-5x x(x-5)0
Now take intersection of (1) and (2),
This gives us 3
ii) x2-2x-3(x-3)(x+1)-1
which makes the inequality as
x2-2x-3>3x-3 =>x2-5x>0=> x(x-5)>0=> x>5 OR x
Now take intersection of (1) and (2),
This gives us -1
Hence from 1 and 2,
Gives the solution set as:
3
Thanks... solved almost in the same but in a diferrent way 😉
hi,
pls solve the following..
1)A milk man sold his buffalo at Rs.720/- at some profit.Had he sold his buffalo at Rs.510/-, the quantum of the loss incurred wud have been double that of profit earned. What is the cost price?
a)600 b)625 c)675 d)none
2)A Shopkeeper buys an article for Rs.400 and marks it for sale at a price that gives him 80 % profit on his cost.He however gives a 15% discount on the Marked price to his customer. Calculate the actual profit % made by shopkeeper ?
a)62% b)64% c)53% d)54%
3)Mithilesh makes 750 articles at a cost of 60 paise per article.He fixes the seeling price such tha if only 600 articles are sold,he would have made a profit of 40% on the outlay.However 120 articles got spoilt and he was able to sell 630 articles at this price.Find his actual profit percent of total outlay assuming that he unsold articles are useless.
a)42% b)53% c)47% d)46%
hi,
pls solve the following..
2)A Shopkeeper buys an article for Rs.400 and marks it for sale at a price that gives him 80 % profit on his cost.He however gives a 15% discount on the Marked price to his customer. Calculate the actual profit % made by shopkeeper ?
a)62% b)64% c)53% d)54%
Its c) 53%.
The price which he marks for the article to sell at a profit of 80% is Rs. 720.
But he gives discount of 15% ,so he sells it at Rs. 612.
So net profit % is (612-400)/4= 53
Its c) 53%.
The price which he marks for the article to sell at a profit of 80% is Rs. 720.
But he gives discount of 15% ,so he sells it at Rs. 612.
So net profit % is (612-400)/4= 53
my approach
lets say he buys at 100
80% profit makes it 180 n after discount of 15%=27 rs mks it 153 rs so profit is
53
time saver i think