hey puys i am getting pissed with this question pls help me crush this out.... here goes the ques....
Circles are drawn with four vertices as the centre and radius equal to the side of a square. If the square is formed by joining the mid points of another square of side 2root(6), find the common area to all the four circles.
This question can be found in arun sharma pg:345 (chapt -11 , LOD-2 mensuration q.no. 43)
Kindly post the method used...i got the diagram but m not able to get the required area....heeeeeelp
hey puys i am getting pissed with this question pls help me crush this out.... here goes the ques....
Circles are drawn with four vertices as the centre and radius equal to the side of a square. If the square is formed by joining the mid points of another square of side 2root(6), find the common area to all the four circles.
This question can be found in arun sharma pg:345 (chapt -11 , LOD-2 mensuration q.no. 43)
Kindly post the method used...i got the diagram but m not able to get the required area....heeeeeelp
Dint understand whether the side of the square u have mentioned is 2sqrt(6) or just sqrt(6).. Can you please clarify ??
Could any of you suggest me the books to be followed for CAT exam (any e-books/online resources) ? I've over 3+ yrs of exp in s/w(Banking Domain). Looking fwd for guidance from CAT 2008 aspirants.
Could any of you suggest me the books to be followed for CAT exam (any e-books/online resources) ? I've over 3+ yrs of exp in s/w(Banking Domain). Looking fwd for guidance from CAT 2008 aspirants.
1)(173)^45 * (152)^77 * (777)^999 Options are-2,4,6,8 I am getting the Answer as 2,by applying the Euler Theorem in the middle one as the first and third term will reduce to one.Hence 2^5 % 10 wud give 2...But the Answer given is 8...
2)55^75 * 93^175 * 107^275 Options are 7,3,5,0 By applying Euler Theorem,I m getting the Remainder as 5,Moreover,it seems it is appropriate to get 5 at units place becoz of 55 term..But again much to the surprise,the answer is 7....
1)(173)^45 * (152)^77 * (777)^999 Options are-2,4,6,8 I am getting the Answer as 2,by applying the Euler Theorem in the middle one as the first and third term will reduce to one.Hence 2^5 % 10 wud give 2...But the Answer given is 8...
2)55^75 * 93^175 * 107^275 Options are 7,3,5,0 By applying Euler Theorem,I m getting the Remainder as 5,Moreover,it seems it is appropriate to get 5 at units place becoz of 55 term..But again much to the surprise,the answer is 7....
here 173^45 cyclicity of 3 =3,9,7,1 45/4=reminder=1 so last digit=3
152^77 last digit=2 777^999 last digit=3
so last digit=3*2*3=18 last digit= 8
2)55^75 * 93^175 * 107^275 Options are 7,3,5,0 By applying Euler Theorem,I m getting the Remainder as 5,Moreover,it seems it is appropriate to get 5 at units place becoz of 55 term..But again much to the surprise,the answer is 7....
here 55 so last digit always 5 just need to care no any power of 10
Hello, Just created account on PG and also in the starting of my CAT 09 prep :).Some queries frm Arun sharma: 1.Unit digit of (12^55/3^11)+(8^48/16^1 8 )--Number system --LOD 2. I am getting as 0 , but answer is 4 2.Greater among--111^4 and 109*110*112*113---Number sys -LOD2 Also frm where can I study the euler's theorem being discussed here? Do respond!!
hello, just created account on pg and also in the starting of my cat 09 prep :).some queries frm arun sharma: 1.unit digit of (12^55/3^11)+(8^48/16^1 8 )--number system --lod 2. I am getting as 0 , but answer is 4 2.greater among--111^4 and 109*110*112*113---number sys -lod2 also frm where can i study the euler's theorem being discussed here? Do respond!!
1. (12^44)*(4^11) + 2^72 = 4 + 6 = last digit is 0 2. 111^4 will be greater...there is a theorem which says that if sum of quantities is equal, product is greatest when quantities are equal
Hello, Just created account on PG and also in the starting of my CAT 09 prep :).Some queries frm Arun sharma: 1.Unit digit of (12^55/3^11)+(8^48/16^1 8 )--Number system --LOD 2. I am getting as 0 , but answer is 4 2.Greater among--111^4 and 109*110*112*113---Number sys -LOD2 Also frm where can I study the euler's theorem being discussed here? Do respond!!
hey thnxx a ton for the sol...your method and ans is rt:) but how did u get angle of sector as 30?
If u see the sides of the triangle formed are in the ratio 1:root3:2..... from this angle of the triangle can be calculated as 60deg..therefore angle of the sector is 30 deg