SSC CGL 2014 TIER 2

If x = r sinA cosC, y = r sinAsinC and z = r cosA, then x^2 + y^2 + z^2 = ?

(A) r

(B) r^2

(C) 2r^3

(D) r^3

Due to an increase of 25% in the price of tea a man can buy 3 kg less for Rs. 600. find the present price of tea. @mba__ 

If (tanθ+cotθ)/ (tanθ−cot θ )= 2, (0

then the value of sin θ is

(a) 2 /√3

(b) √3/2

(c) 1 /2

(d) 1

A reduction of 20% in the price of sugar enables a person to buy 5 kg more sugar for rs 400. find the difference between original and present price.

a reduction of 20% in the price of salt enables a person to buy 4 kg more salt for rs 100. find the decreased price of salt.

If sec^2θ+tan^2θ = 7 /12 , then sec^4 θ - tan^4 θ

(a) 7/12

(b) 1/ 2

(c) 5 /12

(d) 1

If 2 - cos^2 θ = 3 sin θ cos θ, sin θ ≠ cos θ

then tan θ be 

(a) 1/2

(b) 0

(c) 2/3

(d) 1/3

 If A and B are complementary angles, then the value of Sin A cos B + cos A Sin B - tan A tan B + sec^2 A - cot^2 B is

 (a) 2

(b) 0

(c) 1

(d) -1


If sin θ + cos θ = √2 cos (90- θ), then cot θ is

(a) √2+1

(b) 0

(c) √2

(d) √2-1

plzz explain


If x sin^3 θ + y cos^3 θ = sin θ cos θ and x sin θ = y cos θ, sin θ ≠ θ, cos θ ≠ 0, then x^2 + y^2 is

 (a) 1 /√2

(b) 1 /2

(c) 1

(d) √2

The value of (1 + sec 20° + cot 70°)(1-cosec20° + tan 70°)

(a) 0

(b) -1

(c) 2

(d) 1


The area was blocked ___ during the demonstration.


The problem boils __ to a lack of money


 few horses broke ____ from the paddock.

1) It was decided to break __diplomatic 
  relations with that country.
2) She broke ___ in the middle of a sentence 3.Rioting broke __ as a result of the strike.


You pretended to be a journalist and he believed you?
I never thought you'd bring that __!

Mary decided to brush up __her Spanish before going to South-America.


The fuse has burnt ____.

Two sides of a rectangle are measured.One of the sides (length) was measured 10% more than its actual length and the other side(width) was measured 5% less than its actual lenth.The % error in measure obtained for the area of the rectangle is 

A work complete by 120 labourers in 15days.How many labourers will complete the same work in 10 days?

No OA.