Bhai aa gya to CAT wale hume kahi ka nhi chodenge....
toh fir kya hi kar sakte hain...yaa to poem haad easy hogi yaa haad mushkil...joh hoga dekha jayega...mentally prepared raho toh sab hojayega...aur yeh toh bas ek chotti si BILLI hain..
@nits2811 said: Choose the grammatically correct sentence as ur option
A) She recommended that John should take the ferry.
B) She recommended that John takes the ferry.
C) She recommended that John had taken the ferry.
D) She recommended that John take the ferry.
@nits2811 option A, nt sure though, my logic was the frst part f sentence thr is a suggestion which is provided so it shud b followed with 'should' in the second part...
In ΔABC, D is the midpoint of BC. E is a point on AC such that AE : EC = 2 : 1 and F is a point on AB such that AF : FB = 3 : 1. Line segments AD and FE intersect at point O. What is the ratio of the area of ΔDOF to the area of ΔDOE?
a8 : 9
b9 : 8
c3 : 4
d4 : 3
any easy approach for this questn, the solution provided by CL went above my head...
In ΔABC, D is the midpoint of BC. E is a point on AC such that AE : EC = 2 : 1 and F is a point on AB such that AF : FB = 3 : 1. Line segments AD and FE intersect at point O. What is the ratio of the area of ΔDOF to the area of ΔDOE?
a8 : 9
b9 : 8
c3 : 4
d4 : 3
any easy approach for this questn, the solution provided by CL went above my head...
In ΔABC, D is the midpoint of BC. E is a point on AC such that AE : EC = 2 : 1 and F is a point on AB such that AF : FB = 3 : 1. Line segments AD and FE intersect at point O. What is the ratio of the area of ΔDOF to the area of ΔDOE?
a8 : 9
b9 : 8
c3 : 4
d4 : 3
any easy approach for this questn, the solution provided by CL went above my head...
In ΔABC, D is the midpoint of BC. E is a point on AC such that AE : EC = 2 : 1 and F is a point on AB such that AF : FB = 3 : 1. Line segments AD and FE intersect at point O. What is the ratio of the area of ΔDOF to the area of ΔDOE?
a8 : 9
b9 : 8
c3 : 4
d4 : 3
any easy approach for this questn, the solution provided by CL went above my head...
since DOF and DOE has same base OD so area of DOF : area of DOE = perpendicular of triangle DOF : perpendicular of triangle DOF => area of DOF : area of DOE =area of ADF : area of ADE ( as they have same base AD)
take total area = 24 so area ADB = area ADC =12 (median) DF divide ADB in 1:3 so area ADF = 3/4 *12 =9 DE divide ADC in 1:2 so area ADE = 2/3 *12 =8 hence 9:8