CHSL & FCI PREPARATION

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730
1(1/2) =
(1*1)/2=1/2
1+ 1/2=(2+1)/2=3/2

731

The digit place of the number represented by (7^95-3^58)m



a.
b.3
c.6
d. 4
732

i m unable to reply...............toh post krna to dur ki baat hai.........thread nt available ke link pr click krne pr bhi reply post nhi hua..............

733
to all
i will suggest you to bring question on HCF and LCM tmrw..

i wont bring more than 5 question.. rest you guys have to bring..it takes my too much time to do all this thing and all the questions are already done by me..

so if you guys will share also than i will be interested or else.. i will stop ..
734
@surajpandey wrong
735
@custom said:
The digit place of the number represented by (7^95-3^58)m
a.
b.3
c.6
d. 4
my take d........correct me if i m wrong
736
@custom said:
The digit place of the number represented by (7^95-3^58)m
a.
b.3
c.6
d. 4
d????
737
@custom said:
The digit place of the number represented by (7^95-3^58)m
a.0
b.3
c.6
d. 4
yeh tho karo
738

gotta go..............neeni aa rahi hai...............gd ngt.........

739
@custom said:
The digit place of the number represented by (7^95-3^58)m
a.
b.3
c.6
d. 4
4 aayega.
cyclicity use karni hai
740
@surajpandey said:
4 aayega. cyclicity use karni hai
explain please
741
@surajpandey said:
first wala half hai and 2nd wala 1 and half hai

@coolparul007

ohh u are thinking it multiply no re im writing it as there se no way to write mixed fraction
1(1/2) = 3/2

742
@surajpandey said:
4 aayega. cyclicity use karni hai
Unit digits of 7 and 3 both gets repeat after squaring 4 times

3,9,7,1 - For squares of 3
7,9,3,1- for squares of 7

7^95 = {(7^4)^23} * 7^3 =1* 7^3 = 343 (we are taking digits up to 3 places in this case because in question we have to find difference between two ...if product has to find, we would have taken only 3(unit digit) from 343)

Same with 3^58= {(3^4)^14} *3^2 = 1 * 9= 9

7^95 - 3^58 = 343-9= 4 at last digit.
743
@surajpandey said:
Q5
what no. should be added to 231228 to make it exactly divisible by 33.
need shortest way to calculate this.
so please give reasons in supprt of ur answers.
if this no. is exactly divisible by 33 than this no. has to be divisible by 11 and 3 both 231228 is divisible by 3 but it gives reminder 8 when diveded by 11 so if we add 3 than it also divisible by 11
744
@custom said:
The digit place of the number represented by (7^95-3^58)m
a.
b.3
c.6
d. 4
this qustion done by cyclicity method cyclicity of 7 and 3 is 4 than ans is 4

745

hii everyone...can i join u guys??? took some time to put myself togather after d SSC mains....will keep trying and not loose hope...:)

746
@anticipator.lad said:
HCF LCM- Revision
This link will be active for tonight only, as it contained some piracy issues, i guess... Please save it for the future...
bhaiya your efforts will definately not go in vain..i will thoroghly read this notes.. though i have already tried so many questions .
thanks again
747

any questions to be posted ?

nice summary of hcf-lcm @anticipator.lad
748
@mukul1988 said:
@coolparul007
ohh u are thinking it multiply no re im writing it as there se no way to write mixed fraction
1(1/2) = 3/2
sry my mistake..........pr paper mein bhi aise hi options aayenge to kaise pta karange ki mixed term hai ya multiply kra hai.......
749

paper main subset aur superset types aata hai toh distinguish kar sakte hai and they use * or X for product

@coolparul007 said:
sry my mistake..........pr paper mein bhi aise hi options aayenge to kaise pta karange ki mixed term hai ya multiply kra hai.......
paper main subset aur superset types aata hai toh distinguish kar sakte hai and they use * or X for product