Q on hcf and lcm
Q1-5 lets try to do
4- B aankhon se wohi solve hua mujhse sirf...baaki..copy pen leta...
2-D...aankhon se solve kiya...abhi pen copy liya nahi hun
1a 2d 3b 4b 5d
@surajpandey correct me if i m wrong
5- D- 96
@anticipator.lad said:@coolparul007 heahahaa...mere abhi sirf 3 hue and tumhare 5 ke 5....huahaha!! great speed.
mere pc table pr pen n copy padhe the isliye jaldi ho gya............
sahi hai..guys... @coolparul007 @anticipator.lad
i m done ab aur logo pe pass question hai toh please post kare
1-A
@surajpandey said:Q on hcf and lcmQ1-5 lets try to do
ques 1 (A)
sum =45
diff= 5
getting 25 and 20 lcm = 100
ques 2 d
already dicussed just look with product with last digit 1
ques 3 (b)
hcf * lcm = 13*273 = 13*13*21
now product has to be same as hcf*lcm = 13*3one no and 13*7 other no
as only 13 is hcf
another method
lcm*hcf = 13*273 = 3549 (either multiple or just come a round off value) take the root of the product now root of 3500 is close to 60 so look for values near to 60*2
ques 4 b
sum = 60
hcf =12
lcm = 6
divide sum by hcf =5
divide lcm by hcf = 6
only 2,3 fit the values with sum = 5 and product = 6 so nos would be 24,36
ques 5 d
lcm= 84 hcf
hcf = 680/85 =8
lcm = 8*84 ( dont solve )
one no =56
other = 8*8*84/56 = 96
Help me with 3... B aa to raha hai but again..without much concept...
@coolparul007 said:mere pc table pr pen n copy padhe the isliye jaldi ho gya............
koi farak nahi padta usase... exam mein sabke pass rahega...and that time you will be ahead of me... :)
@anticipator.lad said:Help me with 3... B aa to raha hai but again..without much concept...
as hcf is 13
first no. is 13a
2nd number is 13b
use formula
13a *13b = 13*273
a*b=21
it means a is 7 or 3
and b is 3 or 7
thus a +b=10 so the sum of numbers are 13(a+b)= 130
first no. is 13a
2nd number is 13b
use formula
13a *13b = 13*273
a*b=21
it means a is 7 or 3
and b is 3 or 7
thus a +b=10 so the sum of numbers are 13(a+b)= 130
apna @mukul1988 bhai ka jawab nahi....idhar mein sirf solve kar ke option likhta hun...wo bhaisaab...pura procedure operation table par kar ke rakh dete....
@surajpandey said:as hcf is 13 first no. is 13a2nd number is 13buse formula13a *13b = 13*273 a*b=21 it means a is 7 or 3 and b is 3 or 7thus a +b=10 so the sum of numbers are 13(a+b)= 130
hmmm..ab samajh gaya..thanku bhai
aur koi post kar raha ??
1) The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
A. 504 B. 536
C. 544 D. 548
2) If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:
A. 55 / 601
B. 601 / 55
C. 11 / 120
D. 120 / 11
3) The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:
A. 3 B. 13
C. 23 D. 33
4) The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
A. 74 B. 94
C. 184 D. 364
1d 2c 3c
@anticipator.lad said:1) The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:A. 504 B. 536C. 544 D. 548
bhai yeh toh easy hai. sirf 20 ko dekho... ek hi number aisa hai
548.
548.
4d since it is only one divisible by 7.........