well i'm not sure what the answer should be. but i also don't understand why 2 is sufficient. i'm not able to get any set of 5 consecutive and set of 7 consecutive integers whose sum is same.
Well Neha, U have to consider the negative integers as well. With 0 being the median of those numbers. e.g {-2 ,-1, 0, 1, 2} I hope u got wat i mean ...But the problem is the answer is not B even. The answer as given is C and there is no explanation
Well Neha, U have to consider the negative integers as well. With 0 being the median of those numbers. e.g {-2 ,-1, 0, 1, 2} I hope u got wat i mean ...But the problem is the answer is not B even. The answer as given is C and there is no explanation
When u see a set of consecutive odd number of integers , average of that set is always equal to the median , i.e mean = median for odd number of consecutive integers.. You can algebrically prove this as well ..
stament 2 is not suff ..heres why Take a case of sum which is multiple of both 5 and 7.. Say we take 35
Consider sum of S = 35 and so Sum of T =35..
S = 5,6,7,8,9 T = 2,3,4,5,6,7,8
Median of S = 7 and Median of T = 5..( Median = Avegare of such set as explained above) So in this case answer to the question "Is the median of the numbers in set S equal to the median of the numbers in set T? is 'NO'.
Other case of sum being equla could be S = 0
S = -2,-1,0,1,2 T = -3,-2,-1,0,1,2,3
But sum = 0 is also somthing which is divisible by 7 and 5 ( as 0 is divisible by all integers) Here median = 0 for both S and Y and so answer to the question "Is the median of the numbers in set S equal to the median of the numbers in set T?" is 'YES'.. Thus stmnt 2 is not sufficient
A contractor combined x tons of gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that contained 2 percent gravel G, by weight, to produce z tons of a mixture that was 5 percent gravel G, by weight. What is the value of x?
At a certain company, the average (arithmetic mean) number of years of experience is 9.8 years for the male employees and 9.1 years for the female employees. What is the ratio of the number of the company's male employees to the number of the company's female employees?
(1) There are 52 male employees at the company.
(2) The average number of years of experience for the company's male and female employees combined is 9.3 years.
The sum of three integers is 60. What is the median? 1) one of the integers is 10 2) one of the integers is 20
The OA is B.
If one of the integers is 20, there can be two cases: 1) If one of two other integers is less than 20, then the other integer should be greater than 20, in which case 20 will be the median. 2) If all the three integers are 20, then also 20 will be the median.
A contractor combined x tons of gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that contained 2 percent gravel G, by weight, to produce z tons of a mixture that was 5 percent gravel G, by weight. What is the value of x?
At a certain company, the average (arithmetic mean) number of years of experience is 9.8 years for the male employees and 9.1 years for the female employees. What is the ratio of the number of the companys male employees to the number of the companys female employees?
(1) There are 52 male employees at the company.
(2) The average number of years of experience for the companys male and female employees combined is 9.3 years.
A contractor combined x tons of gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that contained 2 percent gravel G, by weight, to produce z tons of a mixture that was 5 percent gravel G, by weight. What is the value of x?
(1) y = 10 (2) z = 16
My answer is D. Given statement gives us following 2 equations: (i) x+y=z (ii) 10x+2y=5z We have 3 variables and 2 equations and we need one more equation to solve for x, y and z.
Statement 1: y=10; we can solve for x, y and z using this 3rd equation..hence, satisfies. Statement 2: z=16; same here...we can solve for x, y and z using this 3rd equation..hence, satisfies.
At a certain company, the average (arithmetic mean) number of years of experience is 9.8 years for the male employees and 9.1 years for the female employees. What is the ratio of the number of the company's male employees to the number of the company's female employees?
(1) There are 52 male employees at the company.
(2) The average number of years of experience for the company's male and female employees combined is 9.3 years.
My answer is B.
If x & y is is the total # of males and females respectively then we need x:y?
Statement1: no help Statement2: can be rewritten as: (9.8x+9.1y)/(x+y) = 9.3. Using this equation we can solve for x:y.
What is the value of X? (A) When X is multiplied by 8, the result is between 50 and 60. (B) When X is doubled, the result is between 10 and 15. Stmt A: - 50 => X = 7 stmt B : - 10 => X = 6 , 7 So using only (A) ...but ans given ( E)
The question does not mention tht X is an integer. It can well be a decimal number which when divided by 8 result lies between 50 and 60. So there is no single answer for the question. Hence E is right.
Statement1 gives d =0.2 Stement2: hcase1: h = 4, then d = 0.246 = 0.25 = 0.3 (to nearest tenth) case2: h = 3, then d = 0.236 = 0.2 (to nearest tenth) Two different answers for d. Hence only statement1 is sufficient.
Each statement alone is sufficient A says dB says h