If w greater than 1?
1) w+2 > 0
2) w^2 > 1
Taking statement 1 ->
w > -2
so W can be -1,0,1,2,3,4.....
But NOT Sufficient
Taking statement 2 ->
w^2 > 1
means w cannot be equal to +1 or -1 or 0, but it can be 2,3,4,5.... or -2,-3,-4,-5...
So, exactly we don't know yet if w>1 or not.
Therefore, NOT Sufficient.
Taking 1 and 2 together ->
since statement 1 says w > -2, therefore w will have values =
2,3,4,5,...... hence W>1.
So, answer should be 'C' but OA is E.
Could anyone please verify where m I going wrong?
If w greater than 1?
1) w+2 > 0
2) w^2 > 1
Taking statement 1 ->
w > -2
so W can be -1,0,1,2,3,4.....
But NOT Sufficient
Taking statement 2 ->
w^2 > 1
means w cannot be equal to +1 or -1 or 0, but it can be 2,3,4,5.... or -2,-3,-4,-5...
So, exactly we don't know yet if w>1 or not.
Therefore, NOT Sufficient.
Taking 1 and 2 together ->
since statement 1 says w > -2, therefore w will have values =
2,3,4,5,...... hence W>1.
So, answer should be 'C' but OA is E.
Could anyone please verify where m I going wrong?
Nowhere its mentioned that W is integer. Consider the example of -1.5, you will get your answer.
Nitin. SaysNowhere its mentioned that W is integer. Consider the example of -1.5, you will get your answer.
Yeah, missed that silly me
thanks
Hi,
can any body explain the following question
Q)Is x a prime number
1)x 2)x-2 is a multiple of 5
Hi,
can any body explain the following question
Q)Is x a prime number
1)x 2)x-2 is a multiple of 5
A alone doesn't give any specific info.
B tells x-2 is multiple of 5 means X could be 7,12,17,21 and so on which also consist of prime as well as non prime. Combining both the two option we get are 7 and 12..one is prime and other non prime. So answer is E.
What's the OA?
combining both we get only 7,12-2 is 10 multiple of 5,so x has only one value 7.then it is C.
But the answer given E .Why?
combining both we get only 7,12-2 is 10 multiple of 5,so x has only one value 7.then it is C.
But the answer given E .Why?
Thats what I explained in my previous post 12 & 7 one is prime and one is non prime so you can't answer. Thats why its E
combining both we get only 7,12-2 is 10 multiple of 5,so x has only one value 7.then it is C.
But the answer given E .Why?
yes but dont forget that even x=12 satisfies both conditions of x being less than 15 and x-2 being a multiple of 5 .So in this case we have 1 value of x being prime ie 7 and the other value 12 not being prime . Thus answer is E
It took the bus 4 hours to get from town A to town B. What was the average speed of the bus for the trip?
1. In the first 2 hours the bus covered 100 miles
2. The average speed of the bus for the first half of the distance was twice its speed for the second half
It took the bus 4 hours to get from town A to town B. What was the average speed of the bus for the trip?
1. In the first 2 hours the bus covered 100 miles
2. The average speed of the bus for the first half of the distance was twice its speed for the second half
Average spped can be calculated by dividing total distance with totaol time.
1.Total distance is not known.So not suff
2.second also can not tell us either the pseed ot the distance so not suff
combining-
let total distance is x
so distance covered in first 2 hrs=100
distance in second 2 hrs=x-100
v1=100/2=50
v2=x-100/2
v1=2*v2=>x-100=50=>x=150
so average speed=150/4=37.5
So C
It took the bus 4 hours to get from town A to town B. What was the average speed of the bus for the trip?
1. In the first 2 hours the bus covered 100 miles
2. The average speed of the bus for the first half of the distance was twice its speed for the second half
cannot be determined combining both
first_timer Sayscannot be determined combining both
right.I made a silly mistake.
Is x
(1) x = -x
(2) x^2 > 0
Is x
(1) x = -x
(2) x^2 > 0
Edit :
From 1, x is negetive
From 2, x can be positive or negative.
So answer should be A.
Is x
(1) x| = -x
(2) x^2 > 0
Recently i have discovered that when i work with 2nd statement 1st, my answer never goes wrong. so changed my startegy of doing the ds ques from 2nd to 1st. ans that's how i'll solve it.
2) X^2>0
can't be sure x can be either positive or negative.
1) |x= -x
a) +x= -x
x+x=0 implies x=0
b) -x= -x
-x+x=0
so i'm getting x=0 only by both cases.
since answer is affirmatively NO so i think A is sufficient.
First_timer how did you get x can be zero or negative by 1st statement?
did i make some mistake?
.
First_timer how did you get x can be zero or negative by 1st statement?
did i make some mistake? :lookround:
Sorry, actually I made a mistake here.
I was working under the assumption that 0 = -0 ( generally), but the modulus function clearly states that a = a when a>=0 and a = -a when a
In that case, answer should be A only.
Recently i have discovered that when i work with 2nd statement 1st, my answer never goes wrong. so changed my startegy of doing the ds ques from 2nd to 1st. ans that's how i'll solve it.
2) X^2>0
can't be sure x can be either positive or negative.
1) x|= -x
a) +x= -x
x+x=0 implies x=0
b) -x= -x
-x+x=0
so i'm getting x=0 only by both cases.
since answer is affirmatively NO so i think A is sufficient.
First_timer how did you get x can be zero or negative by 1st statement?
did i make some mistake? :lookround:
Doubt:
|x=-x; this equation can be satisfied only if x=0 or -ve, e.g lets say x=-2, then we get 2=2. So, isn't the answer should be E?
Is x
(1) x = -x
(2) x^2 > 0
Let me clear up the doubts... according to GMAT, -0 = 0 (I remember a GMATPrep question based on this concept).
So the answer is C.
I know -0 kinda sounds meaningless (that's what I thought too) but take a look at this:
Minus zero
Let me clear up the doubts... according to GMAT, -0 = 0 (I remember a GMATPrep question based on this concept).
So the answer is C.
I know -0 kinda sounds meaningless (that's what I thought too) but take a look at this:
Minus zero
Yes thats what I thought at first, but if u take at the basic definition of modulus function ( as I already stated before ) :
a| = a when a>=0
a = -a when a
So by definition even if a = 0, then from the first relation |0 = 0 only and not -0.
Is the OA option C ? Then it's quite confusing
Is x
(1) x = -x
(2) x^2 > 0
st1.
x>0=>2x=0=>x=0
x-x=-x=>x cantake any negative integer value
so not suff
st2.
x can be either negative or positive but not 0
combining the two
It implies x is not zeroso x is negative.so c