GMAT Data Sufficiency Discussions

I remember q1 from OG where i had differed frm option C n here goes my explanation why i chose A
Statement 1 says that all sides of the hexagon are equal.....which means the figure is a regular hexagon, whose each interior angle = 120 deg
Hence diagonals of this hexagon bisect the angle and 6 triangles are formed, whose each angle = 60 deg
Hence all 6 triangles are equilateral.

Statement 2: Each diagonal bisects each other....=>does not say anything about the sides of the figure n hence is not sufficient.

OA is A
i cud nt understand the explanation either...if any of u cud explain i'll be very grateful

q2) Is it a-IbI
thanks

1. Even I thought the same when I first attempted the hexagon question. A hexagon will be regular hexagon when its six sides and six angles are equal. Statement 1 only says that the hexagon has six equal sides, a distorted/streched hexagon can be drawn with six equal sides but they won't have equal angles. Hence (1) alone is not enough.
Statement 2 is not enough as we can draw a hexagon having unequal sides which will satisfy the criteria. So, (2) alone is also not enough.

Considering both options together gives us a regular hexagon, in which case the triangles will be equilateral. Hence answer is (C).

Hope it helps

2. The inequality is -> (a |b) a b)
b is in modulus.

Three segments are drawn from opposite corners of a hexagon to form six triangles.These segments all bisect each other at point A. Are all of the triangles equilateral?

1. all six sides of hexagon are the same length
2. the three segments drawn between the opposite corners are equal length.

For the question shown above, 800 score has given an explanation for why the answer must be option (C). The link for the explanation has been pasted below:-
Explanation for GMAT MATH Test 1 Question 25

Hi.....I am struk at a silly question from the OG 11..................
Is n an integer?1)n^2 is an inetezer2)n^1/2 is an intezer
2 proofs that n is an intezer...............so the ans is B.according to me the ans should be D.because n^2=n*n......so if n^2 is an intezer n has be be an intezer........puys please help me with my silly query...........thanks in advance

Hi.....I am struk at a silly question from the OG 11..................
Is n an integer?1)n^2 is an inetezer2)n^1/2 is an intezer
2 proofs that n is an intezer...............so the ans is B.according to me the ans should be D.because n^2=n*n......so if n^2 is an intezer n has be be an intezer........puys please help me with my silly query...........thanks in advance

consider the simple example let n^2=5

but n=2.24 .......so n not necesserily be an integer......
consider the simple example let n^2=5

but n=2.24 .......so n not necesserily be an integer......


ok...got it thanks...

Statement 1 says that n^2 is an int...it does not necessarily mean that n is also an integer...n^2 may be 37 but is square root is not an integer
Statement 2 says tht n^(1/2) is an int...defnitely n would also be an integer since square of a number is always an integer

Hence OA is B

thanks

Help me out with this one guys


What is the volume of a certain rectangular solid?

(1) Two adjacent faces of the solid have areas 15 and
24, respectively

(2) Each of two opposite faces of the solid has an area of 40

Help me out with this one guys


What is the volume of a certain rectangular solid?

(1) Two adjacent faces of the solid have areas 15 and
24, respectively

(2) Each of two opposite faces of the solid has an area of 40



IMO, (1) alone is sufficient to get the volume. As the adjacent faces have areas 15 & 24, the common side has to be 3. Hence the volume has to be 3 * 8 * 5.

(2) does not say anything about the individual sides neither about the area of the base (which of course is a square).

Hence, 1 alone is sufficient to get the volume of the rectangular solid.
Help me out with this one guys


What is the volume of a certain rectangular solid?

(1) Two adjacent faces of the solid have areas 15 and
24, respectively

(2) Each of two opposite faces of the solid has an area of 40

Option - 1 : Two adjacent faces of the solid have areas 15 and 24, respectively. It means l.b = 15 and b.h = 24 where l,b,h are length, breadth and height respectivley of the rectangular solid.
One side is common to the adjacent faces whose areas we know. But, from this data we can't be sure as what's the exact l,b or h. Because there are more than one choices fit this solution such as l,b,h =

(You can take l.h also instead of l.b but that wont make any difference because ultimately we have to find l.b.h) Not sufficient.

Option - 2 : Each of two opposite faces of the solid has an area of 40. That means all the 6 faces have area = 40. Again, many possibiliteis. not sufficient.

Considering both option - A and B : They both contradict. Not sufficient.

Answer should be E.

What's the OA ?
Option - 1 : Two adjacent faces of the solid have areas 15 and 24, respectively. It means l.b = 15 and b.h = 24 where l,b,h are length, breadth and height respectivley of the rectangular solid.
One side is common to the adjacent faces whose areas we know. But, from this data we can't be sure as what's the exact l,b or h. Because there are more than one choices fit this solution such as l,b,h =

(You can take l.h also instead of l.b but that wont make any difference because ultimately we have to find l.b.h) Not sufficient.

Option - 2 : Each of two opposite faces of the solid has an area of 40. That means all the 6 faces have area = 40. Again, many possibiliteis. not sufficient.

Considering both option - A and B : They both contradict. Not sufficient.

Answer should be E.

What's the OA ?

15 = 3*5*1
24= 1*2^3*3

We get dff ordered sets for (l.b.h) as (3,5,, (1,15,24) not necessarily in the same order.

Hence 1 is not sufficient.

Statement 2: Area of two opposite faces = 40 is not sufficient to find the 3 sides of the cuboid.

Hence OA is E.

Dopa, I was about to choose E but then read ur post n realised tht there canbe also be another way of representing (l.b.h)

Kindly help out with below ..

Is the Integer n Odd ??

1) n is Divisible by 3

2) 2n is Divisible by twice as many positive integers as n.

wrong post

OA is '2' ... Anyone any ideas ... ???

I think Option 2 is sufficient:-

Consider this - When N iS oDD

Let n=3 ,2n=6...The stem says "2n is divisible by twice as many positive integers as n".So, 3 being a prime number would be divisible by itself and 1 (which means it is divisible by 2 Nos) and 6 is divisible by 1,2,3 and 6 ( which means it is divisible by 4 Nos).To check take another case when n is odd.

Let n=4 , 2n=8 .Now 4 is divisible by 1,2 and 4 (3 Nos) and 8 is divisble by 1,2,4 and 8 (4 Nos)..so when n is even it is not satisfying the stem.

Hence N shall be Odd.

Kindly help out with below ..

Is the Integer n Odd ??

1) n is Divisible by 3

2) 2n is Divisible by twice as many positive integers as n.

Stem 1 is definitely not suff as the nos divisible by 3 are both even as well as odd.

Stem 2: Let n =7
Its factors are 1 and 7 (2 nos)
2n = 14 whose factors are 1,2,7 and 14 (twice the no. of factors of n)
Hence n is definitely odd

OA is B

Q) In the XY-cordinate plane, line L and Line K intersect at the point (4,3). is th product of thier slopes negative?
1) The product of the X-intercepts of lines l and k is positive
2) the product of the Y-intercepts of lines l and k is negative




the OA is C. can anyone please explain the answer.

Store S sold 90 copies of a certain book during the 7 days of the last week and it sold different number of copies everyday. If it sold the greatest number of copies of Sat and 2nd highest on fri, did it sell more than 11 copies on fri?

1)Sold 8 copies on thu
2)sold 38 copies on sat

Q) In the XY-cordinate plane, line L and Line K intersect at the point (4,3). is th product of thier slopes negative?
1) The product of the X-intercepts of lines l and k is positive
2) the product of the Y-intercepts of lines l and k is negative




the OA is C. can anyone please explain the answer.


let L is y=m1x + c1
k is y=m2x + c2

lets take first statement
product of x intercept is +ve

L to determine x intercept x=y/m1 -c1/m1

x intercept of L = -c1/m1
similarly for K x intercept = -c2/m2

now it says product of X-intercepts of lines l and k is positive

=> -c1/m1 * -c2/m2 = c1*c2/m1*m2 is +ve

now in this case we cannot say about product of slope m1*m2, it can be -ve and + ve
so statement 1 is insufficient

now lets take statement 2

y intercept of L = c1
y intercept of K = c2

c1* c2 is -ve but based on this we can not say anything about m1* m2

so statement 2 is insufficient

now lets take both together

by 1st c1*c2/m1*m2 is +ve
from 2nd c1*c2 is -ve

now we can say m1*m2 has to be -ve to make c1*c2/m1*m2 is +ve

hence we can answer by using both the statements

hope m correct with my explanation

Let like "L" be of the form (x/a1) + (y/b1) = 1
Let like "K" be of the form (x/a2) + (y/b2) = 1

These can be further written as:-
L --> b1x + a1y = a1b1 --> y = b1 - (b1x/a1)
K --> b2x + a2y = a2b2 --> y = b2 - (b2x/a2)

We need to prove that (-b1/a1)*(-b2/a2) > 0

Statement (1) --> a1 * a2 > 0 --> is insufficient to answer the question as we do not have info about b1 and b2.

Statement (2) --> b1 * b2
Combining the two statements we see that

b1/a1 * b2/a2
Answer is (C).

Q) In the XY-cordinate plane, line L and Line K intersect at the point (4,3). is th product of thier slopes negative?
1) The product of the X-intercepts of lines l and k is positive
2) the product of the Y-intercepts of lines l and k is negative




the OA is C. can anyone please explain the answer.

thnks for the explanation.. I understood both arch's and inder's answers.. but surprisingly no one has used the datA of lines passing through the point . is that a irrelevant data?