in xy plane at what two points does the graph of y=(x+a)(x+b) intersects the x-axis. 1) a+b= -1 2) the graph intersects the y-axis at (0,-6)
the answer is c Please anyone can explain me the reason why the answer is c.I will be pleased to see some helping me to solve the problem as i have tried this sum for 10 times and i cannot understand the question itself.
The answer is indeed C. The question asks what are the zeros of the equation: y=(x+a)(x+b). Obviously y is 0 at x=-a, and -b. So the question is can we find the values of a and b. stmt1: gives one equation, not sufficient. stmt2: (0, -6) satisfies the equation y=(x+a)(x+b), so from here we get another relation in a and b as ab=-6.
So now we have 2 equations in 2 unknowns so it can be solved for a and b. So the answer is C.
In the xy-plane, what is the slope of line l? (1) Line l dose not intersect the line with equation y = 1 - x. (2) Line l intersects the line with equation y = x - 1. What is the value of the integer k? (1) k + 3 > 0 (2) k^4 0 If x and y are positive, is x^3 > y? (1) x > y (2) x > y
In the xy-plane, what is the slope of line l? (1) Line l dose not intersect the line with equation y = 1 - x. (2) Line l intersects the line with equation y = x - 1. What is the value of the integer k? (1) k + 3 > 0 (2) k^4 0 If x and y are positive, is x^3 > y? (1) x > y (2) x > y
My take - A,B,D
1. stmt 1 - Line 'l' doesnt intersect y=1-x.. => the line l must be parallel to y=1-x.. and hence line l's slope must be equal to line y=1-x's slope... -> sufficient. stmt 2 - Line 'l' intersects y=x-1. It can intersect at any angle...so slope cant be decided...
2. stmt 1 - K =3 >0 => k can be -2, -1, 0, 1,2,3,,........ not sufficeint stmt 2 - K^4 3. both x & y are positive
stmt 1: x > y => x > y^2 => x^3 > Y^6, and since ^6 > y => x^3 > y -- -sufficient stmt 2: x > y => x^3 > y ^3...and since y^3 x^3 > y - sufficient
1. stmt 1 - Line 'l' doesnt intersect y=1-x.. => the line l must be parallel to y=1-x.. and hence line l's slope must be equal to line y=1-x's slope... -> sufficient. stmt 2 - Line 'l' doesnt intersect y=x-1. It can intersect at any angle...so slope cant be decided...
3. both x & y are positive
stmt 1: x > y => x > y^2 => x^3 > Y^6, and since ^6 > y => x^3 > y -- -sufficient stmt 2: x > y => x^3 > y ^3...and since y^3 x^3 > y - sufficient
Hi Alchemist,
Two queries: 1) In statement 2 question number 1, you have mentioned line L doesn't intersect y=x-1; However in actual question the statement 2 says
(2) Line l intersects the line with equation y = x - 1. 2) Question 3 - statement 1 says x > y ; Here it can be 1/2 > 1/4 so x^3>y; (1/4)^3 >1/4; 1/64 If x > y => 2>1; so x^3>y; (4)^3 >1; 64> 2 so x^3>y Not sufficient
Two queries: 1) In statement 2 question number 1, you have mentioned line L doesn't intersect y=x-1; However in actual question the statement 2 says
(2) Line l intersects the line with equation y = x 1. 2) Question 3 - statement 1 says x > y ; Here it can be 1/2 > 1/4 so x^3>y; (1/4)^3 >1/4; 1/64 If x > y => 2>1; so x^3>y; (4)^3 >1; 64> 2 so x^3>y Not sufficient
2. line 2 - it was a copy paste .... sorry.. but the explanation is correct..
3. Yep i missed the decimal part.. and thought them to be integers.....and yes..it is E.