My answer was C (both together can solve) but the exam says E (not solvable even when both options are taken together). This was a Kaplan exam - I really can't ignore the answer but I don't think it is right.
Any take?
x^2+5y=49, confirm if Y is integer
break the equation; y=(49 - x^2)/5
Thus y would be integer only if (49 - x^2) is divisible by 5
1. 1they have NOT defined whether x is an integer or not.. difficult call. Assuming x is an integer, 1For x = 2, Y = (49 - 4)/5 = 9 = Y = integer For x = 3, Y = (49 - 9)/5 = 8 = Y = integer
2. x^2 is an integer. DOES NOT answer the question. The output of (49 - x^2)/5 should be divisible by 5.
assuming that X is an integer, answer would be option A Otherwise it would be option E
My answer was C (both together can solve) but the exam says E (not solvable even when both options are taken together). This was a Kaplan exam - I really can't ignore the answer but I don't think it is right.
Any take?
1) If X takes a value 2 Y is an integer If x takes a value 1.5 Y is not an integer. Not sufficient
2) If X^2 = 10 Y is not an integer If X^2 = 4 Y is an integer
Not sufficient
Combining If x = 2, Y is an integer If x = 1.717 (root 3) Y is not an integer Not sufficient Ans: E
1. What is the mean of the numbers, starting from the mth term to the nth term of the sequence (both inclusive)?
A) The terms are consecutive even numbers B) The median of the terms is 12
My answer is E but the OA given is C. Here is my explanation
A) The number cud be 12 and 14 or 14 and 16. Not sufficient B) Let say the set is (8, 10, 12, 14, 16). mth and nth term cud be any number from the set. so we dont have an unique value for mean. Not sufficient
Comb. the two options the numbers cud be
8, 10 or 10,12. Insufficient
FYI - I have reread the question many times to ensure that I did not miss anything.
1. What is the mean of the numbers, starting from the mth term to the nth term of the sequence (both inclusive)?
A) The terms are consecutive even numbers B) The median of the terms is 12
My answer is E but the OA given is C. Here is my explanation
A) The number cud be 12 and 14 or 14 and 16. Not sufficient B) Let say the set is (8, 10, 12, 14, 16). mth and nth term cud be any number from the set. so we dont have an unique value for mean. Not sufficient
Comb. the two options the numbers cud be
8, 10 or 10,12. Insufficient
FYI - I have reread the question many times to ensure that I did not miss anything.
Ramviswa, the option C as OA is correct. Here is the explanation.
A) The terms are consecutive even numbers.
so suppose we have 2, 4, 6, 8 , 10: Not sufficient since no of terms is not defined.
B) Median of terms is 12 : Not sufficient.
Now if we use both A & B together. Then the info is that the series is arranged in an increasing order and mth & nth terms r the extreme values.
We know that for an arranged series, the median = mean = average of extreme values.
1) No integer in the interval 1 and m^2 + 1, both exclusive, divides m exactly 2) No integer in the interval 1 and m + 1, both exclusive, divides m exactly
My answer is D because both options give me answer m = 1. OA is B
2. X and Y are both negative numbers. Is xy 1) xy = 35 2) x = y-2
My answer is A but the OA is B. I feel that there is a typo in this problem but not sure whether am missing something.
3) In how many ways can four people A, B, C and D be seated so that B and C are always together?
1) A, B, C, D are to be seated in a row 2) The distance between any person and his neighbour is 5 feet.
My answer is A because from 2) we cant make out whether all the guys are sitting in a row or in circle. OA is D.
1) No integer in the interval 1 and m^2 + 1, both exclusive, divides m exactly 2) No integer in the interval 1 and m + 1, both exclusive, divides m exactly
My answer is D because both options give me answer m = 1. OA is B
2. X and Y are both negative numbers. Is xy 1) xy = 35 2) x = y-2
My answer is A but the OA is B. I feel that there is a typo in this problem but not sure whether am missing something.
3) In how many ways can four people A, B, C and D be seated so that B and C are always together?
1) A, B, C, D are to be seated in a row 2) The distance between any person and his neighbour is 5 feet.
My answer is A because from 2) we cant make out whether all the guys are sitting in a row or in circle. OA is D.
Please pitch in with your views.
1.From B, we can conclude that m+1 is prime , so we can say that m is non prime. 2. x=y-2 , we can conclude both x and y are >-1 so xy>1. B is also the answer.I think is option A has a typo. 3.Agree with your reasoning.
1.From B, we can conclude that m+1 is prime , so we can say that m is non prime. 2. x=y-2 , we can conclude both x and y are >-1 so xy>1. B is also the answer.I think is option A has a typo. 3.Agree with your reasoning.
1. Is m a prime number? m is a positive integer 1) No integer in the interval 1 and m^2 + 1, both exclusive, divides m exactly 2) No integer in the interval 1 and m + 1, both exclusive, divides m exactly This can be answered by none of the statement. 1. if it is not divisible by any of the integers between 1 and m^2 +1, .But between 1 and m^2 +1 , m will divide m exactly. So, this can never happen. 2. if it is not divisible by any of the integers between 1 and m + 1, m is prime number. But between 1 and m +1, m will divide m exactly. So, this can never happen. The answer should be E. 2. 2. X and Y are both negative numbers. Is xy 1) xy = 35 2) x = y-2 1 alone can answer the question. If xy = 35, means the set can be (-1,-35), (-5,-7), (-7,-5), (-35, -1) In all these cases xy 2 alone can answer the question. The set of values of x,y are (-3,-1), (-4,-2), (-5,-3)etc. The value of xy= 3, 8, 15, ..xy will always be greater than 3. so xy The answer should be D. 3) In how many ways can four people A, B, C and D be seated so that B and C are always together? 1) A, B, C, D are to be seated in a row 2) The distance between any person and his neighbour is 5 feet. This can be answered using 1 alone. So the answer is A. Using 2, we cannot find the no. of ways as it doesn't tell whether the people are sitting in a row or in a circle.
1.From B, we can conclude that m+1 is prime , so we can say that m is non prime. 2. x=y-2 , we can conclude both x and y are >-1 so xy>1. B is also the answer.I think is option A has a typo. 3.Agree with your reasoning.
Q1. If a positive integer m is not divisible by any integer between 2 and m^2 +1, then the number m is 1. So A also answers the question.
Q2) we cannot answer from x = y-2. If Y = -0.1, X = -2.1 then XY
See my reply above. I have changed the answer for 1. The question 1 can not be answered by any of the option. So the answer should be E. The options will never be true. Between 1 and m+1 and between 1 and m^2 +1, m will exactly divide m.
Q2. I have read in the official guide that whenever a number is written in the GMAT, it is taken as integer and not a fraction unless specified. So you cannot take fractions.
See my reply above. I have changed the answer for 1. The question 1 can not be answered by any of the option. So the answer should be E. The options will never be true. Between 1 and m+1 and between 1 and m^2 +1, m will exactly divide m.
Q2. I have read in the official guide that whenever a number is written in the GMAT, it is taken as integer and not a fraction unless specified. So you cannot take fractions.
According to GMAT, "All numbers used are real numbers".
Can you explain why E. To me, both the statements gives me the answer as 1.
I have already explained that in my earlier post. for your reference...(pasting the explaination again.)
1. Is m a prime number? m is a positive integer 1) No integer in the interval 1 and m^2 + 1, both exclusive, divides m exactly 2) No integer in the interval 1 and m + 1, both exclusive, divides m exactly This can be answered by none of the statement. 1. if it is not divisible by any of the integers between 1 and m^2 +1, .But between 1 and m^2 +1 , m will divide m exactly. So, this can never happen. 2. if it is not divisible by any of the integers between 1 and m + 1, m is prime number. But between 1 and m +1, m will divide m exactly. So, this can never happen. The answer should be E
This is a question (q no.99) from GMAT Quants review book.
1. If x is positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?
1) On the number line, z is closer to 10 than it is to x 2) z = 5x
My answer is E whereas OA is A.
My explanation 1) If x = 1 and z = 9, z is greater than mean If x = 9 and z = 9.1 z is less than mean Insufficient 2) If x = 1 z = 5 then zmean Insufficient
Comb. 1 and 2 We can apply the same conditions as applied for 2) - Insufficient
This is a question (q no.99) from GMAT Quants review book.
1. If x is positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?
1) On the number line, z is closer to 10 than it is to x 2) z = 5x
My answer is E whereas OA is A.
My explanation 1) If x = 1 and z = 9, z is greater than mean If x = 9 and z = 9.1 z is less than mean Insufficient 2) If x = 1 z = 5 then zmean Insufficient
Comb. 1 and 2 We can apply the same conditions as applied for 2) - Insufficient
Please share your thoughts.
Well.. it took me very long to understand where you went wrong.. when I solved it on my own I got answer as option A only, but then your explanation almost got me convinced, till I noticed the highlighted section..
Your assumption of x = 9 and z = 9.1 is NOT supported in the questions, as per option A, Z is closer to 10 than it is to X.. now try and substitute suitable values and you would find that option A is sufficient..
This is a question (q no.99) from GMAT Quants review book.
1. If x is positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?
1) On the number line, z is closer to 10 than it is to x 2) z = 5x
My answer is E whereas OA is A.
My explanation 1) If x = 1 and z = 9, z is greater than mean If x = 9 and z = 9.1 z is less than mean Insufficient 2) If x = 1 z = 5 then zmean Insufficient
Comb. 1 and 2 We can apply the same conditions as applied for 2) - Insufficient
Please share your thoughts.
Hi Ramviswa, Please find my explanation:
1. If x is positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?
1) On the number line, z is closer to 10 than it is to x 2) z = 5x For the 1st statement Mod (z-10) There can be 3 cases for z a. z>10, if z is greater than 10, the average 5+x/2 will always be less than z. b. x -(z-10) i.e. 10 i.e. z >5+x/2. c. z So 1 gives unique answer which is z will be greater than the avg of x and 10. For the second statement. If z=5x, X=1,z=5, then 5+x/2 = 11/2. i.e. z X =2, Z=10 then 5+x/2 = 6. i.e. z So 2 doesn't give unique answer. So the answer should be A.
