Option 1:
Z^3 is an integer... NOT sufficient;
(1.81)^3 = 6
&
(2)^3 = 8
Option 2:
3z is an integer... NOT Sufficient
3(0.667) = 2
&
3(2) = 4
So far answer option A, B and D have been ruled out.
The answer would be either C or E. Let's see... :sneaky:
I would have chosen option C. Bcoz I dont think there can be a non-integer that when multiplied by 3 is integer and also when raised to power of 3 remains an integer.
My answer would have been option C :lookround:
I was wrong. After looking at Varun's answer, I think the answer should be C.
My explanation goes like:
if z^3 is an integer, it is not necessary that z is always an integer.
e.g. if z is cubrt(3)
so 1 alone cannot answer the question.
for 2nd statment - if 3z is an intger, z can be integer or fraction.
e.g. z can be 1,2,3.......or 1/3,2/3,4/3....
So 2 alone cannot answer the question.
if both statements are true.....
z^3 = I1
3z = I2
From these two equations, (I2/3)^3 = I1
i.e. (I2)^3 = 27I1
For I1 to be an integer I2 should be multiple of 3.
So, values of I2 = 3,6,9,12,15
corresponding values of I1 = 1,8, 27,64......
So in all these cases z is an integer.
So both the statements are needed to answer the question.
The answer should be C.