I got the foll problem in Gmat Prep. Cant figure out how to solve it.
Each employee on a certain task force is either a manager or a director. What percent of the employees on the task force are directors?
(1) The average (arithmetic mean) of the managers on the task force is $5000 less than the average salary of all the employees on the task force.
(2) The average (arithmetic mean) of the directros on the task force is $15000 greater than the average salary of all the employees on the task force.
Answer is C
Another good question:
If Bob produces 36 or fewer items in a week, he is paid x dollars per item. If Bob produces more than 36 items in a week, he is paid x dollars per item for the first 36 items and 1 1/2(1.5) times that amount for every additional item.
How many items did Bob produce last week?
(A) Last week Bob was paid a total of $480 for the items he produced that week.
(B) This week Bob produced 2 more items than last week and was paid a total of $510 for the items that he produced this week.
Another good question:
If Bob produces 36 or fewer items in a week, he is paid x dollars per item. If Bob produces more than 36 items in a week, he is paid x dollars per item for the first 36 items and 1 1/2(1.5) times that amount for every additional item.
How many items did Bob produce last week?
(A) Last week Bob was paid a total of $480 for the items he produced that week.
(B) This week Bob produced 2 more items than last week and was paid a total of $510 for the items that he produced this week.
answer is C man..let us assume tht bob produced 'y' articles last week..using st.1 last week he earned:
x + 1.5x(y-36) = 480
using st.2,
this week, he earned :
x + 1.5x(y-34) = 510
solve both eq. and u can get the answer
please answer this...my doubt...should consecutive numbers always be considered from lower to higher or the other way round is also possible?
1) n^2=I =>n=+SQRT(I) and -SQRT(I) . Now if SQRT(I) is either irrational or integer
since SQRT(I) = p/q =>not an irrational no. =>SQRT(I) is an integer =>n is an integer.
2)(n+1)/2 =I =>n=2I-1 =>n is an integer
Therefore Ans is D .Do let me know if I am right.
the answer is correct.my doubt...you've considered sqrt(I) to be either integer or irrational.If n^2 = 20,then?n will not be an integer and p/q can be sqrt(20)?isn't it?
please answer this...my doubt...should consecutive numbers always be considered from lower to higher or the other way round is also possible?
answered in PS thread
cyndrella Saysthe answer is correct.my doubt...you've considered sqrt(I) to be either integer or irrational.If n^2 = 20,then?n will not be an integer and p/q can be sqrt(20)?isn't it?
p/q can never be sqrt(20) cuz if thts the case, then either p or q will have to be non-integers which contradicts the given data that p and q are integers..
pls help me out with this'
IF A,B,C ARE THREE SIDES OF TRIANGLE ,ARE ALL THE ANGLES OF TRIANGLE LESS THAN 90 DEGREE.
1. THE AREAS OF SEMICIRCLE DRAWN WITH A,B,C AS RADIUS ARE 4,5,6.
2. C
srry...post deleted due to incorrect explanation
considering st.1, since the areas are in the ratio 4:5:6, the radii will also be in the same ratio...hence, corresponding angles will also be in the same ratio...thus, the angles are 72, 60 and 48...
considering st.2, let us assume C = 80
then A+B should lie between 80 and 82..then, sum of all angles D
well I think the explanation given for statement 1 is wrong
if areas are in ratio say 4:9 then radii will be in ratio 2:3 ie sqrt of area ratio
since area of semi circle is R^2 * pi/2
More over here A B C are referred as sides not angles. Therefore even statement 2 's explanation is at fault
considering st.1, since the areas are in the ratio 4:5:6, the radii will also be in the same ratio...hence, corresponding angles will also be in the same ratio...thus, the angles are 72, 60 and 48...
considering st.2, let us assume C = 80
then A+B should lie between 80 and 82..then, sum of all angles D
ajay,
Could you pls explain how did u arrive at first conclusion.If three sides are given ,are the angles also in same ratio ??,i guess we need to find the angles using cos A =b^2+c^2-2bc/a,kind of formulae,or am i missing something.
answer is C man..let us assume tht bob produced 'y' articles last week..using st.1 last week he earned:
x + 1.5x(y-36) = 480
using st.2,
this week, he earned :
x + 1.5x(y-34) = 510
solve both eq. and u can get the answer
though the answer is C the better method would be
the error in abv eqn is that first term should be 36x not x
cost of 2 extra items = 510-480 = 30 =>cost of each extra item = 15 => 1.5 x=15
=>x=10
now for total item y
36*10 + 15(y-36)= 480
cyndrella Saysthe answer is correct.my doubt...you've considered sqrt(I) to be either integer or irrational.If n^2 = 20,then?n will not be an integer and p/q can be sqrt(20)?isn't it?
The answer either has to be B or D
I am not convinced with the arguments which say that for stmt 1 : no sqrtof integer can be denoted as p/q
repeated post
cyndrella Saysthe answer is correct.my doubt...you've considered sqrt(I) to be either integer or irrational.If n^2 = 20,then?n will not be an integer and p/q can be sqrt(20)?isn't it?
yes, you are right.
Dear friends
Would you be able to help me..I guess I'm missing the basic concept here.
Is
(1) = 2
(2) 0
i understand that = x , x>0 and -x when x
pls elaborate wrt this problem..
thanks
Dear friends
Would you be able to help me..I guess I'm missing the basic concept here.
Is
(1) = 2
(2) 0
i understand that = x , x>0 and -x when x
pls elaborate wrt this problem..
thanks
what are those question marks??? and is that mod(x) that u are referring to by writing ??? cuz if thts the case, then will never be less than one except when its 0...it will be equal to 1 when its 1..except these two values, it will never be less than 1...cud u post the problem a bit more clearly
though the answer is C the better method would be
the error in abv eqn is that first term should be 36x not x
cost of 2 extra items = 510-480 = 30 =>cost of each extra item = 15 => 1.5 x=15
=>x=10
now for total item y
36*10 + 15(y-36)= 480
Thats why the answer is E and not C.
because the extra item costs Rs 15/- . that can mean 510/15 = 34 items
or
360/10 = 36 items and 150/15 = 10 items ie total 46 items
Thus the total no of items cannot be determined.
Sorry Ajay
its indeed mod(x) not the greatest integer function .
Is mod (x)
(1) mod (x + 1) = 2 mod (x - 1)
(2) mod (x - 3) 0
my apologies for the confusion.
thanks
Sorry Ajay
its indeed mod(x) not the greatest integer function .
Is mod (x)
(1) mod (x + 1) = 2 mod (x - 1)
(2) mod (x - 3) 0
my apologies for the confusion.
thanks
well..i guess the answer is E...
considering st.1,
there cud be 4 possible cases..
case 1:
(x+1) = 2(x-1)
hence, x=3
case 2:
(x+1) = 2* -(x-1)
hence, x=1/3
thus, u dont get a unique answer..
considering st.2,
since mod(x-3)0,
x can take any value except 3..thus, x can be 0, 1, 2, 4,...
thus, st.2 is also nt sufficient