well..i guess the answer is E... considering st.1, there cud be 4 possible cases.. case 1: (x+1) = 2(x-1) hence, x=3 case 2: (x+1) = 2* -(x-1) hence, x=1/3 thus, u dont get a unique answer..
considering st.2, since mod(x-3)0, x can take any value except 3..thus, x can be 0, 1, 2, 4,... thus, st.2 is also nt sufficient
i think ans should be A,
the qn is asking ,is -1 from first statement: the possible regions of inequality are -11,x checking the inequality against these' in the region -1 in the region x>1, x=1/3 ,not in the region in region x thus x=1/3 is the only solution
and from 2nd statement we know that x is not equal to 3
well..i guess the answer is E... considering st.1, there cud be 4 possible cases.. case 1: (x+1) = 2(x-1) hence, x=3 case 2: (x+1) = 2* -(x-1) hence, x=1/3 thus, u dont get a unique answer..
considering st.2, since mod(x-3)0, x can take any value except 3..thus, x can be 0, 1, 2, 4,... thus, st.2 is also nt sufficient
Ajay I think the answer must be C . Since from st 1 we know x = either 3 or 1/3 and stmt 2 we know x3 So from 1 & 2 together. x=1/3 Therefore mod(x) Plz correct me If I am wrong
Thats why the answer is E and not C. because the extra item costs Rs 15/- . that can mean 510/15 = 34 items or 360/10 = 36 items and 150/15 = 10 items ie total 46 items
Thus the total no of items cannot be determined.
Are u sure that answer is E???
I think the answer has to be C
cost of 2 extra items = 510-480 = 30 =>cost of each extra item = 15 => 1.5 x=15 =>x=10 now for total item y
Ajay I think the answer must be C . Since from st 1 we know x = either 3 or 1/3 and stmt 2 we know x3 So from 1 & 2 together. x=1/3 Therefore mod(x) Plz correct me If I am wrong
it should be A ,as frm statement 1 we get only x=1/3, x=3 is not in the range for x if i am not missing something.
it should be A ,as frm statement 1 we get only x=1/3, x=3 is not in the range for x if i am not missing something.
But since in st1 we find out that x can be either 1/3 or 3 . it is only in st2 we get info which says x != 3. so only when we take the stmt 2 into consideration can we narrow down on 1/3 . Plz correct me if wrong . wats the answer by the way
But since in st1 we find out that x can be either 1/3 or 3 . it is only in st2 we get info which says x != 3. so only when we take the stmt 2 into consideration can we narrow down on 1/3 . Plz correct me if wrong . wats the answer by the way
from statement 1 we get x = 1/3 only as when we get x=3 the range we are taking is x also we get x=1/3 for range x > 1 which again doesnt satisfy the solution.so. we get x=1/3 for range -1there are three ranges for the given equation x1,-1
from statement 1 we get x = 1/3 only as when we get x=3 the range we are taking is x also we get x=1/3 for range x > 1 which again doesnt satisfy the solution.so. we get x=1/3 for range -1there are three ranges for the given equation x1,-1
ankaccent and sharkon...this problem itself is confusing...a first look at the problem and we know tht the problem is asking whether mod(x)
can any body assist in solving this problem.. data sufficiency question
question is in above number line is zero half way between s and r ?
a. s is to the right of zero.
b. distance between t and -s is same as distance between t and r.
in above case...ans is c both and b.
my doubt..only b should suffice..
can anybody elobrate..
the answer is ofcourse C...because, st.1 just tells us that 0 is to the right of s..so it can be anywher within r and s or beyond r... st.2 tells us that dist. between t and -s is same as dist. between t and r...this does not tell us the location of zero..so this option is useless... considering both the options, dist. between t and -s will be same as dist. between t and r only if r = -s...this can be concluded because we know zero is to the left of s..hence s is +ve..thus, r has to be equal to -s for the condition to hold true..
can any body assist in solving this problem.. data sufficiency question
question is in above number line is zero half way between s and r ?
a. s is to the right of zero.
b. distance between t and -s is same as distance between t and r.
in above case...ans is c both and b.
my doubt..only b should suffice..
can anybody elobrate..
The Answer must be C only.
The reason it is not B is as follows:
1)Suppose s,r,t are all to the left of Zero ie all are -ve then there is a chance that dist b/w TR is equal to distance b/w T and -S (-S will be +ve and to the Right of Zero).
Hence without knowing S is +ve or -ve it is hard to answer question using B only
since the greatest common factor of both the nos. is 2, it means tht the nos. cud be 4&6, 4&10, 6&10 etc...divide any two such nos. and the remainder will always be greater than 1..infact, i think in most cases it is exactly 2...hence, this statement is sufficient to answer the question
option 2 :
the LCM is 30...so the nos. cud be 6&10, 3&10, 15&30, 3&30, 6&30 etc... and try dividing any of these combinations, the remainder will always be greater than 1....this statement is also sufficient on its own to answer the question. so the answer is C
here as we can see that numbers 3 and 10 when 10 divided by 3 we get remainder as 1 so answer choice is a, not c
1)Suppose s,r,t are all to the left of Zero ie all are -ve then there is a chance that dist b/w TR is equal to distance b/w T and -S (-S will be +ve and to the Right of Zero).
Hence without knowing S is +ve or -ve it is hard to answer question using B only
Hi With clue b alone you can draw the above diagram (forget zero inthe diagram) which says r is not between s and -s .. Zero is always between s and -s . with this you can always say zero is not in between r and s . so anwer is B
see, the equation can be rewritten as : x 1 - when y>0, take any value of y>0...2,3,4....the corresponding values of x will be x 2 - we are given that x
hence, the value of x will always be less than 0... thus statement 2 is also sufficient to answer on its own
i sugget simple approach to this problem for 2 stem...
we know that -2x>3y, 2x+5y=20 here by substituting y in terms of x in inequality, we can find that x any other approach will be highly appreciated..:grab:
see, the equation can be rewritten as : x 1 - when y>0, take any value of y>0...2,3,4....the corresponding values of x will be x 2 - we are given that x
hence, the value of x will always be less than 0... thus statement 2 is also sufficient to answer on its own
Sriram_Avadhani Says
Hi With clue b alone you can draw the above diagram (forget zero inthe diagram) which says r is not between s and -s .. Zero is always between s and -s . with this you can always say zero is not in between r and s . so anwer is B
no...
answer c is correct...even i assumd that variables r,s,t as positive... we cannot say that variable x is +ve no and -x is -ve no, it may be possible that x is -ve and -x is +ve..
the answer is ofcourse C...because, st.1 just tells us that 0 is to the right of s..so it can be anywher within r and s or beyond r... st.2 tells us that dist. between t and -s is same as dist. between t and r...this does not tell us the location of zero..so this option is useless... considering both the options, dist. between t and -s will be same as dist. between t and r only if r = -s...this can be concluded because we know zero is to the left of s..hence s is +ve..thus, r has to be equal to -s for the condition to hold true..
see, i can further explain why st. b is nt sufficient on its own.. if zero lies to the right of 't' , then 's' is -ve...thus, -s will be +ve value of s...but, if zero lies midway between r and s, then r = -s...still the condition is satisfied..thus, u dont get a unique location for zero..thts why the answer's C
Hi With clue b alone you can draw the above diagram (forget zero inthe diagram) which says r is not between s and -s .. Zero is always between s and -s . with this you can always say zero is not in between r and s . so anwer is B
see, i can further explain why st. b is nt sufficient on its own.. if zero lies to the right of 't' , then 's' is -ve...thus, -s will be +ve value of s...but, if zero lies midway between r and s, then r = -s...still the condition is satisfied..thus, u dont get a unique location for zero..thts why the answer's C
1) n^2=I =>n=+SQRT(I) and -SQRT(I) . Now if SQRT(I) is either irrational or integer since SQRT(I) = p/q =>not an irrational no. =>SQRT(I) is an integer =>n is an integer.
