GMAT Data Sufficiency Discussions

MBA GMAT
1901
Deepak..can you please explain the Bold and italised statement.....
how can it be said that we will have one factor which will be less than K ??


Consider for instance 13! + 2...This is divisible by 2 which means that 2 is a factor of this number.So, 1
1902
For the above q

statement 1 : Nt Suff ( K can be composite or prime)

statement 2 : possible values

K = 13!+2
K = 13!+3
.
.
.
.
K = 13!+13

For all the above values it is possible to get one factor which will be less than K.Suff

So my take for the above q is option B.
OA please

The OA is B indeed..
1903

Can any1 please help me with this questions ..... i would be grateful !

Q. How many more first-time jobless claims were filed in week P than in week T

1). For Weeks P, Q, R, S Average(A.M)no. of 1st time jobless claims filed was 388250

2). For Weeks Q, R, S, T Average(A.M)no. of 1st time jobless claims filed was
383000

-------------------------------------------------------------------

Thanx !

1904
Can any1 please help me with this questions ..... i would be grateful !

Q. How many more first-time jobless claims were filed in week P than in week T

1). For Weeks P, Q, R, S Average(A.M)no. of 1st time jobless claims filed was 388250

2). For Weeks Q, R, S, T Average(A.M)no. of 1st time jobless claims filed was
383000

-------------------------------------------------------------------

Thanx !


Statement 1:
==========
P+Q+R+S = 4*x.Nt suff ----(1)

Statement 2:
==========
Q+R+S+T = 4y.Nt suff ----(2)

(1) - (2) gives P - T = 4(x-y) which says how much P > T which is the requirement.So I wud go with option C for the above q
1905
Can any1 please help me with this questions ..... i would be grateful !

Q. How many more first-time jobless claims were filed in week P than in week T

1). For Weeks P, Q, R, S Average(A.M)no. of 1st time jobless claims filed was 388250

2). For Weeks Q, R, S, T Average(A.M)no. of 1st time jobless claims filed was
383000

-------------------------------------------------------------------

Thanx !



pretty straighfwd , Ques asks wat is P-T

1. P+Q+R+S = 4*388250

Not suff

2. Q+R+S+T = 4*383000
Not suff

1. & 2. together
P-T = 4*5250

IMO C
1906

Great !answers r right !! thanks deepak and ndhadha !!

1907

Peter, Paul, and Mary each received a passing score on his/her history midterm. The average (arithmetic mean) of the three scores was 78. What was the median of the three scores?

(1) Peter scored a 73 on his exam.

(2) Mary scored a 78 on her exam.

Pls explain...

1908
Peter, Paul, and Mary each received a passing score on his/her history midterm. The average (arithmetic mean) of the three scores was 78. What was the median of the three scores?

(1) Peter scored a 73 on his exam.

(2) Mary scored a 78 on her exam.


I wud go with option C for the above q
1909

Is x
(1) x = (1/2)y

(2) y = 0.5z

1910

In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

(2) a + |b| = |c| + d

1911
deepakraam Says
I wud go with option C for the above q


C is NOT correct... you want to try again?

hint, 78 is mean & 78 is one of the scores...
1912
Peter, Paul, and Mary each received a passing score on his/her history midterm. The average (arithmetic mean) of the three scores was 78. What was the median of the three scores?

(1) Peter scored a 73 on his exam.

(2) Mary scored a 78 on her exam.

Pls explain...


The total marks obtained=78*3=234
st1. Pe marks 73 then balance marks of paul and mary=161.cant say anything.
st2.mary scored 78,balance marks=156,cant say
combinig two the median would be=234-73-78=73

hence C
1913
C is NOT correct... you want to try again?

hint, 78 is mean & 78 is one of the scores...

Yes u are right.B itself is suff.
1914
Is x
(1) x = (1/2)y

(2) y = 0.5z


Ans E ..

Individually it tells u nothing ..
combined ...x = 1/4 z

Still nothing since, both cud be +ve or -ve

If z = 4 then x = 1 , hence xz ...Insuff
1915
In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

(2) a + |b| = |c| + |d


This problem has been posted earlier on this thread...
have pasted the soln here again for everyone's benefit

Ans option should be C

St 1 : equal ratio tells us nothing ...not sufficient

St 2 : a|+|b| = |c|+d

Same total does not necessarily mean equidistant points ..
5+3 = 4+4 , but(5,3) and (4,4) are not equidistant ..Not sufficient

Combined :
With same total and same ratio ,co-ordinates are same ..
Suff...Ans C

Link to the same problem with different wordings :
http://www.pagalguy.com/forum/gmat-and-related-discussions/20702-gmat-data-sufficiency-discussions-137.html#post1594342
1916
Is x
(1) x = (1/2)y

(2) y = 0.5z


Statement 1; Nt suff

Statement 2; Nt suff

combining both we get x = 1/4 z.still nt suff since Z can be + or -ve.

So I wud go with option E
1917
in the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

(2) a + |b| = |c| + d

OA is C...
1918
is x
(1) x = (1/2)y

(2) y = 0.5z

OA is E.....
1919
Peter, Paul, and Mary each received a passing score on his/her history midterm. The average (arithmetic mean) of the three scores was 78. What was the median of the three scores?

(1) Peter scored a 73 on his exam.

(2) Mary scored a 78 on her exam.

Pls explain...


OA - B
since 78 is the mean and also one of the scores...
1920

Try this:
Tom is going to move, he has three kinds of boxes: large, medium, and small. Now he has already 11 large boxes, each of which is either empty or filled with 6 medium boxes. Medium boxes are filled in the large boxes and each of them is either empty or filled with 6 small boxes. Small boxes are empty and filled in the medium boxes. How many boxes does Tom have?

1) He has 56 empty boxes
2) He has 42 small boxes