Try this: Tom is going to move, he has three kinds of boxes: large, medium, and small. Now he has already 11 large boxes, each of which is either empty or filled with 6 medium boxes. Medium boxes are filled in the large boxes and each of them is either empty or filled with 6 small boxes. Small boxes are empty and filled in the medium boxes. How many boxes does Tom have?
1) He has 56 empty boxes 2) He has 42 small boxes
good one!!!!
No. of Large Empty - a No. of Large Full - b No. of Med Empty - c No. of Med Full - d No of small - e
Total Large = 11 = a + b ......eq 1 Total Med = 6b = c + d ......eqn 2 Small = 6d = e
1) 56 empty boxes -> a + c + 6d = 56 ... Not Suff
2) 42 small boxes -> 6d = 42, So d = 7 Not suff...
Try this: Tom is going to move, he has three kinds of boxes: large, medium, and small. Now he has already 11 large boxes, each of which is either empty or filled with 6 medium boxes. Medium boxes are filled in the large boxes and each of them is either empty or filled with 6 small boxes. Small boxes are empty and filled in the medium boxes. How many boxes does Tom have?
1) He has 56 empty boxes 2) He has 42 small boxes
Ans C ...
Individually tells u nothing ..
Combined , 42 small means, 7 filled medium boxes, medium boxes shd be a multiple of 6 ...so nearest multiple is 12 ...i.e 2 filled big boxes ...
Tom is going to move, he has three kinds of boxes: large, medium, and small. Now he has already 11 large boxes, each of which is either empty or filled with 6 medium boxes. Medium boxes are filled in the large boxes and each of them is either empty or filled with 6 small boxes. Small boxes are empty and filled in the medium boxes. How many boxes does Tom have?
There are 11 big boxes. Lets say, in only one big box there are 6 med. boxes and in only one med. box there are 6 small , so number of empty boxes = 11 - 1 +
First (-1) because I am asuming that it has 6 medium boxes. Then (6-1) because I am asuming that 1 med. box has 6 small boxes - one filled and 5 empty. then (6) because all small boxes are empty.
Now, you can generalize it:-
No. of Empty boxes = 11 + n(6-1) = 56 5n = 45 ==> n = 9
So, total number of boxes = 11 + n(6) -- because we are not excluding that filled box. = 65 boxes.. SO, Answer shd be A
Ans for the below prblm is option C
Tom is going to move, he has three kinds of boxes: large, medium, and small. Now he has already 11 large boxes, each of which is either empty or filled with 6 medium boxes. Medium boxes are filled in the large boxes and each of them is either empty or filled with 6 small boxes. Small boxes are empty and filled in the medium boxes. How many boxes does Tom have?
There are 11 big boxes. Lets say, in only one big box there are 6 med. boxes and in only one med. box there are 6 small , so number of empty boxes = 11 - 1 +
First (-1) because I am asuming that it has 6 medium boxes. Then (6-1) because I am asuming that 1 med. box has 6 small boxes - one filled and 5 empty. then (6) because all small boxes are empty.
Now, you can generalize it:-
No. of Empty boxes = 11 + n(6-1) = 56 5n = 45 ==> n = 9
So, total number of boxes = 11 + n(6) -- because we are not excluding that filled box. = 65 boxes.. SO, Answer shd be A
Nipun ...partially correct analysis ...
Every empty large box reduces the potential of empty boxes by 35 and every empty medium box reduces the potential of empty box by 5 ..
So, u can also look at this way ...
Total possible empty boxes for 11 large boxes are : 11*6*6 = 396 ..
Now, let there be m large empty boxes and n medium empty box ..
Sequence A is defined by the equation An = 3n + 7, where n is an integer greater than or equal to 1. If set B is comprised of the first x terms of sequence A, what is the median of set B ?
In a certain state 15 billion dollars are spent in lottery tickets. How much money did the low fifty of the society, ordered by income, spent in lottery tickets? 1) The low fifty of the society spent the same than the high fifty of the society 2) 10% of the people bought 65% of the tickets
How can you have 8 medium boxes and 9 small boxes. In the Q, it is written that If A large box is filled with medium boxes, then it has to be 6 or none and same for small boxes. Your example is contradicting question..
Take the below case for instance,
Large = 11 Medium = 8 small = 9
Filled : L : 2 M : 2 S : 0 T : 4
Empty : L : 9 M : 6 S : 9 T : 24
Total no.of boxes : 28
L = Large S = small M = Medium T = Total
Applying ur formula , 11 +5n = 24 5n = 13 .n is not an integer which will not be possible.
YOu are right to an extent but it doesnot matter if the empty box is large or medium or small. Every empty box if filled creates 5 more empty boxes. And If we are given with total no. of empty boxes, we can find total no. of boxes but we cannot find how many are medium and how any are small....
Nipun ...partially correct analysis ...
Every empty large box reduces the potential of empty boxes by 35 and every empty medium box reduces the potential of empty box by 5 ..
So, u can also look at this way ...
Total possible empty boxes for 11 large boxes are : 11*6*6 = 396 ..
Now, let there be m large empty boxes and n medium empty box ..
YOu are right to an extent but it doesnot matter if the empty box is large or medium or small. Every empty box if filled creates 5 more empty boxes. And If we are given with total no. of empty boxes, we can find total no. of boxes but we cannot find how many are medium and how any are small....
Yes, now i agree with you nipun, We have definitive total but no definitive distribution among the 3 kinds ...i overlooked the fact that total is asked, rather than 1 specific kind
How can you have 8 medium boxes and 9 small boxes. In the Q, it is written that If A large box is filled with medium boxes, then it has to be 6 or none and same for small boxes. Your example is contradicting question..
I agree with u Nipun. I'm jus thinking in ur lines and ur approach sounds correct.
