Guys cud u plz help me out with these??
1) If b, c, and d are constants and x^2 + bx + c = (x + d)^2 for all values of x, what is the value
of c?
(1) d = 3
(2) b = 6
2) If each of the students in a certain mathematics class is either a junior or a senior, how
many students are in the class?
(1) If one student is to be chosen at random from the class to attend a conference,
the probability that the student chosen will be a senior is 4/7.
(2) There are 5 more seniors in the class than juniors.
3)
At a certain company, 25 percent of the employees are male and 50 percent of the
employees are sales staff. What is the number of employees at this company?
(1) Exactly 7 of the employees at the company are males who are sales staff.
(2) There are 16 more female employees than male employees at the company.
4) If 4 A. 42 B. 42 C. 28 D. 24 E. 24
(plz let me know if theree is any particular method to solve the pbm above)
5) A certain restaurant offers 6 kinds of cheese and 2 kinds of fruit for its dessert platter. If
each dessert platter contains an equal number of kinds of cheese and kinds of fruit, how
many different dessert platters could the restaurant offer?
A. 8
B. 12
C. 15
D. 21
E. 27
6) If x is a positive integer, is the remainder 0 when (3^x + 1)/10?
(1) x = 3n + 2, where n is a positive integer.
(2) x > 4
4) If -4 A. -42 B. -42 C. -28 D. -24 E. -24
(plz let me know if theree is any particular method to solve the pbm above)
soln 4 ::
ans is B
maximum is maximum(two minim -ves prdct or two max +ves product)
minimum is minimum(all possible combis of one -ve and one +ve)
6c1*2c1 + 6c2*2c2 = 27
5) A certain restaurant offers 6 kinds of cheese and 2 kinds of fruit for its dessert platter. If
each dessert platter contains an equal number of kinds of cheese and kinds of fruit, how
many different dessert platters could the restaurant offer?
A. 8
B. 12
C. 15
D. 21
E. 27
6) If x is a positive integer, is the remainder 0 when (3^x + 1)/10?
(1) x = 3n + 2, where n is a positive integer.
(2) x > 4
cannot be determined using the data given
3^x + 1 is divisible by 10 for x=2 6 10 .....
only few values satisfy using 1
only few values satisfy using 2
using both ... also we cannot conclude
Hope I m clear 😃
Guys cud u plz help me out with these??
1) If b, c, and d are constants and x^2 + bx + c = (x + d)^2 for all values of x, what is the value
of c?
(1) d = 3
(2) b = 6
2) If each of the students in a certain mathematics class is either a junior or a senior, how
many students are in the class?
(1) If one student is to be chosen at random from the class to attend a conference,
the probability that the student chosen will be a senior is 4/7.
(2) There are 5 more seniors in the class than juniors.
3)
At a certain company, 25 percent of the employees are male and 50 percent of the
employees are sales staff. What is the number of employees at this company?
(1) Exactly 7 of the employees at the company are males who are sales staff.
(2) There are 16 more female employees than male employees at the company.
4) If -4 A. -42 B. -42 C. -28 D. -24 E. -24
(plz let me know if theree is any particular method to solve the pbm above)
5) A certain restaurant offers 6 kinds of cheese and 2 kinds of fruit for its dessert platter. If
each dessert platter contains an equal number of kinds of cheese and kinds of fruit, how
many different dessert platters could the restaurant offer?
A. 8
B. 12
C. 15
D. 21
E. 27
6) If x is a positive integer, is the remainder 0 when (3^x + 1)/10?
(1) x = 3n + 2, where n is a positive integer.
(2) x > 4
1.d (lokking at coefficients)
2.c ( stat 1 is just a ratio and info in stat 2 match with that in 1 hence conclusive)
3.b ( stat 1 gives no link between the two independent facts, stat 2 gives the difference between M and Fs as 16 which is 50 percent.......assuming the guys are either males or females)
4.b (multiply the extremes, you get four values, 2 positive and 2 negative ....pick minimum from negative and max from positive....gives the range)
5.e (1 each 6c1*2c1 + 2 each 6c2*4c2)
6. e (x; 4n+2 should do, unit' digit has a repetibility of 4 and since 3 sq is 9 so would be the ending of 3^6 and so on, statement 2 is useless )
Can any one please help me with these questio0n? Have the answers but cant find the right approach for the question
??:.. 1. What will be the remainder when 13^7 + 14^7 + 15^7 + 16^7 is divided by 58?a. 57
b. 1
c. 30
d. 0 (Correct Answer)
e. 28
2. In a class comprising boys and girls, there were 45 hand shakes amongst the girls and 105 hand shakes amongst the boys. How many hand shakes took place between a boy and a girl, if each member of the class shook hands exactly once with every other student in the class?
a. 25
b. 15
c. 150 (Correct Answer)
d. 300
e. 24
3. If a circle, regular hexagon and a regular octagon have the same area and if the perimeter of the circle is represented by "c", that of the hexagon by "h" and that of the octagon by "o", then which of the following is true?
a. c > o > h
b. c > h > o
c. h > c > o
d. o > h > c
e. h > o > c (Correct Answer)
Can any one please help me with these questio0n? Have the answers but cant find the right approach for the question??:.. 1. What will be the remainder when 13^7 + 14^7 + 15^7 + 16^7 is divided by 58?a. 57
b. 1
c. 30
d. 0 (Correct Answer)
e. 28
2. In a class comprising boys and girls, there were 45 hand shakes amongst the girls and 105 hand shakes amongst the boys. How many hand shakes took place between a boy and a girl, if each member of the class shook hands exactly once with every other student in the class?
a. 25
b. 15
c. 150 (Correct Answer)
d. 300
e. 24
3. If a circle, regular hexagon and a regular octagon have the same area and if the perimeter of the circle is represented by "c", that of the hexagon by "h" and that of the octagon by "o", then which of the following is true?
a. c > o > h
b. c > h > o
c. h > c > o
d. o > h > c
e. h > o > c (Correct Answer)
1. any expression of the form a^n + b^n where n is odd can be expressed as (a+b)
for this problem make pair of 13-16 and 14-19, do the algebra and see that the part comes like 29*some odd number + 29*some odd number, you get 29*some even number, that does it.
2.i'll cut the crap short, let the number of girls be x and that of boys be y, xC2=45 and yC2=105, quick maths ..... x=10, y=15. Total = 25 . Total handshakes = 25C2= 300 subtract those of boys and those of girls....... remainder boys and girls.
3. dude
go through the thread again i once already answered the question few posts back with sound logic.PS- no answers first, next time onwards
What is the number of female employees in Company
X ?
(1) If Company
X were to hire 14 more people and all of these people were females, the ratio of the number of male employees to the number of female employees would then be 16 to 9.
(2) Company
X has 105 more male employees than female employees.
A Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D EACH Statement ALONE is sufficient.
E Statements (1) and (2) TOGETHER are NOT sufficient.
THe answer should be (c)
Suppose no of males employeed = X
No of females employed =Y
From statement (1) :
X/(Y+14) = 16/9 (a)
From statement (2) :
X-Y = 105 (b)
The simultaneous eqs (a) & (b) gives X=208 & Y=103
Hence no of female employees at present = 103.
Few questions from my side in DS
1. Is 5^k less than 1000?
a. 5^(k-1) > 3000
b. 5^(k-1) = 5^k - 500
2. Is ab=1
a. aba=a
b. bab=b
3. Is sqrt((x-3)^2) = 3-x
a. x!= 3
b. -x x >0
Friend... There is a separate thread for DS.
1. Is 5^k less than 1000?
a. 5^(k-1) > 3000
b. 5^(k-1) = 5^k - 500
Can be answer using any one. From (a) we can arrive at 5^k > 15000 > 1000. From (b) we can arrive at 5^k = 650.
2. Is ab=1
a. aba=a
b. bab=b
Cannot be answer. Taking only (a) or only (b) - either a or b can be 0. Taking both together - both (a) and (b) can be zero.
3. Is sqrt((x-3)^2) = 3-x
a. x!= 3
b. -x x >0
I think this cannot be answered as both (a) and (b) dont seem to indicate if we need to take the -ve sqrt or not.
New concept:snipersm:
When you see something like ( X= sqrt(9) ; X = ? )
what should be the answer ?? +/- 3 ???
but the following concept from official GMATPrep from mba.com ( official GMAT site ) explains differently.
sqrt(n) denotes a positive number whose square is n.
For example, 
sqrt(9) denotes 3 not the -3, see the square root concept in GMATPrep.
Other way of looking at it is :
square roots of 9 are : sqrt(9) and -sqrt(9)
but simply put , sqrt(9) is just +3 not -3.
Learning point is : sqrt(x) is only the positive of x's square roots 😞
Few questions from my side in DS
1. Is 5^k less than 1000?
a. 5^(k-1) > 3000
b. 5^(k-1) = 5^k - 500
2. Is ab=1
a. aba=a
b. bab=b
3. Is sqrt((x-3)^2) = 3-x
a. x!= 3
b. -x x| >0
the answer for the third question is b, if there is no typo in statement 1. because there is no integer n possible for which n! = 3. Statement 2 says that x is a negative number and since sqrt of n^2 is |n we can get answer using the GMATPrep' rules on this matter.
I have attached a few questions from gmat prep
Can someone please explain the answers?
I have my gmat scheduled on 17th of this month.
Thanks a lot in advance....
Q10 PO subtends an angle of 30 degree with negative X axis, angle POQ is 90 degree, so QO subtends angle of 60 degree with + X axis, hence t/s = sqrt 3. Now radius is 2 therefore t has to be sqrt 3 and s is 1.
Q7 even if you know QR=RS you dont know where the line from S is going to fall on PT, and similarly for statement 2. NOw when you combine them together.
let angle R be y and angle T be 90-y, so the other angles of the newly formed isoscles triangles would be (180-y)/2 and (90+y)/2 respectively. Now a straight line is 180 degrees hence one of these angles each+x= 180. we get x=45
Q30 pigs+cows=40
statement 1 says cows>26 or pigs statement 2 says more than 12 pigs, hence we get a unique value of 13.
Q37, an excellent question, reiterates the fact that you bloody need to check all the darned possibilities. there are many possibilities on the number line and the one where
r
PS- grrrrrrrrrrrrrrrrrrrrrrr.........no answers please, give some time to everyone for figuring out the solutions.
I have attached a few questions from gmat prep
Can someone please explain the answers?
I have my gmat scheduled on 17th of this month.
Thanks a lot in advance....
Same explanations for Q30 as by dumbjoe.
In Q7, in case you didnt understand, dumbjoes explantion uses the two theorms "External angle theorm" and "Sum of three angles of a triangle is 180".
Just to add to Q10, we get the angles using the formula tan(angle) = y co-ordinate / x co-ordinate. This gives us the 30 degree angle subtended by PO. The same formula then can be used to arrive at the answer.
Also making Q37 a bit more clear. When we say that s is to the right of zero, then for distance(t,r) = distance(t,-s) to be true, r and -s have to be one and the same point. Hence in that case, zero will be halfway between them.
thanks man-h for clarifying the solutions, when i looked at them again after reading your post, indeed i was a bit presumptous there.
If x is positive, which of the following could be the correct ordering of 1/x, 2x, and x^2 ?
a) (x^2) b) (x^2) c) 2x
A) None
B) a only
C) c only
D) a & b only
E) a, b, and c
If x is positive, which of the following could be the correct ordering of 1/x, 2x, and x^2 ?
a)(x^2) b)(x^2) c)2x
A)None
B)a only
C)c only
D)a & b only
E)a, b, and c
possibilities are x1. As no sign of equality in conditions we can also ignore them(or consider them, wont make a difference at x=0.5,1)
for 0
a ranch has both horses and ponies. Exactly 5/6 of ponies have horseshoes and exactly 2/3 of the ponies with horseshoes are Icelandic. If there are 3 more horses than ponies, what is the minimum number of horses and ponies combined on the ranch?
a. 12
b. 21
c. 27
d. 39
e. 57
a ranch has both horses and ponies. Exactly 5/6 of ponies have horseshoes and exactly 2/3 of the ponies with horseshoes are Icelandic. If there are 3 more horses than ponies, what is the minimum number of horses and ponies combined on the ranch?
a. 12
b. 21
c. 27
d. 39
e. 57
The number of ponies has to be such that it should be divisible by 6 and then by 3 i.e. minimum 18. Hence minimum number of horses and ponies = 18 + 21 = 39.
39 was the correct answer, solution same as that of man-h.