possibilities are x1. As no sign of equality in conditions we can also ignore them(or consider them, wont make a difference at x=0.5,1) for 0x^2 so statement c disqualifies. now depending on x> or
Dumbjoe, Thanks 4 the answer, you got it correct. Just wanted to give a detailed explanation of the reason.
When we see questions of this type, at first glance we would think that the equation has to satisfy all the possible values of 'x'.
But this qn is a bit different that, if there exists one value that satisfy the relations , then the relation is satisfied on the whole because of the word "could" in the question.
I think the answer to this question lies more with the "could" factor.
We need to figure out , if there exists at least one value of 'x' that cud satisfy the given relations.
x^2 X^2 2x
The answer choice 'D'.
I got this one wrong for the reason I just explained in this post.
what are you saying man.........been more than active.....infact it was only yesterday that one of the moderators warned me to cool my heels a bit :argue: of all the people Neo chose my post to edit the download links that i had put up . as to discussions thread, you put up questions and i will try to answer, these days more in a cramming mode than doing questions hence myself dont have many to put here. Try this one
baseball' world series matches 2 teams against each other in a best of 7 games. The first team to win four games wins the series and no subsequent games are played. If you have no special info about either of teams what is the probability that the world series will consist of fewer than 7 games?
what are you saying man.........been more than active.....infact it was only yesterday that one of the moderators warned me to cool my heels a bit :argue: of all the people Neo chose my post to edit the download links that i had put up . as to discussions thread, you put up questions and i will try to answer, these days more in a cramming mode than doing questions hence myself dont have many to put here. Try this one
baseball' world series matches 2 teams against each other in a best of 7 games. The first team to win four games wins the series and no subsequent games are played. If you have no special info about either of teams what is the probability that the world series will consist of fewer than 7 games?
a. 12.5 b. 25 c. 31.25 d. 68.75 e. 75
Realised one very basic fact after hitting my head on the question for a while. The question is wrong or misprinted. 0
@ neo righty ho! :oha: wont say i was unaware, but thought may be the restriction was only for uploading stuff on PG itself, and since I uploaded it on another site, I was not going against the rules. Besides you edited post by someone with OG 11 rapidshare link on it but didnot remove the link.:crazyeye:
@man-h
i am surprised. But to clarify, it is not uncommon to express probability in percentage. Entirely acceptable to express it this way instead of fraction. By the way i hope my explaination suffices to dispell your doubts on that hexagon problem :-P
A jar contains 30 marbles, of which 20 are red and 10 are blue. If 9 of the marbles are removed, how many of the marbles left in the jar are red?
(1) Of the marbles removed, the ratio of the number of red ones to the number of blue ones is 2 : 1. (2) Of the first 6 marbles removed, 4 are red.
A Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D EACH Statement ALONE is sufficient. E Statements (1) and (2) TOGETHER are NOT sufficient.
A jar contains 30 marbles, of which 20 are red and 10 are blue. If 9 of the marbles are removed, how many of the marbles left in the jar are red?
(1) Of the marbles removed, the ratio of the number of red ones to the number of blue ones is 2 : 1. (2) Of the first 6 marbles removed, 4 are red.
A Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D EACH Statement ALONE is sufficient. E Statements (1) and (2) TOGETHER are NOT sufficient.
The answer is (A).
(1) The only possible combination is 6 red and 3 blue = 9 marbles. Hence the question can be answered.
(2) The fact that 4 out of the first 6 are red tells us nothing about the remaining 3 that were removed.
This questions seems too simple. Are there any angles that I have missed out? There surely must be some reason why it was posted here.
what are you saying man.........been more than active.....infact it was only yesterday that one of the moderators warned me to cool my heels a bit :argue: of all the people Neo chose my post to edit the download links that i had put up . as to discussions thread, you put up questions and i will try to answer, these days more in a cramming mode than doing questions hence myself dont have many to put here. Try this one
baseball' world series matches 2 teams against each other in a best of 7 games. The first team to win four games wins the series and no subsequent games are played. If you have no special info about either of teams what is the probability that the world series will consist of fewer than 7 games?
a. 12.5 b. 25 c. 31.25 d. 68.75 e. 75
dumbjoe,
Fewer than 7 games means : Exactly ( 4 or 5 or 6 ) games are played before the tournament is concluded ( either of the two teams won 4 games).
4 games : All games must be won by 1 team, assuming equal probability. (1/2) ^ 4.
Note: Since it could be any of the two teams, in the end we will multiply the answer by 2 to get final answer.
5 games : Last game must be won by the winning team, and out of previous 4 games, exactly 3 must be won by the winning team ( meaning that 1 and only 1 game must be won by the losing team.)
4C3 * (1/2)^4 * (1/2)
6 games: 6th game makes the winning team win 4 games, so they should previously have won exactly 3 more games out of 5 games.
5C3 * (1/2)^5 * (1/2)
Adding them together = (1/2)^4 + 4C1 * (1/2)^5 + 5C3 * (1/2)^6
= 275/8 ( in % )
Since either team could win the tournament; multiplying this by 2
baseball' world series matches 2 teams against each other in a best of 7 games. The first team to win four games wins the series and no subsequent games are played. If you have no special info about either of teams what is the probability that the world series will consist of fewer than 7 games?
a. 12.5 b. 25 c. 31.25 d. 68.75 e. 75
The cases in which there will be 7 matches is when in the first 6 games both teams have won 3 each. In all other cases there will be less than 7 matches. Hence the last match doesnt matter really. The total number of ways in which 6 matches can result is 2^6 = 64 ways. The ways in which the first 6 games can be won 3 each is 6 C 3 = 20. Hence required probablity is (64 - 20) * 100 / 64 = 68.75.
The cases in which there will be 7 matches is when in the first 6 games both teams have won 3 each. In all other cases there will be less than 7 matches. Hence the last match doesnt matter really. The total number of ways in which 6 matches can result is 2^6 = 64 ways. The ways in which the first 6 games can be won 3 each is 6 C 3 = 20. Hence required probablity is (64 - 20) * 100 / 64 = 68.75.
The cases in which there will be 7 matches is when in the first 6 games both teams have won 3 each. In all other cases there will be less than 7 matches. Hence the last match doesnt matter really. The total number of ways in which 6 matches can result is 2^6 = 64 ways. The ways in which the first 6 games can be won 3 each is 6 C 3 = 20. Hence required probablity is (64 - 20) * 100 / 64 = 68.75.
Hence D.
total number of ways is not 64 all matches need not be played dude .... It should be 2*(6c3+5c3+4c3+4c4)
total number of ways is not 64 all matches need not be played dude .... It should be 2*(6c3+5c3+4c3+4c4)
Guess not ! Each spot can be taken by either teams, meaning that 2 possibilities for each spot. Hence 6 spots, one after other, would mean that 2^6 by multiplication theorem.
total number of ways is not 64 all matches need not be played dude .... It should be 2*(6c3+5c3+4c3+4c4)
Guess not ! Each spot can be taken by either teams, meaning that 2 possibilities for each spot. Hence 6 spots, one after other, would mean that 2^6 by multiplication theorem. Remember that, this number is only for "exactly" 6 games, but not for any number of matches below 6.
total number of ways is not 64 all matches need not be played dude .... It should be 2*(6c3+5c3+4c3+4c4)
I have used the approach (Total number of ways - Not application ways). Total number of ways is the Universal set including when all 7 need to be played and when less than 7 are played.
@dumbJoe: Where are you?? Whats the answer? But considering that ChivaS and I reached the same answer by different approaches, I think D is the correct answer. DumbJoe do also provide the explanation and approach.
. 
But to clarify, it is not uncommon to express probability in percentage. Entirely acceptable to express it this way instead of fraction.