it is indeed a very good questions, certainly for those targeting 51 in quant. methodology is quite simple though,
h(n) = 2 * 2x2 * 2x3 * 2x4 * 2x5 * 2x6 * 2x7 * .................................... so if n is an even number, all numbers from 1 to n/2 are factors of h(n). This implies that for n=100. 1 to 50 are factors, the last prime number is 47 here. hence if we add 1 to h(n) we cannot get a factor among 1 to 50 for sure, because since h(n) was a multiple of each one of them individually, you need to add atleast the factor itself to get yet another multiple. Since the smallest prime number is 2, this requisite minimum accretion comes to 2.
Thanks Dumbjoe,
I had misread the question and left out the even part (.product of all even intergers from 2 to n inclusive)
Basically as you say h(100) = 2* 2*2* 2*3.... 2*50 => 2^50 * 50! so For h(100)+1 P has to be greater than 50???
For every positive even integer n, the function h(n) is defined to be the product of all even intergers from 2 to n inclusive. If p is the smallest prime factor of h(100) + 1, then p is
Page-287 of Kaplan 800 has a Question 5. I feel the solution is incorrect. Anyone tried? I tried to reason it myself but the answer seems to be incorrect!
Here is the question: A batch of cookies was divided among 3 tins: 2/3 of all the cookies were placed in either the blue tin or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin?
A)15/2 B)9/4 C)5/9 D)7/5 E)9/7
I got the answer as 5/7. It is not in the choices and Kaplan explains the answer as 5/9. Can anyone please help me how?
Is this the wrong place to ask? I put my question here because I dont check other threads and have developed a team like feel for this thread.
Edit:Moved both for your benefit as well as for others
I have been solving RS Aggarwal MBA book which covers various topics. However, some times there are topics which I don't think are asked in GMAT. For instance I found cube factorisation sums which I was solving. They aren't asked in GMAT right? So I just avoid topics or levels of sums I am not encountering?
I will try and find the DS Sharma IX and X books as well and go over it quickly to brush things up apart from the other things you guys mentioned.
What about IMS BRM? I see Keya had gone over them for quants. Should I purchase IMS material?
I have been solving RS Aggarwal MBA book which covers various topics. However, some times there are topics which I don't think are asked in GMAT. For instance I found cube factorisation sums which I was solving. They aren't asked in GMAT right? So I just avoid topics or levels of sums I am not encountering?
I will try and find the DS Sharma IX and X books as well and go over it quickly to brush things up apart from the other things you guys mentioned.
What about IMS BRM? I see Keya had gone over them for quants. Should I purchase IMS material?
The OG11 and Kaplan Maths should be sufficient I believe. You can also check esnips.com for the quants material. IMS material is more oriented towards CAT.
GMAT quants is relatively easier than CAT. VA needs more specific focus is what I feel.
I have been solving RS Aggarwal MBA book which covers various topics. However, some times there are topics which I don't think are asked in GMAT. For instance I found cube factorisation sums which I was solving. They aren't asked in GMAT right? So I just avoid topics or levels of sums I am not encountering?
I will try and find the DS Sharma IX and X books as well and go over it quickly to brush things up apart from the other things you guys mentioned.
What about IMS BRM? I see Keya had gone over them for quants. Should I purchase IMS material?
Keya might have got her reasons for following the IMS stuff, but it is usually considered way too much for GMAT. I dont say it aint good but it may be more than what you need. I would again say, give a few sectional tests so that you can understand what GMAT wants, then revise accordingly, because you would find that in DS or quant silly mistakes would hurt you as much if not more than not knowing about the right approach. Geometry is the only area which can bleed you if you dont have a good grip over the properties and theorems (only the very basic which CBSE NCERT books' chapter revisions should suffice, if not then a few RD sharma solve examples should do well to make things clear) But please dont overdo the whole exercise. OG 11 and OG MAths workbook are the benchmark for what and how much you need to know. It is not possible to write everything here, i hope others can suggest things which didnt occur to me.
1.For every positive integer n, the function f(n) is defined to be the product of all the Even integer from 2 to n, inclusive. If p is the smallest Prime factor of h(100)+1, then p is:-
A.Between 2 and 10 B.Between 10 and 20 C.Between 20 and 30 D.Between 30 and 40 E.Greater than 50
1.For every positive integer n, the function f(n) is defined to be the product of all the Even integer from 2 to n, inclusive. If p is the smallest Prime factor of h(100)+1, then p is:-
A.Between 2 and 10 B.Between 10 and 20 C.Between 20 and 30 D.Between 30 and 40 E.Greater than 50
Thanks in advance.....................:(
Hi!
Tis question has been well explained by Dumbjoe here...
I am new in the forum and new to world of MBA aspirant. I am going to start preparing for GMAT, can you guys pls suggest me which book is good for GMAT preparation.
1.For all positive integers m, = 3m where m is odd and = 1/2 m where m is even.Which of the following is equivalent to * a)81 b)54 c)36 d)27 e)18
2.At a dinner party, 5 people are to be seated around a circular table .Two seating arrangements are considered different only when the position of people are different relative to each other.What is the total number of different possible seating arrangement for the group. a)5 b)10 c)24 d)32 e)120
1.For all positive integers m, = 3m where m is odd and = 1/2 m where m is even.Which of the following is equivalent to * a)81 b)54 c)36 d)27 e)18
2.At a dinner party, 5 people are to be seated around a circular table .Two seating arrangements are considered different only when the position of people are different relative to each other.What is the total number of different possible seating arrangement for the group. a)5 b)10 c)24 d)32 e)120
Plz post the explanations.....
= 3*9 = 27 = (1/2)*6 = 3 and 27 times 3 is 81. So choice A. Is there anything which i missed?? ----------------------------------------------- Ans = (5-1)! = 4! = 24 This is ring permutation. If total is N then N-1 factorial is the number of possible arrangements.
= 3*9 = 27 = (1/2)*6 = 3 and 27 times 3 is 81. So choice A. Is there anything which i missed?? ----------------------------------------------- Ans = (5-1)! = 4! = 24 This is ring permutation. If total is N then N-1 factorial is the number of possible arrangements.
Hi... In 1st question even i chose 81 but i got it wrong.......Ans is 27 neone can explain why ans. is 27.......
I am new in the forum and new to world of MBA aspirant. I am going to start preparing for GMAT, can you guys pls suggest me which book is good for GMAT preparation.
Thanks Sumit
Hi Sumit.
It depends when you are planning for the test. If you have sufficient time at hand (more than 4 months) then start with downloads from websites and all. give 1 -2 diag tests available online free on scores of websites.
If you have 2 months or less, start with OG11. Thats the starting point.
Then on, you will know which area to work on more. Best of luck. We all are in the same boat.
Please solve the following questions: 1.What is the total number of integers between 100 and 200 that are divisible by 3? (A) 33 (B) 32 (C) 31 (D) 30 (E) 29
2.If n is an integer and n = (2 . 3 . 5 . 7 . 11 . 13)/77k then which of the following could be the value of k? (A) 22 (B) 26 (C) 35 (D) 54 (E) 60
3. In the formula w=p/v^(1/t) , integers p and t are positive constants. If w =2 when v = 1 and if w=1/2 when v = 64, then t = (A) 1 (B) 2 (C) 3 (D) 4 (E) 16
4. Length = 20 in, Breadth = 8 in, Height = 2 in. The figure above shows the dimensions of a rectangular box that is to be completely wrapped with paper. If a single sheet of paper is to be used without patching, then the dimensions of the paper could be (A) 17 in by 25 in (B) 21 in by 24 in (C) 24 in by 12 in (D) 24 in by 14 in (E) 26 in by 14 in
5. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N? (A) 86 (B) 52 (C) 34 (D) 28 (E) 10
6. The R students in a class agree to contribute equally to buy their teacher a birthday present that costs y dollars. If x of the students later fail to contribute their share, which of the following represents the additional number of dollars that each of the remaining students must contribute in order to pay for the present? (A) y/R (B) y/(R-x) (C) xy/(R-x) (D) xy/R(R-x) (E) y/R(R-x)
Please solve the following questions: 1.What is the total number of integers between 100 and 200 that are divisible by 3? (A) 33 (B) 32 (C) 31 (D) 30 (E) 29
2.If n is an integer and n = (2 . 3 . 5 . 7 . 11 . 13)/77k then which of the following could be the value of k? (A) 22 (B) 26 (C) 35 (D) 54 (E) 60
3. In the formula w=p/v^(1/t) , integers p and t are positive constants. If w =2 when v = 1 and if w=1/2 when v = 64, then t = (A) 1 (B) 2 (C) 3 (D) 4 (E) 16
4. Length = 20 in, Breadth = 8 in, Height = 2 in. The figure above shows the dimensions of a rectangular box that is to be completely wrapped with paper. If a single sheet of paper is to be used without patching, then the dimensions of the paper could be (A) 17 in by 25 in (B) 21 in by 24 in (C) 24 in by 12 in (D) 24 in by 14 in (E) 26 in by 14 in
5. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N? (A) 86 (B) 52 (C) 34 (D) 28 (E) 10
6. The R students in a class agree to contribute equally to buy their teacher a birthday present that costs y dollars. If x of the students later fail to contribute their share, which of the following represents the additional number of dollars that each of the remaining students must contribute in order to pay for the present? (A) y/R (B) y/(R-x) (C) xy/(R-x) (D) xy/R(R-x) (E) y/R(R-x)
Also please explain the answers.
1) For no. of integers divisible it means, the no. of multiples. just divide with the number. the integer less than equal to that is the number.
so between 100 and 200... the ans is 200/3-100/3 (removing muliples less than 100 from 200) 33.
2) 2.3.5.7.11.13/77k -> 2.3.5.13/k so its obvious that k can be 26 only
3) w=p/v^(1/t). when v=1; w=2 which means p=2 when v=64;w=1/2... so 1/2= 2/64^(1/t).... 1/2^2 = 1/64^(1/t) ..64=2^6...as the bases are equal the powers shud be equal.. so 2=6/t which gives t =3
4) didnt understand
5) M= 6p+1 N=6k+3.. so M+N = 6(p+k)+4.. so we have to check numbers which doesnt give remainder 4..so its clearly 86
6) x people fail. so the extra amount is xy/R... y/R was supposed to be each ones contribution. so each one has to pay xy/R(R-x)