Hi...
In 1st question even i chose 81 but i got it wrong.......Ans is 27 neone can explain why ans. is 27.......
print mistake

Hi...
In 1st question even i chose 81 but i got it wrong.......Ans is 27 neone can explain why ans. is 27.......
Some more doubts...
7. A family made a down payment of $75 and borrowed the balance on a set of encyclopedias that cost $400. The balance with interest was paid in 23 monthly payments of $16 each and a final payment of $9. The amount of interest paid was what percent of the amount borrowed?
Hey Shubh,
Some doubts...
8. Are you sure there is no other data given? Is E the midpoint of AD?
=> Yes that is all the data
10. Choice (B)
Since AB = BC= AC - Its an equilateral. Similar for the other side.
Symetric figure so Angle split into half by the chord.
=> Given AB = BC = CD, and as I see, BC and CD are arcs and no line segments.
13. Choice(D)
vt = d
(v+5)(t+1) = d+70
(V+10)(t+2) = D+x
Solving for x, we get x = 150
=> I'd gotten so far, but din't know how to proceed. Need help solving the equations.
14. => I took the equations as
3.5c + 1w = 63.5
c + w = 22
was I wrong??
What made you translate the statemets to "1 question wrong implies he loses 3.5 +1 = 4.5 marks"
14. He would have gained 3.5 had he done the question correctly. He lost that and also lost another 1 mark by doing it wrong. So total he lost 4.5 marks doing 1 question wrong. I hope this explains.
13. solving eqn 2 , vt + 5t + 5 + v= d+ 70
implies d + 5t + 5 + v= d+ 70
implies 5t + v= 65
Solving eqn 3, vt + 10t + 2v + 20 = d + X
implies d +2(5t+v) + 20 = d + X
implies 2(5t+v) + 20 = X
implies X = 2(65)+ 20 = 130+ 20 = 150
Thanks,
Hi,
I need to start prep for Problem Solving.
Can sb plz suggest me where to start with.
Also, i need OG 11 - PS, can sb help me on this one.
Thanks in advance.
20. On July 1, 1982, Ms. Fox deposited $10,000 in a new account at the annual interest rate of 12 percent compounded monthly. If no additional deposits or withdrawals were made and if interest was credited on the last day of each month, what was the amount of money in the account on September 1, 1982?
(A) $10,200
(B) $10,201
(C) $11,100
(D) $12,100
(E) $12,544
21. Fig attached
The outline of a sign for an ice-cream store is made by placing of the circumference of a circle with radius 2 feet on top of an isosceles triangle with height 5 feet, as shown above. What is the perimeter, in feet, of the sign?
(A) 3pi + 3(3)^1/2
(B) 3pi + 6(3)^1/2
(C) 3pi + 2(32)^1/2
(D) 4pi + 3(3)^1/2
(E) 4pi + 6(3)^1/2
22. A merchant purchased a jacket for $60 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 25 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant's gross profit on this sale?
(A) $0
(B) $3
(C) $4
(D) $12
(E) $15
Answers:
7 D 8 B 9 C 10 B 11 D 12 B 13 D
14 A 15 B 16 B 17 C 18 C 19 C 20 B
21 B 22 C
PS: what are png files? How do i open them??
Hi,
The answer should be E. Becase BC may or may not be smaller than CD.
e.g. If CD = 5 then BC = 10 but if CD = 7 then BC = 6
Remember BC = 20 - (CD+AB) = 20 - 2CD
give the solution too
Hi Sumit, I din't get which question you were trying to answer. Please specify the number of the question.
And yes, I'm putting up so many questions as they are the ones I'm unable to solve and my question bank does not have solutions/explanations provided.
PFA some more...
~
8. Fig attached
If each side of Triangle ACD above has length 3 and if AB has length 1, what is the area of region BCDE? -> Answer is B
(A) 9/4
(B) 7/4 * 3^(1/2)
(C) 9/4 * 3^(1/2)
(D) 7/2 * 3^(1/2)
(E) 6 + 3^(1/2)
Solution : Angle A = 60 ang E inside Triangle ABE = 30 using trigo area of this is root 3 by 2 and the area of triagle is 9 root 3 by 4 hence area is 7 root 3 by 4
Help me with this guys!
The figure attached shows the shape of a tunnel entrance. If the curved portion is of a circle and the base of the entrance is 12 feet across, what is the perimeter, in feet, of the curved poition of the entrance?
Answers:
9Pi
12Pi
9Pi sq.root of 2
18Pi
9Pi/(sq.root of 2)
Help me with this guys!
The figure attached shows the shape of a tunnel entrance. If the curved portion is of a circle and the base of the entrance is 12 feet across, what is the perimeter, in feet, of the curved poition of the entrance?
Answers:
9Pi
12Pi
9Pi sq.root of 2
18Pi
9Pi/(sq.root of 2)
Answer: 9 Pi sq. root of 2..
o-range SaysCan you provide explanation please
Hi,
Can I please get the solution explanations to the questions attached?? I have many more to post.
Hi,
Can I please get the solution explanations to the questions attached?? I have many more to post.
Here they are..
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6509d1182437946-gmat-problem-solving-discussions-1.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6510d1182437946-gmat-problem-solving-discussions-2.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6511d1182437946-gmat-problem-solving-discussions-3.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6512d1182437946-gmat-problem-solving-discussions-4.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6513d1182437946-gmat-problem-solving-discussions-5.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6514d1182438055-gmat-problem-solving-discussions-6.jpg
Here they are..
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6514d1182438055-gmat-problem-solving-discussions-6.jpg
Just got to see the first one...
The 2 tight angled triangles are similar..
the hypothenuse being 5, the other 2 sides are 3 and 4 respectively... SImilarly... the side of length 4 and of length 8 are corresponding sides of a pair of similar triangles..
SO if we subtract the area of of FED from FAB, we will get the area of the required quad.
FAB = 1/2*(base*ht) = 1/2*(8*6) = 24; and
FED = 1/2*(4*3) = 6
Therefore, area of Quad. ABED = 24-6 = 18 .. Option (e).