GMAT Problem Solving Discussions

Hi...
In 1st question even i chose 81 but i got it wrong.......Ans is 27 neone can explain why ans. is 27.......


print mistake
Some more doubts...

7. A family made a down payment of $75 and borrowed the balance on a set of encyclopedias that cost $400. The balance with interest was paid in 23 monthly payments of $16 each and a final payment of $9. The amount of interest paid was what percent of the amount borrowed?
(A) 6%
(B) 12%
(C) 14%
(D) 16%
(E) 20%

8. Fig attached
If each side of Triangle ACD above has length 3 and if AB has length 1, what is the area of region BCDE?
(A) 9/4
(B) 7/4 * 3^(1/2)
(C) 9/4 * 3^(1/2)
(D) 7/2 * 3^(1/2)
(E) 6 + 3^(1/2)

9. Fig attached
In 1980, approximately what fraction of the cost to the consumer for the production of 6 ounces of frozen orange juice went to the farmer?
(A) 3/11
(B) 1/3
(C) 4/9
(D) 5/9
(E) 3/5

10. Fig attached
If A is the center of the circle shown above and AB=BC=CD, what is the value of x?
(A) 15
(B) 30
(C) 45
(D) 60
(E) 75

11. In each production lot for a certain toy, 25 percent of the toys are red and 75 percent of the toys are blue. Half the toys are size A and half are size B. If 10 out of a lot of 100 toys are red and size A, how many of the toys are blue and size B?
(A) 15 (B) 25 (C) 30
(D) 35 (E) 40

12. What is the least possible product of 4 different integers, each of which has a value between -5 and 10, inclusive?
(A) -5040 (B) -3600
(C) -720 (D) -600
(E) -120

13. If a motorist had driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 70 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 2 hours longer and at an average rate of 10 miles per hour faster on that day?
(A) 100 (B) 120 (C) 140
(D) 150 (E) 160

14. A student responded to all of the 22 questions on a test and received a score of 63.5. If the scores were derived by adding 3.5 points for each correct answer and deducting 1 point for each incorrect answer, how many questions did the student answer incorrectly?
(A) 3
(B) 4
(C) 15
(D) 18
(E) 20

15. One-fifth of the light switches produced by a certain factory are defective. Four-fifths of the defective switches are rejected and of the nondefective switches are rejected by mistake. If all the switches not rejected are sold, what percent of the switches sold by the factory are defective?
(A) 4%
(B) 5%
(C) 6.25%
(D) 11%
(E) 16%

16. Fig attached
In Triangle PQS above, if PQ =3 and PS = 4, then PR =
(A) 9/4
(B) 12/5
(C) 16/5
(D) 15/4
(E) 20/3

17. Fig attached
In the figure above, two rectangles with the same dimensions overlap to form the shaded region. If each rectangle has perimeter 12 and the shaded region has perimeter 3, what is the total length of the heavy line segments?
(A) 15 (B) 18 (C) 21
(D) 22 (E) 23

18. If an organization were to sell n tickets for a theater production, the total revenue from ticket sales would be 20 percent greater than the total costs of the production. If the organization actually sold all but 5 percent of the n tickets, the total revenue from ticket sales was what percent greater than the total costs of the production?
(A) 4% (B) 10% (C) 14%
(D) 15% (E) 18%

19. How many liters of pure alcohol must be added to a 100-liter solution that is 20 percent alcohol in order to produce a solution that is 25 percent alcohol?
(A) 7/2
(B) 5
(C) 20/3
(D) 8
(E) 39/4
Some more doubts...

7. A family made a down payment of $75 and borrowed the balance on a set of encyclopedias that cost $400. The balance with interest was paid in 23 monthly payments of $16 each and a final payment of $9. The amount of interest paid was what percent of the amount borrowed?


7. Choice(D)
Net paid over total cost = interest = 52$
Borrowed amount = 325
Percent = approx 16%

8. Are you sure there is no other data given? Is E the midpoint of AD?

9. Rough Calculation - Approx = Choice (C)
44.44/100 = 4/9

10. Choice (B)
Since AB = BC= AC - Its an equilateral. Similar for the other side.
Symetric figure so Angle split into half by the chord.

11. Choice (D)
A is 50 which includes 10 Red and so that means 40 are Blue.
This implies B is 50 means - 15 are Red and 35 are Blue. Hence the answer.

12. Choice(B)
10 * 9 * 8* 7 = But is +ve so ignore.
10 * 9 * 8* -5 = -3600 This is the answer.

13. Choice(D)
vt = d
(v+5)(t+1) = d+70
(V+10)(t+2) = D+x
Solving for x, we get x = 150

14. Choice (A)
Full marks = 3.5* 22 = 77
1 question wrong implies he loses 3.5 +1 = 4.5 marks
He made 3 mistakes so lost 13.5 marks. Hence score now is 77-13.5 = 63.5

15. Question typing error- rejected and of the nondefective switches ??? are rejected by mistake.
The data says if total 100 switches manufactured, then 16 are defective and rejected,
4 are defective and rejected. So based on the numbers of the non-defective switches incorrectly rejected, we can solve this question.

16. Choice (B)
(1/2)3*4 = (1/2)* 5X

17. Good question but would need to know which is less heavy line segment. Can yo please rename the points?

18. Choice (C)
N(Selling price per unit) = 1.2 (Cost Price)
Implies , 0.95 NS = 0.95*1.2 CP = 1.14 CP
So 14% Profit

19. Choice (C)
Back solving : Alcohol(in 100 lit) + Pure alochol
------------------------------------------- = (25%) = (25/100)
Total Solution + Pure Alcohol
20 + (20/3)
=----------------
100+ 20/3
This answer choice hits.. so C.

Please post the answers. Thanks.

Hey Shubh,

Some doubts...

8. Are you sure there is no other data given? Is E the midpoint of AD?
=> Yes that is all the data

10. Choice (B)
Since AB = BC= AC - Its an equilateral. Similar for the other side.
Symetric figure so Angle split into half by the chord.
=> Given AB = BC = CD, and as I see, BC and CD are arcs and no line segments.

13. Choice(D)
vt = d
(v+5)(t+1) = d+70
(V+10)(t+2) = D+x
Solving for x, we get x = 150
=> I'd gotten so far, but din't know how to proceed. Need help solving the equations.

14. => I took the equations as
3.5c + 1w = 63.5
c + w = 22
was I wrong??
What made you translate the statemets to "1 question wrong implies he loses 3.5 +1 = 4.5 marks"

14. He would have gained 3.5 had he done the question correctly. He lost that and also lost another 1 mark by doing it wrong. So total he lost 4.5 marks doing 1 question wrong. I hope this explains.

13. solving eqn 2 , vt + 5t + 5 + v= d+ 70
implies d + 5t + 5 + v= d+ 70
implies 5t + v= 65
Solving eqn 3, vt + 10t + 2v + 20 = d + X
implies d +2(5t+v) + 20 = d + X
implies 2(5t+v) + 20 = X
implies X = 2(65)+ 20 = 130+ 20 = 150

Thanks,

Hi,
I need to start prep for Problem Solving.
Can sb plz suggest me where to start with.
Also, i need OG 11 - PS, can sb help me on this one.

Thanks in advance.

20. On July 1, 1982, Ms. Fox deposited $10,000 in a new account at the annual interest rate of 12 percent compounded monthly. If no additional deposits or withdrawals were made and if interest was credited on the last day of each month, what was the amount of money in the account on September 1, 1982?
(A) $10,200
(B) $10,201
(C) $11,100
(D) $12,100
(E) $12,544

21. Fig attached
The outline of a sign for an ice-cream store is made by placing of the circumference of a circle with radius 2 feet on top of an isosceles triangle with height 5 feet, as shown above. What is the perimeter, in feet, of the sign?
(A) 3pi + 3(3)^1/2
(B) 3pi + 6(3)^1/2
(C) 3pi + 2(32)^1/2
(D) 4pi + 3(3)^1/2
(E) 4pi + 6(3)^1/2

22. A merchant purchased a jacket for $60 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 25 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant's gross profit on this sale?
(A) $0
(B) $3
(C) $4
(D) $12
(E) $15


Answers:
7 D 8 B 9 C 10 B 11 D 12 B 13 D
14 A 15 B 16 B 17 C 18 C 19 C 20 B
21 B 22 C

PS: what are png files? How do i open them??

Hi,
The answer should be E. Becase BC may or may not be smaller than CD.
e.g. If CD = 5 then BC = 10 but if CD = 7 then BC = 6
Remember BC = 20 - (CD+AB) = 20 - 2CD

give the solution too

Hi Sumit, I din't get which question you were trying to answer. Please specify the number of the question.
And yes, I'm putting up so many questions as they are the ones I'm unable to solve and my question bank does not have solutions/explanations provided.

PFA some more...


~

8. Fig attached
If each side of Triangle ACD above has length 3 and if AB has length 1, what is the area of region BCDE? -> Answer is B
(A) 9/4
(B) 7/4 * 3^(1/2)
(C) 9/4 * 3^(1/2)
(D) 7/2 * 3^(1/2)
(E) 6 + 3^(1/2)

Solution : Angle A = 60 ang E inside Triangle ABE = 30 using trigo area of this is root 3 by 2 and the area of triagle is 9 root 3 by 4 hence area is 7 root 3 by 4

Help me with this guys!

The figure attached shows the shape of a tunnel entrance. If the curved portion is of a circle and the base of the entrance is 12 feet across, what is the perimeter, in feet, of the curved poition of the entrance?


Answers:
9Pi
12Pi
9Pi sq.root of 2
18Pi
9Pi/(sq.root of 2)

Help me with this guys!

The figure attached shows the shape of a tunnel entrance. If the curved portion is of a circle and the base of the entrance is 12 feet across, what is the perimeter, in feet, of the curved poition of the entrance?


Answers:
9Pi
12Pi
9Pi sq.root of 2
18Pi
9Pi/(sq.root of 2)


Answer: 9 Pi sq. root of 2..

Answer: 9 Pi sq. root of 2..



Can you provide explanation please
o-range Says
Can you provide explanation please


Consider it like a circle (3/4th) intercepted by a chord.

Since it is 3/4th the angle will be 270 degrees... therefore the other angle will be 90 degrees..

COnsider the right angles triangle at the centre.. the hypothenuse will be the base of the tunnel (which is given as 12 ft)..

by pythagorous theorom.. hypothenuse sq. = side sq + side sq.

Each side in this figure wil be equal to the radius R

Equation is:

12 sq = R sq + R sq

therefore R = 6 * sq rt of 2

and perimiter will be 2 Pi R = 2 * Pi * 6 sq rt of 2 which will give u the answer..

Hi,

Can I please get the solution explanations to the questions attached?? I have many more to post.

Hi,

Can I please get the solution explanations to the questions attached?? I have many more to post.


Where's the attachment dude?

Here they are..

http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6509d1182437946-gmat-problem-solving-discussions-1.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6510d1182437946-gmat-problem-solving-discussions-2.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6511d1182437946-gmat-problem-solving-discussions-3.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6512d1182437946-gmat-problem-solving-discussions-4.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6513d1182437946-gmat-problem-solving-discussions-5.jpg
http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6514d1182438055-gmat-problem-solving-discussions-6.jpg

Here they are..

http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6514d1182438055-gmat-problem-solving-discussions-6.jpg




Just got to see the first one...

The 2 tight angled triangles are similar..

the hypothenuse being 5, the other 2 sides are 3 and 4 respectively... SImilarly... the side of length 4 and of length 8 are corresponding sides of a pair of similar triangles..

SO if we subtract the area of of FED from FAB, we will get the area of the required quad.

FAB = 1/2*(base*ht) = 1/2*(8*6) = 24; and
FED = 1/2*(4*3) = 6

Therefore, area of Quad. ABED = 24-6 = 18 .. Option (e).
Just got to see the first one...

The 2 tight angled triangles are similar..

the hypothenuse being 5, the other 2 sides are 3 and 4 respectively... SImilarly... the side of length 4 and of length 8 are corresponding sides of a pair of similar triangles..

SO if we subtract the area of of FED from FAB, we will get the area of the required quad.

FAB = 1/2*(base*ht) = 1/2*(8*6) = 24; and
FED = 1/2*(4*3) = 6

Therefore, area of Quad. ABED = 24-6 = 18 .. Option (e).

For - http://www.pagalguy.com/forum/attach...cussions-2.jpg

Prob 24 -
82% is 138 gallons, so 124 gallons is roughly 72%
Hence, its 28% short of full capacity, answer is (D) 30%

Prob 25 - 1/10% of 5000 is 5.
1/10 of 5000 is 500.. Diff is 495, hence answer is (D) 495

Prob 26 - Answer by symmetry direct is y=1, hence answer is (E) 1

--------------------------------

For - http://www.pagalguy.com/forum/attach...cussions-3.jpg
Prob 27 - Answer can never be 0.. 1/(x-1) if equal to 0, leaves us with no equation...for this expression to be 0, (x-1) should be infinity, which is mathematically not representable....Answer is (B) 0

Prob 28 - Ans is (E) 23/37 .. Hmm strategy - well, 1/3 and 2/3 are 0.3333 and 0.6666 resp, 41/99 and 2/11 will always have 2 decimal recurring...left with 23/27 - u can chk it - it has 3 decimal recurring

Prob 29 - Ans is (E) 3
He loses 7 individual socks, and for getting max number of pairs, we have to assume that he lost 6 individual socks which formed pairs and 1 more. Hence, he lost 4 pairs (As the lone socks will not form a pair) - hence he will be left with 6 socks, that is 3 pairs and hence the answer.

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For - http://www.pagalguy.com/forum/attach...cussions-4.jpg
Prob 30: x^2 + 3x + k = 10...4 is one solution,
sum of the roots is -(b/a) which is -3...
4 is a root, hence other root has to be -7, therefore sol is: (A) -7

Prob 30: Min value of n can be 0, as n= -1 reduces the expression to 0 which is not greater than 1.. Max value of n is 3 as n=4, makes 5n + 5 = 25, which is not less than 25 (its equal to)...
hence, the solution set is 0,1,2,3..which makes it 4 integer solutions...Hence, answer is (B)
Prob 32: Direct qn - Ans is (B), as B gives 2 as the sq rt of 4, which is not a square of any integer..Other options are 1, 9, 16 and 36 which are squares.

Prob 33: Sq rt of 5 is roughly 2.2 as 23 squared is 529. Hence 2.2 + 1 = 3.2 divided by 2 is 1.6...Hence 8 to 5 i.e (A) is the answer

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