the hypothenuse being 5, the other 2 sides are 3 and 4 respectively... SImilarly... the side of length 4 and of length 8 are corresponding sides of a pair of similar triangles..
SO if we subtract the area of of FED from FAB, we will get the area of the required quad.
FAB = 1/2*(base*ht) = 1/2*(8*6) = 24; and FED = 1/2*(4*3) = 6
Therefore, area of Quad. ABED = 24-6 = 18 .. Option (e).
Prob 35: If u notice the figure - there are 5 cities, and u dots are in the form of 4,3,2,1... So, in general for n cities - u will (n-1) + (n-2) + (n-3) + ... 1 number of dots.. For 30 cities - it shud be 1+ 2 + ... + 29 .. Applying the formula n*(n+1)/2 => (29*30)/2 = 435, answer is (B) ----------------------------------------------------------------- For - http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6514d1182438055-gmat-problem-solving-discussions-6.jpg Prob 36 - Ans is (E), because we need the exp like: -4 hence x + 1 Prob 37 - Answer is (E) 5/8. If the day crew has 'x' workers and each load 'y' boxes, total boxes loaded = x.y As per problem, night crew has 4/5x workers and each load 3/4y boxes, hence total boxes loaded - 3/5x.y Hence, the required ratio is (x.y)/{(x.y) + (3/5)x.y} = 5/8
Prob 24 - 82% is 138 gallons, so 124 gallons is roughly 72% Hence, its 28% short of full capacity, answer is (D) 30%
Prob 25 - 1/10% of 5000 is 5. 1/10 of 5000 is 500.. Diff is 495, hence answer is (D) 495
Prob 26 - Answer by symmetry direct is y=1, hence answer is (E) 1
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For - http://www.pagalguy.com/forum/attach...cussions-3.jpg Prob 27 - Answer can never be 0.. 1/(x-1) if equal to 0, leaves us with no equation...for this expression to be 0, (x-1) should be infinity, which is mathematically not representable....Answer is (B) 0
Prob 28 - Ans is (E) 23/37 .. Hmm strategy - well, 1/3 and 2/3 are 0.3333 and 0.6666 resp, 41/99 and 2/11 will always have 2 decimal recurring...left with 23/27 - u can chk it - it has 3 decimal recurring
Prob 29 - Ans is (E) 3 He loses 7 individual socks, and for getting max number of pairs, we have to assume that he lost 6 individual socks which formed pairs and 1 more. Hence, he lost 4 pairs (As the lone socks will not form a pair) - hence he will be left with 6 socks, that is 3 pairs and hence the answer.
----------------------------------- For - http://www.pagalguy.com/forum/attach...cussions-4.jpg Prob 30: x^2 + 3x + k = 10...4 is one solution, sum of the roots is -(b/a) which is -3... 4 is a root, hence other root has to be -7, therefore sol is: (A) -7
Prob 30: Min value of n can be 0, as n= -1 reduces the expression to 0 which is not greater than 1.. Max value of n is 3 as n=4, makes 5n + 5 = 25, which is not less than 25 (its equal to)... hence, the solution set is 0,1,2,3..which makes it 4 integer solutions...Hence, answer is (B) Prob 32: Direct qn - Ans is (B), as B gives 2 as the sq rt of 4, which is not a square of any integer..Other options are 1, 9, 16 and 36 which are squares.
Prob 33: Sq rt of 5 is roughly 2.2 as 23 squared is 529. Hence 2.2 + 1 = 3.2 divided by 2 is 1.6...Hence 8 to 5 i.e (A) is the answer
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Answers to the questions: 24 E 25 D 26 E 27 B 28 E 29 B 30 A 31 B 32 B 33 A 34 B 35 B 36 E 37 E 38 C 39 E 40 C 41 D 42 D 43 D 44 C 45 D 46 E 47 C
Hi All, Help needed on these 2 questions below. Little explanation is actually needed. I have listed the answers below too. On a certain road, 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit dont receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit? A.10.5% B.12.5% C.15% D.22% E. 30% Can anyone please explain the solution to this? I am not able to understand the data in the question. Answer is 12.5% 2. If d>0 and 0I.C>0 II.c/d III.c2 + d2 >1 A.I only B.II only C.I and II only D. II and III only E. I , II and III (I thought the option E is correct, but it is C. My reasoning : Whatever be the case, c2+d2 (C square+ d square) would always be greater than 1 because they are positives and addition of integers/real numbers) since 1-c/d is less than 1. Can anyone please explain?
On a certain road, 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit dont receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit? A.10.5% B.12.5% C.15% D.22% E. 30%
1. B) Total Motorist = 100 Total Motorist who o/speed = x X = (o/speeding who get ticket (10%* 100) + o/speeding no ticket) Speeding no ticket = 20% of those who o/speed => Speeding with ticket = 80 % of those who o/speed =>10 = 80%(x) =>x=12.5%
Need help on the question in the attachment. Please post the explanation.
Hi!
Avg = 124 Median = 140 No of wood pieces = 5 =>Median is the third piece in increasing order of length. =>For median to be 140; Length for biggest 3 pieces has to be atleast 140 cms=> =>Total length of these 3 pieces = 420 =>Remaining 2 pieces to be 200 cms =>(140 * 3 + 100*2)/5 =>Hence Answer is 100
Prob 35: If u notice the figure - there are 5 cities, and u dots are in the form of 4,3,2,1... So, in general for n cities - u will (n-1) + (n-2) + (n-3) + ... 1 number of dots.. For 30 cities - it shud be 1+ 2 + ... + 29 .. Applying the formula n*(n+1)/2 => (29*30)/2 = 435, answer is (B) ----------------------------------------------------------------- For - http://www.pagalguy.com/forum/attachments/gmat-and-related-discussions/6514d1182438055-gmat-problem-solving-discussions-6.jpg Prob 36 - Ans is (E), because we need the exp like: -4 hence x + 1| Prob 37 - Answer is (E) 5/8. If the day crew has 'x' workers and each load 'y' boxes, total boxes loaded = x.y As per problem, night crew has 4/5x workers and each load 3/4y boxes, hence total boxes loaded - 3/5x.y Hence, the required ratio is (x.y)/{(x.y) + (3/5)x.y} = 5/8
. A couple of admits from top schools and a few aspirants have already agreed to join in:smile:. Interested Chennai or nearby 
