Pls help.........
2 persons each make a single throw with a pair of dice.Find the probability that the throws are equal?
i dont remember the choices.......
one more..........
There are n stations between two cities A & B. A train is to stop at 3 of these n stations.What is the probability that no two of these stations are consecutive?
QUestions I was not able to solve.Please find time to solve and respond:
1: For every positive integer n h(n) is product of all even interegrs 2 to n inclusive.If P is the smallest prime factor of h(100)+1 , then p lies between:
Options are:
A: Between 2 and 10
B:Between 10 and 20
C:Between 20 and 30
D:Between 30 and 40
E: greater than 40
2:Alice's take home pay last year was the same each month and she saved the same fraction of her take home pay each month.The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take home pay that she did not save. If all the money that she saved last year was from her take home pay, what fraction of her take home pay did save each month.
Answer options:
A 1/2
B 1/3
C 1/4
D 1/5
E 1/6
QUestions I was not able to solve.Please find time to solve and respond:
1: For every positive integer n h(n) is product of all even interegrs 2 to n inclusive.If P is the smallest prime factor of h(100)+1 , then p lies between:
Options are:
A: Between 2 and 10
B:Between 10 and 20
C:Between 20 and 30
D:Between 30 and 40
E: greater than 40
2:Alice's take home pay last year was the same each month and she saved the same fraction of her take home pay each month.The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take home pay that she did not save. If all the money that she saved last year was from her take home pay, what fraction of her take home pay did save each month.
Answer options:
A 1/2
B 1/3
C 1/4
D 1/5
E 1/6
For the second question i got the ans as 3/4. This is the approach .......i dont know i'm correct b/c i didn't get an ans frm choice.
take home pay=x
saving=y
12*y=3*12*(x-y)
=> y=3/4
QUestions I was not able to solve.Please find time to solve and respond:
1: For every positive integer n h(n) is product of all even interegrs 2 to n inclusive.If P is the smallest prime factor of h(100)+1 , then p lies between:
Options are:
A: Between 2 and 10
B:Between 10 and 20
C:Between 20 and 30
D:Between 30 and 40
E: greater than 40
2:Alice's take home pay last year was the same each month and she saved the same fraction of her take home pay each month.The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take home pay that she did not save. If all the money that she saved last year was from her take home pay, what fraction of her take home pay did save each month.
Answer options:
A 1/2
B 1/3
C 1/4
D 1/5
E 1/6
Ok, the answer to 2nd question is:
D 1/5
Assume alice take home is 50, she saves 1/5 of that which is 10. The remainder she spends, 40.
Saving for the year = 10 x 12 = 120
40 x 3 = 120
There you have it.
PS; had to register here to answer your question.
QUestions I was not able to solve.Please find time to solve and respond:
1: For every positive integer n h(n) is product of all even interegrs 2 to n inclusive.If P is the smallest prime factor of h(100)+1 , then p lies between:
Options are:
A: Between 2 and 10
B:Between 10 and 20
C:Between 20 and 30
D:Between 30 and 40
E: greater than 40
2:Alice's take home pay last year was the same each month and she saved the same fraction of her take home pay each month.The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take home pay that she did not save. If all the money that she saved last year was from her take home pay, what fraction of her take home pay did save each month.
Answer options:
A 1/2
B 1/3
C 1/4
D 1/5
E 1/6
2nd question one is already answered so i will answer only the 1st one.
Well h(100) + 1 = > 2*4*....*100 + 1 ==> (2*1)*(2*2)...*(2*50) + 1
so we can reduce h(100) + 1 = 2^50(1*2*...*50) + 1.
for any given number to be a factor of h(100) + 1 , the entire h(100) + 1 , should be divisible
Since all numbers from 2 to 50 is a factor of h(100) , then none of them can be a factor of h(100) + 1.
Thus answer is E , greater than 40
pls help.......
The number of triangles whose vertices are at the vertices of an octagon but none of whose sides happen to come from the sides of the octagon is
a.24
b.52
c.48
d.16
pls help.......
The number of triangles whose vertices are at the vertices of an octagon but none of whose sides happen to come from the sides of the octagon is
a.24
b.52
c.48
d.16
pick ne vertex, then we r left with 7 vertices. out of which we have to pick 2 non adjacent vertices. there are 6 possiblities. So total 8*6 = 48.
But each triod will be counted 3 times. So answer sud be 48/3 =16.
pls help me with this combinations problem....
A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 10 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?
A. 42
B. 70
C. 140
D. 165
E. 315
A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 10 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?
A. 42
B. 70
C. 140
D. 165
E. 315
pls help me with this combinations problem....
A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 10 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?
A. 42
B. 70
C. 140
D. 165
E. 315
i think its 7C1*10C2=315
pls help me with this combinations problem....
A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 10 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?
A. 42
B. 70
C. 140
D. 165
E. 315
Guess its 315..
One candidate among 7 can be selected for the post of math dept in 7 ways
2 candidates among 10 can be selected for comp sci dept in 2C10 ways which is 45
So the total number of ways of selecting the 3 candidates is 7x45 = 315
Thank u for quick reply..It is 315..
ashishjha100 Saysi think its 7C1*10C2=315
Hey Guys,
attached are a couple of questions from gmatprep.. somehow im not able to get the solution for both of them .. Please guide me
Hi.. Can someone plz help me answer these questions?!.. Thanks a ton!
1) On Saturday morning, Malachi will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation, the probability of rain on each day is 0.2, what is the probability that Malachi will return home at the end of the day on the following Monday?
(A) 0.008 (B) 0.128 (C) 0.488 (D) 0.512 (E) 0.640
----------------------------------------------------------------------
(2) A photographer will arrange 6 people of 6 different heights for a photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him/her. How many such arrangements of the 6 people are possible?
(A) 5 (B) 6 (C) 9 (D) 24 (E) 36
-----------------------------------------------------------------------
1) On Saturday morning, Malachi will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation, the probability of rain on each day is 0.2, what is the probability that Malachi will return home at the end of the day on the following Monday?
(A) 0.008 (B) 0.128 (C) 0.488 (D) 0.512 (E) 0.640
----------------------------------------------------------------------
(2) A photographer will arrange 6 people of 6 different heights for a photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him/her. How many such arrangements of the 6 people are possible?
(A) 5 (B) 6 (C) 9 (D) 24 (E) 36
-----------------------------------------------------------------------
My take:
1st Question:
1st day - Probability of not returningback - 0.8
2nd day - Probability of not returningback - 0.8
3rd day - Probability of returningback - 0.2
So probablity that she wouldreturn back by EOD monday - 08 * 0.8 * 0.2 = 0.128
2nd Question:
This is interesting. I could see that the with the given constraints there can be only one way of arranging. BUt thats not the answer. So I am also looking forward for an answer.
My take:
1st Question:
1st day - Probability of not returningback - 0.8
2nd day - Probability of not returningback - 0.8
3rd day - Probability of returningback - 0.2
So probablity that she wouldreturn back by EOD monday - 08 * 0.8 * 0.2 = 0.128
2nd Question:
This is interesting. I could see that the with the given constraints there can be only one way of arranging. BUt thats not the answer. So I am also looking forward for an answer.
Hi.. the first question I now realise is fairly simple! For some reason, I thought "following monday" meant the following week and not the monday that comes immediately after saturday!
Anyway.. here are the answers:
(1) B and (2) A..
I still don't understand how to solve Q(2).
Hi.. Can someone plz help me answer these questions?!.. Thanks a ton!
1) On Saturday morning, Malachi will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation, the probability of rain on each day is 0.2, what is the probability that Malachi will return home at the end of the day on the following Monday?
(A) 0.008 (B) 0.128 (C) 0.488 (D) 0.512 (E) 0.640
----------------------------------------------------------------------
(2) A photographer will arrange 6 people of 6 different heights for a photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him/her. How many such arrangements of the 6 people are possible?
(A) 5 (B) 6 (C) 9 (D) 24 (E) 36
-----------------------------------------------------------------------
Hope 1st Q is solved...........
For 2nd Q is the ans A?
My reasoning..........
A>B>C>D>E>F
The positions of A & F are fixed.....so the remaining positions are
A 1 2
3 4 F
So B can take only positions 1&3
When B takes 1, C can have 3&4 and D can have 3,4&5 and E only 3&5.
When B takes 3, Ccan have only 1 D&E; can have 3&5.
Correct me if i'm wrong........
Hey Guys,
attached are a couple of questions from gmatprep.. somehow im not able to get the solution for both of them .. Please guide me
Simple hai yar :
+ (-3) (-9) 0
---|------------
4 | 1 -5 4
10 | 7 +1 10
5 2 -4 +5
so answer is 5, 3rd option.
Simple hai yar :
+ (-3) (-9) 0
---|------------
4 | 1 -5 4
10 | 7 +1 10
5 2 -4 +5
so answer is 5, 3rd option.
Thnks Jha.. hw abt the second... one any ideas?
Here are a couple one from the same set ... since all these questions are appearing right at the start, I assume tht these should be relatively simpler .. but i haven't seen such kind of questions previously and not sure about the approach to follow .... experts please guide me .. may be it will benefit few others