Here are a couple one from the same set ... since all these questions are appearing right at the start, I assume tht these should be relatively simpler .. but i haven't seen such kind of questions previously and not sure about the approach to follow .... experts please guide me .. may be it will benefit few others
For ur first question.......reasoning is
h(100)=2*3*........*100 =2^50(1*2*......*50) so prime no:s from 1 to 50 are factors of h(100) therefore for p to be factor of h(100)+1 it should be greater than 50
ans is E.
Second question my reasoning is........
let no:of 7's in 350 be x & 77's be (n-x)
=> 7x+77(n-x)=350 =>x=(11n - 50)/10 or x=11n/10 - 5
since x can only be a whole number we can check options which is completely divisible by 10 and only option is C
Hope this will clear ur doubt........criticisms are welcome........
Step 1: Calculate area of triangle ABE: AB = 1 unit, BE/ AB = tan(60 degrees) ==> BE = 1*tan(60 degrees) = sq.root(3) ==> Area(triangle ABE) = (1/2)*(1)*(sq.root(3)) = 1/
Step 1: Calculate area of triangle ABE: AB = 1 unit, BE/ AB = tan(60 degrees) ==> BE = 1*tan(60 degrees) = sq.root(3) ==> Area(triangle ABE) = (1/2)*(1)*(sq.root(3)) = 1/
pls help me in solving this prob Q16: The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers? A. 1,104 B. 972 C. 672 D. 294 E.192
pls help me in solving this prob Q16: The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers? A. 1,104 B. 972 C. 672 D. 294 E.192
let three numbers are S,M,L S+M+L=40(given) L=3M (given)and
S=L-23(given)>S=3M-23 3M-23+M+3M=40 =>7M=63 M=9 =>L=27 and S=4 hence S*M*L=972
Hi... Could someone help me in solving these problems. I have posted answers along with these. But haven't got a clue on how to arrive at these answers..
1) For every positive integer n, the function h(n) is defined to be the product of all event integers from 2 to n, inclusive. If p is the smallest prime factor of h(100)+1, then p is (a) between 2 and 10 (b) between 10 and 20 (c) between 20 and 30 (d) between 30 and 40 (e) greater than 40 Ans: e
2) On a certain sight-seeing tour, the ratio of the number of women to the number of children was 5 to 2. What was the number of men on the sight-seeing tour? (1) On the sight-seeing tour, the ratio of the number of children to the number of men was 5 to 11 (2) The number of women on the sight-seeing tour was less than 30. Ans (c)
3) If n is a multiple of 5 and n=p^2q, where p and q are prime numbers, which of the following must be a multiple of 25? (a) p^2 (b) q^2 (c) pq (d) p^2q^2 (e) p^3q Ans (d)
4) Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussel sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussel sprouts. How many of teh students like brussels sprouts but dislike lima beans? (1) 120 students eat in the cafeteria (2) 40 of the students like lima beans Ans (D)
5) If each of the following fractions were written as a repeating decimal, which would have the longest sequence of different digits? (a) 2/11 (b) 1/3 (c) 41/99 (d) 2/3 (e) 23/37 Ans : e
Will go from bottom to top... 5th Question Simply using division 2/11=0.222 (repeating decimal is 1 digit) 1/3=0.333 (repeating decimal is 1 digit) 41/99 = 0.414141 (repeating decimal is 2 digits) 2/3=0.6666 (repeating decimal is 1 digit) 23/37 =0.621621(repeating decimal is 3 digits)
so the number with longest sequence is option e
4th question ---------------- 2/3 dislike lima beans .... From (1)..of total 120 ..its 80 students (2/3 * 120) out of 80 ...3/5 dislike brussel sprouts...so its 48 students .. so students like brussels sprouts but dislike lima beans 80-48 = 32
From (2) ...40 students like lima beans If 2/3 dislike lima beans of all students...1/3 like lima beans so (1/3 * total students) = 40 ...so total students =120 and the from above we can achieve students like brussels sprouts but dislike lima beans....