GMAT Problem Solving Discussions

Here are some more questions from GMATPREP .... can someone help please
(Check the attachments please)

Thanks !

2) The chair problemm.
b) Only B is required.
Analysis: First chair = $10, rest $1 / chair
usign (1) total cost > $30 = (10 + 20) min chirs can be 21 (10 + 20*1). So we cant decided on no of chairs.
using (2) Average = 1.36.
Let N be the no of chairs. therefore:
/N = 1.36
9 + N = 1.36N
9 = 0.36N
9/0.36 = N
N= 25.
Thus N > 24.
first step... 4^11 = 2^22
second step... 2^22 = 2*2^21
third step... club 5 and 2 together since now they hav same powers...
that gives...10^21
so X = 21



the mistake u made is....u evaluated division before exponent...
PEMDAS rule says...exponent before division...

so we proceed as...
P = parantheses...(4-1) = 3
now E = exponents... 2^(3)^2= 2^9
now D = division...(2^9)divided by 2 will give 2^8
answer 8

Cheers!!


Is the division is in the exponent, then ofcourse, you will to the division first, correct?
If you assume the division to be in the exponent and then it matches the answer 2^(9/2) :s

Cheers
Satish
Is the division is in the exponent, then ofcourse, you will to the division first, correct?
If you assume the division to be in the exponent and then it matches the answer 2^(9/2) :s

Cheers
Satish

Infact i too asumes it your way satk :)
I too arrived at the answer 2^(9/2).
Infact i too asumes it your way satk :)
I too arrived at the answer 2^(9/2).


Guyz I dun totally get wat u want to say....but I think the confusion here is what if the division has to be done in the exponent part...rite??

See if the guy who set the question wants you to do the division first in the exponent...then he will put that in brackets...

e.g... 2^4/2 = (2*2*2*2)/2 = 8
but 2^(4/2) = 2^2 = 4

to decide whether /2 is to be operated first u don hav to assume...jus go by PEMDAS....or BODMAS....anything...same thing here...if no brackets...simply follow it....but if brackets then only the order can change...but infact its not violating the rule...cuz the rule says u hav to do parantheses first....

also viniculum comes first...that is the bar on top of the expression...

in case where multiplication and division are on the same level...u do from left to right...multiplication and division come together...

3/3*3 = 1 not 1/3 if u say division first and multiplication later u will get 3.
if u say multiplication first, division later....u get 1/3

so u may get confused. cuz pemdas says m first d later.
but our old school bodmas says opposite...

so the thing actually is ... M and D are on same level...
if u hav to do them from left to right.

thats my bit...i hope that helps in further questions too....

and the answer for that one is greater than 4, in fact its greater than 8.

cheers!!
What is the reminder when 9^1 + 9^2 + 9^3 + ...... + 9^9 is divided by 6?

(1) 0
(2) 3
(3) 4
(4) 2
(5) None of these

Option 2-->3??

What is the reminder when 9^1 + 9^2 + 9^3 + ...... + 9^9 is divided by 6?
(1) 0
(2) 3
(3) 4
(4) 2
(5) None of these


Ok, the answer to this must be (5)None of these. Here is what I did:

Numerator = 9^1 + 9^2 + 9^3 + ...... + 9^9 = 9 (1+ 9^1 + 9^2 + 9^3 + ...... + 9^8 )
= 3x3 (1+ 9^1 + 9^2 + 9^3 + ...... + 9^8]
Denominator = 6 = 2x3
Cancel 3 from both num. and den...so you are left with 2 in the denominator. If you divide any integer by 2, the remainder will either be always zero or 1. Hence, options 2,3 and 4 are ruled out.

Remainder will be zero if the numerator is even number.

Lets find out-
Numerator after cancelling 3 = 3 (1+ 9^1 + 9^2 + 9^3 + ...... + 9^8]
9 raised to any integer will always be odd.
Hence, the expression inside the bracket evaluates to (1 + even number) = odd number.

Inside the bracket, I wrote even number because when 8 odd numbers are added, it will give even number.

Numerator = 3 x (some odd number) = odd number. Hence, if you divide this number by 2, you will get a remainder of 1. Hence, none of the options given.

Hope this makes sense. If neone has any other better solution for dis, pls post!

Cheers!
Satish
Here are some more questions from GMATPREP .... can someone help please
(Check the attachments please)

Thanks !

Regarding the straight line problem, the answer must be both A and B are required to answer the question. The one that is already marked in the attachment.
If neone finds it is wrong, please post correct answer with analysis.
Cheers!
Satish

ans: rem=3

approach -
rem when 9 div 6 = 3
rem when 9^2 div 6 = rem when 3^3 div by 6 =3
.... till 9^9..
therefore rem=rem when 3*9 div 6 =3

ans: rem=3

approach -
rem when 9 div 6 = 3
rem when 9^2 div 6 = rem when 3^3 div by 6 =3
.... till 9^9..
therefore rem=rem when 3*9 div 6 =3

TanBhai, it's E)None of these. Please follow mailsatk's post above:
http://www.pagalguy.com/654153-post126.html

Please solve this!

Before the Civil War, Harriet Tubman, herself an escaped slave, returned again and again to Maryland to guide other slaves along the Underground Railroad to freedom.

(A) herself an escaped slave, returned again and again to Maryland to guide
(B) being an escaped slave herself, returned again and again to Maryland so as to guide
(C) an escaped slave herself, returned again and again to Maryland for guiding
(D) herself as an escaped slave, returned again and again to Maryland so as to be the guide of
(E) who had been herself as an escaped slave, returned again and again to Maryland for the guiding of

B??
C,D and E are all incorrect

c You guide someoneYou are guided by someone therefore "to guide"
D is too verbose
E is incorrect. You act "as something" but you "are something"
A

B??
C,D and E are all incorrect

c You guide someoneYou are guided by someone therefore "to guide"
D is too verbose
E is incorrect. You act "as something" but you "are something"
A

I too guessed (B) but the answer is (A). Dont know why. I want the analysis for this ??:
Please solve this!

Before the Civil War, Harriet Tubman, herself an escaped slave, returned again and again to Maryland to guide other slaves along the Underground Railroad to freedom.

(A) herself an escaped slave, returned again and again to Maryland to guide
(B) being an escaped slave herself, returned again and again to Maryland so as to guide
(C) an escaped slave herself, returned again and again to Maryland for guiding
(D) herself as an escaped slave, returned again and again to Maryland so as to be the guide of
(E) who had been herself as an escaped slave, returned again and again to Maryland for the guiding of


I think answer is C. Analysis mat poocho bhai...I am not good at that :oops:
nairpraveenk Says
I too guessed (B) but the answer is (A). Dont know why. I want the analysis for this ??:


Damn! These SCs really suck!! I had thot it might be A initially.... 😞
nairpraveenk Says
I too guessed (B) but the answer is (A). Dont know why. I want the analysis for this ??:

I knew B wld be wrong because "so as to" is wrong in 99% cases... πŸ˜ƒ
mailsatk Says
Damn! These SCs really suck!! I had thot it might be A initially.... :(

:D satk, am selcting the tough ones and posting them here. Infact these SC, even I got them worng. :)

So cheer up buddy πŸ˜ƒ
mailsatk Says
I knew B wld be wrong because "so as to" is wrong in 99% cases... :)

Thanks, this is usefull πŸ˜ƒ

While posting dubious problems...
(not exactly dubious but the problems that more than two persons got wrong answer)
please provide the reference source also.. (like 1000 SC #155)

sorry i initially made a promise that i d try post on this thread.. but guess i wouldnt :(

keep it up Praveen good work there.

C would be wrong since like I said earlier, you guide somebody or are guided by somebody. "For guiding" is wrong.

Between A and B, A is less verbose. "B" is a personal preference. However I dont think the GMAT cares very much for my personal preference