two triplets (2,2,9) and (1,6,6) give 13 as sum. So, if thirteen is the sum then we cannot say that which of the triplets is there.
For every other sum, we just have one corresponding triplet.
@asheky the sum is 13.
@sachin_nitrkl if you know that the sum is 11, then the numbers can be uniquely found. It shud be 13 i think.@asheky what is the answer???
yeah i guess u r right .. misunderstood the question
What is the number of nines used in numbeing a 453 page book?
how many four-digit numbers are divisible by 5 but not by 25
@ @
Not sure but the answer is given as 9999 in Arun sharma. I guess that is wrong. Can you please explain how have you got that (1440)?
@bpolagani :
The 4-digit numbers will range from 1000 till 9999
Now the numbers in the series from 1000 ,1005,1010....to 9995 will be divided by 5
Total numbers=1800
Numbers divided by 25 will be 1000,1025,....9075
Total numbers=360
Numbers which are divided by 5 but not by 25=1800-360=1440
Find the highest power of 2 in 1!+2!+3!...600!
@bpolagani said:Find the highest power of 2 in 1!+2!+3!...600!
It will be 0.
Because the sum is an odd integer :)
@bpolagani said:
What is the number of nines used in numbeing a 453 page book?
85 ?
What will be the sum of all two digit positive integers which exceed the product of their digits by 12 .......?
@Neel453 said:What will be the sum of all two digit positive integers which exceed the product of their digits by 12 .......?
i think only 28 will satisfy the given condition .
@Neel453 said:What will be the sum of all two digit positive integers which exceed the product of their digits by 12 .......?
28 and 39 numbers.. sum = 67
how to find remainder of 32 to the power 32 when divide by 3
@Neel453 said:how to find remainder of 32 to the power 32 when divide by 3
rem(32^32/3) = rem(-1^32/3) = 1