@Pulkit1990 that's the thing, I neither have the answer nor the solution..I hope ur answer is right...it'd help if u posted the solution...
@mayurdhingra thanks mayur but it'd really help if you could give me the complete solution.
@yasaswimr i just applied first sum of a finite GP formula and then applied euler theorem for finding the remainder....hope it will work for you...
@yasaswimr said:Throw some light on this plzQ.) What is the remainder when 1+7+7^2+7^3+....+7^2009 is divided by 9?
[1+7+4]%9=3
so 9 terms will provide with the remainder 0
there are 2010 terms
2010 is of the form 9k+3
and we know that 3 terms is giving a remainder of 3 so
3 is the answer
so 9 terms will provide with the remainder 0
there are 2010 terms
2010 is of the form 9k+3
and we know that 3 terms is giving a remainder of 3 so
3 is the answer
@yasaswimr there are 2010 terms in total which is a multiple of 3.
First three terms give a total of 1+7+4 = 12 as remainder i.e. 3 as remainder.
Similary next 3, also give 3 as remainder.\
Total remainder = 3+3+.... (670 times) = 2010/9 = 3. Hence the answer is 3.
@mayurdhingra & @REVEALED thanks a lot guys...really appreciate it.
@Pulkit1990 u r on the right path...u just missed the last step..thanx a lot
Please help me with this -
Next number of this series?
1,4,108,294,?
1,4,108,294,?
Thank you
Need help here:
Q) When the smallest three-digit number which when divided by 7, 8 and 11 leaves respective remainders of 4, 3 and 7, is divided by 9, the remainder is
a) 5
b) None of these
c) 8
d) 7
pls elaborate the process involved...
thanks in advance !
Q) When the smallest three-digit number which when divided by 7, 8 and 11 leaves respective remainders of 4, 3 and 7, is divided by 9, the remainder is
a) 5
b) None of these
c) 8
d) 7
pls elaborate the process involved...
thanks in advance !
@Sandeeppappu said:Need help here:Q) When the smallest three-digit number which when divided by 7, 8 and 11 leaves respective remainders of 4, 3 and 7, is divided by 9, the remainder isa) 5 b) None of these c) 8 d) 7pls elaborate the process involved...thanks in advance !
None of This.....remainder is 3
@Sandeeppappu said:Need help here:Q) When the smallest three-digit number which when divided by 7, 8 and 11 leaves respective remainders of 4, 3 and 7, is divided by 9, the remainder isa) 5 b) None of these c) 8 d) 7pls elaborate the process involved...thanks in advance !
7a+4=8b+3
56c+11=11d+7
616n+403
403 mod 9=7
determine the number of zeros at the end of (2^123-2^122-2^121)X(3^234-3^233-3^232)
ans options
A)0
b)1
c)121
D)none of these
m confused as i feel its option A
but the ans is given as B
plzzz help
ans options
A)0
b)1
c)121
D)none of these
m confused as i feel its option A
but the ans is given as B
plzzz help
koi plz bata do Number System ki theory k liye kya prefer kiya jaye . I want to strong my Number System . thanks in advance .......
@Neel453 number system arun sharma ki quant book mein kaafi sahi samjhaya hai. I would strongly recommend that.
Hi Guys i have a doubt in Number system, Kindly give your inputs :
(Non MCQ type question- CL package)
The product of three positive integers is 36. if one knows the sum of 3 nos., but is unable to uniquely identify the nos., what is the sum of three nos. ?
to uniquely identify the numbers , they have to be distinct.
so if u look for triplets which give such a product
we find only 1 triplet which is (2,3,6)
whose sum is 11