Number System - Questions & Discussions

MBA CAT 2022
1633
Find the number of non - negative integral solutions to the system of equations x+y+z+u+t=20 and x+y+z=5.
(a)228 (b)336 (c)448 (d)528


actually i have some problem in this type of questions...so can u guys plz solve dis?

It is Option (b) 336.

Applied the same approach as stated in the solution send by me.
1634
It is Option (b) 336.

Applied the same approach as stated in the solution send by me.


one thing i could not understand is the approach i mean why we took 10+2-1
1635
jhinki Says
one thing i could not understand is the approach i mean why we took 10+2-1

You could now remember this as a trick for solving such type of questions.
1636
rahicecream Says
brother in these types of questions you dont need to add...you have to take common...suppose there are 10 5's and 12 2's....so number of zeroes will be 10...


Ya got it. A bit of conceptual prob.:biggrin:
1637

in such problem its always no of 5 which is going to limit the no of 0 there will be always enough no of 2's to give the poduct 10 - Just to add if the same sum is asked on base 12 its no of 6 and so

1638

what is the remainder obtained when 43^101+23^101 is divided by 66?

1639
krishnaghosh Says
what is the remainder obtained when 43^101+23^101 is divided by 66?


=1

rule= a^n+b^n is divisible by a + b if n is odd
1640
=1

rule= a^n+b^n is divisible by a + b if n is odd


Then it shud be zero na??
1641
on the edge Says
Then it shud be zero na??

yes it is indeed zero.
1642
aman15490 Says
yes it is indeed zero.

tats right
1643

Hay guys, can anyone pl help me getting the Biju series for quant? Where can i get it?

1644

Can someone help me :
wat is the units place of 7^7^7 ?

1645
Can someone help me :
wat is the units place of 7^7^7 ?


first fid the remainder of 7^7 divided by 4...

7^7/4=>3^7/4
=>3...
so 7^7 is of the form 4k+3
=>7^(4k+3)
=>7^4k x 7^3
=>1x3
=>3
1646

Can someone help me on this one:

If n is an odd multiple of 3, then in how many ways can 2^n be expressed as a product of 3 factors??

1647
Can someone help me on this one:

If n is an odd multiple of 3, then in how many ways can 2^n be expressed as a product of 3 factors??


it should be nC3 ways

suppose we have n=9 which is an odd multiple of 3 then it can be expressed as 9C3 ways i.e. 84 ways
1648

No, that has not been given as the correct answer

The answer is given as (n+3)^2/12

1649

the ans is 16

1650
find the remainder when (38^16!)^1777 is divided by 17

a. 1
b. 16
c. 8
d. 13


the ans is 16
1651

What is the remainder when (2^232) is divided by 43 ?

1652

5920,7976,10803 when divided by a three digit number gives the same remainder .
Find the three digit number.