If F(x,y) is a remainder function signifying x mod y
f(8^643, 132)/(c-1) = f(52^60,31).Then find the value of f(((2^c+3^c+5^c+7^c+....+43^c+47^c)+2^5c)),2^3*3^2*5^1)
A)17 B)0 C)10 D)58 E)57
Anyone provide correct solution for this. Koi jugaad nai lag rha
@padmanabhan1989 bhai tere option bahut loose hain itne loose option ate ni hai but phir bhi check kar simply pata chal jayega ki yeh jo root ke andar wali term hai 9 se badi ho sakti hai thodi hi but 36 tak no poosible value and 1 se definately badi hogi
The exterior angles of a polygon have distinct and integral measures in degrees. If its least exterior angle is 17째, find the maximum number of sides it can have.
@SufyS
'X' is the time taken by A,B and C to complete the race.
Speed of A = (1000/X)
Speed of B = (940/X)
Speed of C = (910/X)
'Y' is the headstart B can give to C
As time taken is same
Time Taken by B = (1000)(X)/940
Time Taken by C = (1000-Y)(X)/910
Equating both, Y = 1000-( (1000) (910) / (940) )
Y = 31.9
'X' is the time taken by A,B and C to complete the race.
Speed of A = (1000/X)
Speed of B = (940/X)
Speed of C = (910/X)
'Y' is the headstart B can give to C
As time taken is same
Time Taken by B = (1000)(X)/940
Time Taken by C = (1000-Y)(X)/910
Equating both, Y = 1000-( (1000) (910) / (940) )
Y = 31.9
@catter2011 said:The exterior angles of a polygon have distinct and integral measures in degrees. If its least exterior angle is 17째, find the maximum number of sides it can have.
Options?
21??
21??
There are nine two-digit numbers. When they are arranged in ascending order, each number, excluding the least, is 10 more than the preceeding number. Find the average of the tens digits of the numbers. (with approach pls.)
@catter2011 said:The exterior angles of a polygon have distinct and integral measures in degrees. If its least exterior angle is 17째, find the maximum number of sides it can have.
n/2(34+n-1)=>33n+n^2-720=>n^2+33n-720=>(n-15)(n+48)
15 sides
15 sides
@sauravd2001 said:@padmanabhan1989 bhai tere option bahut loose hain itne loose option ate ni hai but phir bhi check kar simply pata chal jayega ki yeh jo root ke andar wali term hai 9 se badi ho sakti hai thodi hi but 36 tak no poosible value and 1 se definately badi hogi
Thanks buddy. But plese do reply in English. Hindi maalum naye :)
@krum said:n/2(17+n-1)=>16n+n^2-720=>n^2+16n-720=>(n-20)(n+36)20 sides
calc mistake.. n/2(34+n-1).. solve it u ll get 15
@catter2011 said:There are nine two-digit numbers. When they are arranged in ascending order, each number, excluding the least, is 10 more than the preceeding number. Find the average of the tens digits of the numbers. (with approach pls.)
45/9=5
@Torque024 said:If F(x,y) is a remainder function signifying x mod yf(8^643, 132)/(c-1) = f(52^60,31).Then find the value of f(((2^c+3^c+5^c+7^c+....+43^c+47^c)+2^5c)),2^3*3^2*5^1)A)17 B)0 C)10 D)58 E)57Anyone provide correct solution for this. Koi jugaad nai lag rha
do u have explanation for this one buddy? traditional methods don't seem to work here, there is a jugad to confirm the answer as 0 but its too shallow
Anand and Balu have some amounts with them. If Anand gives र10 to Balu, the difference in the amounts with them would be र20. If Anand gives र5 to Balu, the difference in the amounts with them would be र10. Find the difference (in र) in the amounts with them.
@krum said:do u have explanation for this one buddy? traditional methods don't seem to work here, there is a jugad to confirm the answer as 0 but its too shallow
Nai bus solution hai ki 0 hoga, jugaad bata do.
@catter2011 said:Anand and Balu have some amounts with them. If Anand gives र10 to Balu, the difference in the amounts with them would be र20. If Anand gives र5 to Balu, the difference in the amounts with them would be र10. Find the difference (in र) in the amounts with them.
0
@catter2011 said:Anand and Balu have some amounts with them. If Anand gives र10 to Balu, the difference in the amounts with them would be र20. If Anand gives र5 to Balu, the difference in the amounts with them would be र10. Find the difference (in र) in the amounts with them.
Both will have same amt of money so difference=0??
@Torque024 said:range of |x-5|-|x-3|These questions are solved like this or is there any other method other than values substitution?x>5(x-5)-(x-3)=-2x(-x+5)-(-x+3)=23(-x+5)-(x-3)=-2x-8Am I doing right?
u can plot the graph and find values.. generally in such qs. after extreme value the value remain constant.. here it is 5 and 3.. so at 5 the functions gives value of -2 and at x=3(another extreme value) function gives value of 2.. b/w his function the value might change but not after.. hence range is [-2,2]