The seven-digit number 1468 x 8y is divisible by 4. Find the probability that it is also divisible by 9.
@Torque024 said:iski approach batado
u need 9 2 digit numbers with c.d 10
first digit can be anything from 10-19
say 12
=>12,22,32,...,92
average of tens = (1+2+3+4+..+9)/9=45/9=5
first digit can be anything from 10-19
say 12
=>12,22,32,...,92
average of tens = (1+2+3+4+..+9)/9=45/9=5
@krum said:e?
@Torque024 said:Bhai lagakar ye aa gaya tha x^2+y^2+z^2 =62 only possible for 1,5,6 ismai bhi to combinations ban jayenge x,y,z ke so none hi hoga kyu?
wrong.. find another value..
Answer given is sth else.. though i havent checked it..
@catter2011 said:The seven-digit number 1468 x 8y is divisible by 4. Find the probability that it is also divisible by 9.
y can be 0,4,8
=>1+4+6+8+x+8+0/4/8
=>(19+x) or (23+x) or (27+x)
19+x=>x=8
23+x=>x=4
27+x=>x=0 or 9
1/3*1/10+1/3*1/10+1/3*2/10
=>1/30+1/30+2/30
=>4/30
=>2/15
=>1+4+6+8+x+8+0/4/8
=>(19+x) or (23+x) or (27+x)
19+x=>x=8
23+x=>x=4
27+x=>x=0 or 9
1/3*1/10+1/3*1/10+1/3*2/10
=>1/30+1/30+2/30
=>4/30
=>2/15
@catter2011 said:The seven-digit number 1468 x 8y is divisible by 4. Find the probability that it is also divisible by 9.
80,84,88
x could take.. 0 to 9 i.e 10 values,
so total cases 30,
favorable cases,
x=0,9 ,5 ,1
So,4/30 ?
nobody's firing crackers ? 1 just hit my ribs :|@Torque024 said:Nai bus solution hai ki 0 hoga, jugaad bata do.
sorry man, even the jugad won't work, i was wrong, maybe something would click in my dreams :p
@catter2011 said:The seven-digit number 1468 x 8y is divisible by 4. Find the probability that it is also divisible by 9.
4/30??
@krum said:y can be 0,4,8=>1+4+6+8+x+8+0/4/8=>(19+x) or (23+x) or (27+x)19+x=>x=8 23+x=>x=427+x=>x=0 or 91/3*1/10+1/3*1/10+1/3*2/10=>1/30+1/30+2/30=>4/30=>2/15
thoda bohut.. .. final step edit karta hun
4/(10*3) = 4/30 = 2/15
4/(10*3) = 4/30 = 2/15
@catter2011 said:thoda bohut.. .. final step edit karta hun4/(10*3) = 4/30 = 2/15
??, didn't get u, is it 2/15 or not?
@krum said:??, didn't get u, is it 2/15 or not?
yeah its 2/15.. but
rather than
"1/3*1/10+1/3*1/10+1/3*2/10
=>1/30+1/30+2/30
=>4/30
=>2/15"
u can directly put 4/(10*3) = 2/15
rather than
"1/3*1/10+1/3*1/10+1/3*2/10
=>1/30+1/30+2/30
=>4/30
=>2/15"
u can directly put 4/(10*3) = 2/15
@catter2011 said:yeah its 2/15.. butrather than "1/3*1/10+1/3*1/10+1/3*2/10=>1/30+1/30+2/30=>4/30=>2/15"u can directly put 4/(10*3) = 2/15
and save 2 seconds 
A + B + C + D = D + E + F + G = G + H + I = 17 where each letter represent a number from 1 to 9.
Find out number of ordered pairs (D,G) if letter A = 4.
@bullseyes said:A + B + C + D = D + E + F + G = G + H + I = 17 where each letter represent a number from 1 to 9. Find out number of ordered pairs (D,G) if letter A = 4.
a+b+c+d+e+f+g+h+i=45
=>e+f=11
=>d+g=6
1,5
5,1
=>e+f=11
=>d+g=6
1,5
5,1
In a B-School there is a vacancy for the post of a Lecturer in Marketing Management. Four candidates have been shortlisted after written examination, followed by Group Discussion and first round of Personal Interview. A panel consisting of five experts takes the final interview of the short listed candidates. If one of the selectors has a personal grudge against a particular shortlisted candidate, and would never vote for him, find the total number of ways the votes can be cast.
OPTIONS
1) 1024
2) 256
3) 624
4) None of these
OPTIONS
1) 1024
2) 256
3) 624
4) None of these
@catter2011 said:KRUM explain in more detail
a+b+c+d+e+f+g+h+i=45
given
A + B + C + D=17
G + H + I=17
=>e+f=45-17-17=11
given
D + E + F + G=17
=>D+G=17-11=6
D,G => 1,5; 2,4; 3,3; 4,2; 5,1
but all digits are unique so 3,3 not possible, also given A=4, so 2,4; 4,2 not possible
given
A + B + C + D=17
G + H + I=17
=>e+f=45-17-17=11
given
D + E + F + G=17
=>D+G=17-11=6
D,G => 1,5; 2,4; 3,3; 4,2; 5,1
but all digits are unique so 3,3 not possible, also given A=4, so 2,4; 4,2 not possible
@sujamait said:In a B-School there is a vacancy for the post of a Lecturer in Marketing Management. Four candidates have been shortlisted after written examination, followed by Group Discussion and first round of Personal Interview. A panel consisting of five experts takes the final interview of the short listed candidates. If one of the selectors has a personal grudge against a particular shortlisted candidate, and would never vote for him, find the total number of ways the votes can be cast.OPTIONS1) 1024 2) 256 3) 624 4) None of these
NONE, 768 ?
In acute angled ˆ†ABC, CD and BE are altitudes and G is the orthocentre. AD = 6 and AC = 10. Find ratio of areas of đ?›ĽBCED and ˆ†ABC.
OPTIONS
1) 9 : 25
2) 12 : 20
3) 16 : 20
4) 16 : 25
5) Data insufficient
OPTIONS
1) 9 : 25
2) 12 : 20
3) 16 : 20
4) 16 : 25
5) Data insufficient
@krum said:a+b+c+d+e+f+g+h+i=45given A + B + C + D=17G + H + I=17=>e+f=45-17-17=11givenD + E + F + G=17=>D+G=17-11=6D,G => 1,5; 2,4; 3,3; 4,2; 5,1but all digits are unique so 3,3 not possible, also given A=4, so 2,4; 4,2 not possible
"a+b+c+d+e+f+g+h+i=45"
yeh expression kaise aya ?
yeh expression kaise aya ?
@sujamait said:In a B-School there is a vacancy for the post of a Lecturer in Marketing Management. Four candidates have been shortlisted after written examination, followed by Group Discussion and first round of Personal Interview. A panel consisting of five experts takes the final interview of the short listed candidates. If one of the selectors has a personal grudge against a particular shortlisted candidate, and would never vote for him, find the total number of ways the votes can be cast.OPTIONS1) 1024 2) 256 3) 624 4) None of these
3*4^4=768