Official Quant thread for CAT 2013

@chandrakant.k said:
since the number of ripe mangoes is a 3 digit numberthe maximum number = 200the nearest cube = 125 in each boxso total 625 the first statement doesn't hold true here.so check for 64total mangoes = 64*5 = 320 other condition not satisifedtake 27total mangoes == 27*5 = 135now had there been 10 more total = 145which can be divided as 64+81so 135 is the number of mangoes sum of digit = 9??ALL : Please post the solution while posting your answer. There will be different ways of solving a particular problem. And different people will have different approach. so it would to learn how others think of solution and it will be a good experience
I approached this way
Total mangoes have 3 digit and should be multiple of 5 such let be 5n
now n should be perfect cube ; n can be 8,27,64... as 5n should be of three digit n=27
total mangoes=27*5=135
sum of digits=9 :)
@catter2011 said:
3^n kasie ayaa ?aint it p!/ α! β! γ! = 1050, given γ+β+α = p
a,b,c se code banana hai
let code be of length 3
possible ways =3*3*3= 27=no of distinct codes
Let code be of length n
3*3*3*..n > 1050
so min value of n=7
@sujamait said:
An intelligence agency wants to develop a new code containing 1050 distinct critical words for its sleuths. It intends to use just three symbols - α, β and γ – for each letter in the code. If all the words are designed to have exactly p number of characters, what is the minimum required value of p?OPTIONS1) 6 2) 7 3) 8 4) This code is not possible
3^n>1050
so n = 7
@Torque024 said:
a,b,c se code banana hai let code be of length 3possible ways =3*3*3= 27=no of distinct codesLet code be of length n3*3*3*..n > 1050so min value of n=7
if code is of length 3

possible ways =>

abc
abc
bca
bac
cba
cab


=> 3!/1!1!1! = 6
@catter2011 said:
if code is of length 3possible ways =>abcabcbcabaccbacab=> 3!/1!1!1! = 6
We can use repetition here. 😃 so 3*3*3
@Torque024 said:
We can use repetition here. so 3*3*3
Missed tht point.. thnkz.. may be it aint necessary a,b,c should present..

min and max value of 4^(cosx)+4^(sinx)??

@Torque024

but 3^n can never be exactly 1050, hence code impossible
@astute99 options?

@audiq7 said:
@astute99 options?
dn hv options, u tell ur approach??
@catter2011 said:
@Torque024but 3^n can never be exactly 1050, hence code impossible
We need 1057, take any group of 1057 from 3^7.
@catter2011 said:
Anand and Balu have some amounts with them. If Anand gives र10 to Balu, the difference in the amounts with them would be र20. If Anand gives र5 to Balu, the difference in the amounts with them would be र10. Find the difference (in र) in the amounts with them.
x- 10 - y - 10 = 20
=> x-y = 40
x-5-y-5 = 10
=> x-y = 20

I am unable to find the unique value of x and y :(
@astute99 said:
dn hv options, u tell ur approach??
it should be minimum when both are negative and equal ie sinx and cosx
maximum when both sinx and conx are positive and equal..
@surajmenonv said:
is it 7? my heart says not possible though
bhai can you explain what is question is asking for, i am not even able to comprehend :(
@astute99 min wud be 5. max wud be around 5.30 putting x=45
@audiq7 said:
@astute99 min wud be 5. max wud be around 5.30 putting x=45
approach batao bhai ekdum basic se???????
A doctor has decided to prescribe two new drugs D1 and D2 to 200 heart patients such that 50 get drug D1, 50 get drug D2 and 100 get both. The 200 patients are chosen so that each had 80% chance of having a heart attack if given neither of the drugs. Drug D1 reduces the probability of a heart attack by 35%, while drug D2 reduces the probability by 20%. The two drugs when taken together, work independently. If a patient, selected randomly from the chosen 200 patients, has a heart attack then the probability that the selected patient was given both the drugs is:

A. 0.42
B. 0.49
C. 0.56
D. 0.40
@mohnish_khiani .42

@rachit_28 said:
x- 10 - y - 10 = 20 => x-y = 40x-5-y-5 = 10=> x-y = 20I am unable to find the unique value of x and y
|x-y-20|=20;|x-y-10|=10
Only possible if x-y=0;
@audiq7 said:
@astute99 min wud be 5. max wud be around 5.30 putting x=45
@astute99 said:
approach batao bhai ekdum basic se???????

nopes.. it is--
Max: 2^1+_/2
Min: 2^1-_/2