@rachit_28 said:x- 10 - y - 10 = 20 => x-y = 40x-5-y-5 = 10=> x-y = 20I am unable to find the unique value of x and y
bhai dono k paas same amount hain...hence difference should b 0
correct me if I am wrong
@astute99 said:bhai approach batao kaise kiya???????
max
4 ^1/root2 + 4^1/root2
2.4^1/root2
2.2^root2
2^1+root2
min 4^ -1/root2 + 4 -1/root2
2/4^1/root2
2/2^2/root
2/2^root2
2^1-root2
ps::: for max...both sinx/cosx =1/root2
for min both sinx/cosx =-1/root2
@astute99 said:bhai approach batao kaise kiya???????
@audiq7 said:@Anivesh90 kaise kiya? isiliye options chahiye, samaz aata hai kuchh to galat kiya hai!!
the max value will be at x=pi/4 (when both sin and cos are positive)
min value will be at x=5pi/4 (when both are negative)
@milestogo3 said:max 4 ^1/root2 + 4^1/root22.4^1/root22.2^root22^1+root2min 4^ -1/root2 + 4 -1/root22/4^1/root22/2^2/root2/2^root22^1-root2ps::: for max...both sinx/cosx =1/root2for min both sinx/cosx =-1/root2
bhai underlined part kaise kiya samajh ni aaya????
@sauravd2001 said:@Anivesh90 yeh question kitne dino se chal raha hai ?
pta ni.. kuch din pehle bhi tha..ab fir kisi ne dal diya..
@Anivesh90 said:the max value will be at x=pi/4 (when both sin and cos are positive)min value will be at x=5pi/4 (when both are negative)
samajh ni aayi ye dono lines ???
@astute99 said:bhai underlined part kaise kiya samajh ni aaya????
i told you in previous posts...
for max sinx = cos x = positive...which is in first quadrant pi/4
for min both should be equal and negative ...both are negative in third quadrant. pi+pi/4 =5pi/4
i was avoiding as i dont hvae copy right now...so gave u an inkling about when it would be max and when min..
@mohnish_khiani are simple theorem hai kuch din pahle bhi aya tha yeh jab kisi ne galat post kiya tha .8*.65*.8*100/(.8*.65*.8*100+.65*.8*50+.8*.8*50)=.4176 kuch ayge aphir age yeh .42 ho jayega
@mohnish_khiani said:A doctor has decided to prescribe two new drugs D1 and D2 to 200 heart patients such that 50 get drug D1, 50 get drug D2 and 100 get both. The 200 patients are chosen so that each had 80% chance of having a heart attack if given neither of the drugs. Drug D1 reduces the probability of a heart attack by 35%, while drug D2 reduces the probability by 20%. The two drugs when taken together, work independently. If a patient, selected randomly from the chosen 200 patients, has a heart attack then the probability that the selected patient was given both the drugs is:A. 0.42B. 0.49C. 0.56D. 0.40
Probability of the person prescribed with D1 to hv heart attack=>.8*(1-.35)*50=26
Probability of the person prescribed with D2 to hv heart attack=>.8*(1-.2)*50=32
Probability of the person prescribed with both D1 and D2 to hv heart attack=>.8*.65*.8*100=41.6
probability that the selected patient was given both the drugs is 41.6/(26+32+41.6) =.42approx
@astute99 bhai ratle ki jab sin cos dono term diye hue ho same base ke stah toh max aur min term hamesha pie /4 or 5pie/4 pe hi ayegi respectively nai toh difrerntiate karke dekh le