Three Professors Dr. Gupta, Dr Sharma and Dr.Singh are evaluating answer scripts of a subject.Dr. Gupta is 40% more efficient than Dr. Sharma,who is 20% more efficient than Dr. Singh. Dr. Guptatakes 10 days less than Dr. Sharma to completethe evaluation work. Dr. Gupta starts the evaluationwork and works for 10 days and then Dr. Sharmatakes over. Dr. Sharma evaluates for next 15 daysand then stops. In how many days, Dr. Singh cancomplete the remaining evaluation work.A. 7.2 days B. 9.5 daysC. 11.5 days D. None of thesewith approach
Assume the efficiencies of Gupta, Sharma and Singh be 1.4x, x and x/1.2 respectively.
Now equating the work,
xy = 1.4xy - 14x
y = 35
Therefore Singh will complete the work in 42 days.
Three Professors Dr. Gupta, Dr Sharma and Dr.Singh are evaluating answer scripts of a subject.Dr. Gupta is 40% more efficient than Dr. Sharma,who is 20% more efficient than Dr. Singh. Dr. Guptatakes 10 days less than Dr. Sharma to completethe evaluation work. Dr. Gupta starts the evaluationwork and works for 10 days and then Dr. Sharmatakes over. Dr. Sharma evaluates for next 15 daysand then stops. In how many days, Dr. Singh cancomplete the remaining evaluation work.A. 7.2 days B. 9.5 daysC. 11.5 days D. None of thesewith approach
Assume the efficiencies of Gupta, Sharma and Singh be 1.4x, x and x/1.2 respectively.Now equating the work, xy = 1.4xy - 14xy = 35Therefore Singh will complete the work in 42 days.Now 10/25 + 15/35 + d/42 = 1On solving d= 7.2 days.
On solving you get, 2/5 + 3/7 + d/42 =1, i.e d/42 = 6/35 i.e d=36/5 = 7.2 Calculation Mistake.
@karl especially in IIFT, maine kai saare questions ke answer none of these dekhe hai ! an alternate way to add the trick by increasing the frequency of OAs to none of these !
Three Professors Dr. Gupta, Dr Sharma and Dr.Singh are evaluating answer scripts of a subject.Dr. Gupta is 40% more efficient than Dr. Sharma,who is 20% more efficient than Dr. Singh. Dr. Guptatakes 10 days less than Dr. Sharma to completethe evaluation work. Dr. Gupta starts the evaluationwork and works for 10 days and then Dr. Sharmatakes over. Dr. Sharma evaluates for next 15 daysand then stops. In how many days, Dr. Singh cancomplete the remaining evaluation work.A. 7.2 days B. 9.5 daysC. 11.5 days D. None of thesewith approach
g=g*1.4-10 =>g=25,sh=35
si=35*1.2=42
==>required days = [1-(10/25+15/35)]*42 ==>[1-(2/5+3/7)]*42 ==>[1-29/35]*42=6/5*6=7.2
Three Professors Dr. Gupta, Dr Sharma and Dr.Singh are evaluating answer scripts of a subject.Dr. Gupta is 40% more efficient than Dr. Sharma,who is 20% more efficient than Dr. Singh. Dr. Guptatakes 10 days less than Dr. Sharma to completethe evaluation work. Dr. Gupta starts the evaluationwork and works for 10 days and then Dr. Sharmatakes over. Dr. Sharma evaluates for next 15 daysand then stops. In how many days, Dr. Singh cancomplete the remaining evaluation work.A. 7.2 days B. 9.5 daysC. 11.5 days D. None of thesewith approach
g=1.4sh=1.68si
sh=1.2si
1/sh-1/g=10 =>0.4/1.4sh=10
sh=4/140=1/35 , so sh takes 35 days , g takes 25 days,si takes 42 days
10/25 + 15/35 + K/42 =1
K=7.2days
Set A is a set of the first 400 primes that can be written in the form 3n + 1. Set B is a set of the first 600 primes that can be written in the form 6m + 1. How many elements does set (A ˆŠ B) have? OPTIONS
A box B1 has 299 identical cards. These cards are divided into three heaps and placed in boxes B1, B2 and B3 such that each box has at least one card. What is the probability that B1 has more cards than B2 and B3 put together?
Real numbers - a, b and c - form an arithmetic progression. Some permutation of a, b and c also forms a geometric progression. If a ≠ b ≠ c and c = 2396, what is the sum of all possible values of b? OPTIONS
A box B1 has 299 identical cards. These cards are divided into three heaps and placed in boxes B1, B2 and B3 such that each box has at least one card. What is the probability that B1 has more cards than B2 and B3 put together?
Real numbers - a, b and c - form an arithmetic progression. Some permutation of a, b and c also forms a geometric progression. If a ≠ b ≠ c and c = 2396, what is the sum of all possible values of b?OPTIONS1) −599 2) 1198 3) 1797 4) 3594 5) Cannot be determined
b = (a + c) /2...(1)
b is the not the geometric mean otherwise a = b = c ..
Case 1: c is the geometric mean => c^2 = a*b
Multiply (1) by a on both the sides => 2*ab = a^2 + ac
=> 2c^2 = a^2 + ac
=> c^2 - a^2 = ac - c^2
=> (c-a)*(c+a) = (a-c)*(c)
=> c + a = -c
=> a = -2c
=> b = -c/2
Case 2: a is the geometric mean => a^2 = b*c
Multiply (1) by c on both the sides => 2*bc = ac + c^2
Set A is a set of the first 400 primes that can be written in the form 3n + 1. Set B is a set of the first 600 primes that can be written in the form 6m + 1. How many elements does set (A ˆŠ B) have?OPTIONS1) 150 2) 200 3) 400 4) None of these
Set A has first 400 prime numbers of the form 3n + 1
Also, if 3n + 1 is a prime, then n must be of the form 2k = > A has first 400 prime numbers of the form 6k + 1
and B has first 600 prime numbers of the form 6m + 1
yup!A box B1 has 299 identical cards. These cards are divided into three heaps and placed in boxes B1, B2 and B3 such that each box has at least one card. What is the probability that B1 has more cards than B2 and B3 put together?
Real numbers - a, b and c - form an arithmetic progression. Some permutation of a, b and c also forms a geometric progression. If a ≠ b ≠ c and c = 2396, what is the sum of all possible values of b?OPTIONS1) −599 2) 1198 3) 1797 4) 3594 5) Cannot be determined
....OA is 7.2
...its a IIFT ques 