Official Quant thread for CAT 2013

MBA CAT 2022
3061
@Brooklyn said:
can u explain d q !! i didnt get it :/
@maddy2807 said:
samjha yaar... sab upar se gaya
First letter can be selected in 3 ways..A,B or C
Next letter can be selected in only 2 ways..for e.g if we select A, then the next letter can be A or C, but it cannot be B..since A cannot be followed by B.
Similarly, for the remaining letters, we will have only 2 options.
So the answer comes out to be 3*2*2*2*2*2*2
3062
@Torque024 said:
168/29
OA me tag kar dena. mujhe.
3063
@maddy2807 said:
OA me tag kar dena. mujhe.
http://www.qbyte.org/puzzles/p076s.html
Hope this helps
3064
@Torque024 kaise bro + @maddy2807 Bhai 4sqt(2) to vaise kafi close h correct answer k kaise kia ???
3065

Let N be the greatest multiple of 8, no two of whose digits are the same.
What is the remainder when N is divided by 1000?

3066
@grkkrg options?
3067
@grkkrg said:
Let N be the greatest multiple of 8, no two of whose digits are the same. What is the remainder when N is divided by 1000?
992?
3068
@grkkrg said:
Let N be the greatest multiple of 8, no two of whose digits are the same. What is the remainder when N is divided by 1000?
no. aisa kuchh hoga kya 9876543120 (largest no. with distinct digits divisible by 8)

remainder=120
3069
@Torque024 said:
992?
how can it be 992 when no two digits are same
3070
@grkkrg said:
Let N be the greatest multiple of 8, no two of whose digits are the same. What is the remainder when N is divided by 1000?


EDITED
120? A wild guess..1234567890*8 = 9876543120
Giving the options would help
3071
@Torque024 said:
992?
no two digits are the same
3072
@sumeet1489 said:
how can it be 992 when no two digits are same
han
3073
@grkkrg said:
Let N be the greatest multiple of 8, no two of whose digits are the same. What is the remainder when N is divided by 1000?
9876543120..so rem 120 aaj neend barabar aa rhi hai..
3074
@audiq7 said:
@grkkrg options?
a) 104
b) 120
c) 128
d) 320

(Options are not provided in the question. I made these up. :P)

3075
@sumeet1489 said:
no. aisa kuchh hoga kya 9876543120 (largest no. with distinct digits divisible by 8)remainder=120
approach ??
3076

itna andhkar chaya hua hai ki 채rtof problem solving" ..art of living dikh rha tha..

Define a "good word" as a sequence of letters that consists only of the letters A , B, and C - some of these letters may not appear in the sequence - and in which A is never immediately followed by B, B is never immediately followed by C, and C is never immediately followed by A. How many seven-letter good words are there?

A _ _ _ _ _ _ so, 2.2... so, 2^6 choices
similarly when it start with B , C ..
hence
3.2^6 I guess.

......................................

3077
@Torque024 options for triangle question ?
3078
@Brooklyn said:
approach ??

largest no. possible with all distinct digits=9876543210

but this won't be divisible by 8 as last three digits are 210

so next highest no. whose last 3 digits are divisible by 8 = 9876543120
3079
@bhargav_it said:
@Torque024 options for triangle question ?
OA is 168/29
3080
@grkkrg said:
In a regular tetrahedron the centers of the four faces are the vertices of a smaller tetrahedron. The ratio of the volume of the smaller tetrahedron to that of the larger is m/n, where m and n are relatively prime positive integers. Find m + n.
dimensions of the smaller cube will be (1/2)(2/3) times the larger one.
So, volume of the smaller one will be 1/27 times the larger one.

m + n = 28