Official Quant thread for CAT 2013

Anyone solving Time material SM1001311. p/m me there are certain ques i would love to discuss in TSD exercise no 6.

@AIM_IIM_2013 said:
Anyone solving Time material SM1001311. p/m me there are certain ques i would love to discuss in TSD exercise no 6.
share q here !!
@chillfactor said:
dimensions of the smaller cube will be (1/2)(2/3) times the larger one.So, volume of the smaller one will be 1/27 times the larger one.m + n = 28
appraoch sir !! i didnt get how to approach dis 😞
@Brooklyn Bada ques h aur photo upload nahi ho rahi .jpg format upload karna ban h kya yaha pe ???
@AIM_IIM_2013 said:
@Brooklyn Bada ques h aur photo upload nahi ho rahi .jpg format upload karna ban h kya yaha pe ???
upload on dropbox n give link here 😃
@maddy2807 said:
4rt(3) ?
Bhai approach ?
@Brooklyn said:
appraoch sir !! i didnt get how to approach dis
..You have to look at the figure of a tetrahedron or visualize.. You will see that when you join the centres..you will get a smaller tetrahedron whose sides are in ratio 1: (1/2)*(2/3) This 2/3 is because of centroid dividing the side in ratio 1:2 ..Very difficult to explain like this 😞 Sorry for that
@rachit_28 said:
Bhai approach ?
check 3084 post.
@Brooklyn said:
appraoch sir !! i didnt get how to approach dis
Just visualise the figure.
Suppose ABCD is the larger tetrahedron (obviously all the faces are equilateral triangle)
P, Q R, S, T and U are mid points of AB, BC, CA, AD, BD and CD respectively
and X, Y, Z, W are mid points of the 4 faces ABC, BCD, ABD and ACD respectively.

Now, AXQ is in straight line. Similarly AWU are in straight line.

We know that mid-points of the faces are the centroid of the triangles (means they divide the medians in 2:1 ratio)

In triangle BCD
Q and U are mid points of sides BC and CD
=> QU = (1/2)BD ...................(1)

Consider triangle AQU, AQ and AU are medians of the triangles ABC and ACD
Also, X and W lies on AQ and AU respectively and they divide these sides in 2:1 ratio
Hence, we can say that XW is parallel to QU
=> AWX and AUQ are similar triangles
=> WX = (2/3)QU ...............................(2)

From (1) and (2), we can say that
WX = (1/3)BD

Similarly other sides will be of same dimension

Ratio of volumes = (1/3)続 = 1/27

Let me know if its not clear, will try to post a diagram.
@AIM_IIM_2013 said:
Don't even try equation formation dimag ka dahi ho jayga fig bana k analysis he best approach h.
Aankho ki roshni chali jayegi isko padhne k bad :P
@chillfactor said:
Ratio of volumes = (1/3)続 = 1/27Let me know if its not clear, will try to post a diagram.
How did you do this - (1/3)続:wow: ---others would have written it as (1/3)^3
@chillfactor : sir figure coz i cant visualize , dats problem, thats y i couldnt figure how to approach it :banghead:
@AIM_IIM_2013 said:
unreadable
@AIM_IIM_2013 said:
bhai... aankhe fat gai meri...

There are 3 frnd T S R . they live on the bank of a lake in city P . T have a hover that can travel on land and water both at the speed of 30 kmph. They all decide to go city Q which is 120 km away on the other side of the lake. T and R started on the hover and S started on the boat at 6 kmph . In order to minimize the time taken for the entire journey. T drop R on the road and R start walking at 6 kmph toward the destination. By that time T take hover back on the bank where S has just reached. He pick up S and take him to the destination . they all reach destination at the same time Assume time to drop and pick up is negligible.
how long R S T take to reach city q (destination) from city p?

3 hr 5 hr 6 hr 8 hr
what is the length of the lake?
30 km 18 km 12 km 60 km
A family of 5 members with distinct walking speeds need to cross a bridge at night The bridge is so old that at any given moment it can withstand the weights of a maximum of two people walking on it... There is only a single lamp which will glow for 30 seconds before getting extinguished ... A, B, C, D, E needs 1,3,6,8,12 seconds respectively to cross the bridge on their own... Since it's dark at night at least one person (not necessary the same person) must come back and forth carrying the lamp to help others cross the bridge... When two persons walk together they would take the time equal to the one taken by the slower person to cross the bridge ... (for example when C walks with E they would take 12 seconds to cross the bridge together)... Whats the minimum time in which you can make all of them cross the bridge ?
a) exactly 30 seconds
b) 29 seconds
c) 28 seconds
d)
Not possible to make them cross within 30 seconds
@AIM_IIM_2013 said:
There are 3 frnd T S R . they live on the bank of a lake in city P . T have a hover that can travel on land and water both at the speed of 30 kmph. They all decide to go city Q which is 120 km away on the other side of the lake. T and R started on the hover and S started on the boat at 6 kmph . In order to minimize the time taken for the entire journey. T drop R on the road and R start walking at 6 kmph toward the destination. By that time T take hover back on the bank where S has just reached. He pick up S and take him to the destination . they all reach destination at the same time Assume time to drop and pick up is negligible.how long R S T take to reach city q (destination) from city p?3 hr 5 hr 6 hr 8 hr what is the length of the lake? 30 km 18 km 12 km 60 km
@Brooklyn @maddy2807 @gs4890 dekh lo ab bhai log
Hint :Draw fig and use proportionality to draw conclusion regarding the length traveled by S and R .
pheww

The min no of straight lines rqd to get 16 non-overlapping parallelograms is?
8
10
17
7

How many odd nos btw 150 and 350 are neither divisible by 9 nor by 11?
81
161
78
162