Official Quant thread for CAT 2013

@Brooklyn said:
@chillfactor : sir figure coz i cant visualize , dats problem, thats y i couldnt figure how to approach it
@sonamaries7 10
@sonamaries7 said:
How many odd nos btw 150 and 350 are neither divisible by 9 nor by 11?8116178162
is it 81 sonamaries 😉 ?
@AIM_IIM_2013 said:
@sonamaries7 10
ryt, approach plz....
@sonamaries7 said:
How many odd nos btw 150 and 350 are neither divisible by 9 nor by 11?8116178162
162
??
in a cyclic quad PQRS, the sides are PQ=p, QR=q, RS=r and PS=s,
if p*q=3*s* r, and anglePQR=120, then s=?(in terms of p,q ,r)
OPtions:
p+r-q
q+r-p
p+q-r
(p+q+r)/3

Edited
@sonamaries7 said:
How many odd nos btw 150 and 350 are neither divisible by 9 nor by 11?8116178162
odd multiples of 9 = 11
odd multiple of 11 = 9
odd multiples of 99 = 1
odd numbers which are multiples of 9 or 11 = 11 + 9 - 1 = 19

odd numbers which are neither divisible by 9 not by 11 = 100 - 19 = 81

5 parallel line E to W then 5 parallel lines N to S cutting them. This is the best approach to make 16 parallelogram.

@gautam22 Yo correct perfect !
@Brooklyn said:
162??
sirf odd...81 hai
@sonamaries7 said:
The min no of straight lines rqd to get 16 non-overlapping parallelograms is?810177
10?
skew chess board of 4*4

pls help in solving this ques in the attachment...

@AIM_IIM_2013 said:
5 parallel line E to W then 5 parallel lines N to S cutting them. This is the best approach to make 16 parallelogram.
@Torque024 said:
10? skew chess board of 4*4
can i get a fig plz...
@sonamaries7 5*5 chess board ki fig chaiye bhai tuje ? 😁
@gautam22 said:
(p^2+q^2-r^2+4*p*q/3)^1/2?
refer to the qs above...updated the options...
A no N expressed to the base 5 is 232323...a total of 100 digits. What is the rem when N^4231 is divided by 4?
0
1
2
4
@sonamaries7 said:
The min no of straight lines rqd to get 16 non-overlapping parallelograms is?810177
getting 10 sonamaries ;)
@sonamaries7 said:
in a cyclic quad PQRS, the sides are PQ=p, QR=q, RS=r and PS=s, if p*q=3*s* r, and anglePQR=120, then s=?(in terms of p,q ,r)OPtions:p+r-qq+r-pp+q-r(p+q+r)/3Edited
PQR = 120°
Cos120° = (p² + q² - PR²)/(2pq)
=> PR² = p² + q² + pq

Also, PSR = 60° (in cyclic quadrilateral, sum of opposite angles is 180°)

so, PR² = s² + r² - sr

=> p² + q² + pq = s² + r² - sr
=> (p + q)² - pq = (s + r)² - 3sr
=> (p + q)² = (s + r)², as pq = 3sr

So, s = p + q - r
@freedom_fighter said:
pls help in solving this ques in the attachment...
d
@freedom_fighter said:
pls help in solving this ques in the attachment...
Is it D) ?