by checking the symmetry. 1-9/10 = 1/10put x =1-xf(x) = 9^x/(3+9^x) f(1-x) = 9^1-x/3+9^1-xf(1-x)=9/9^x / 3.9^x+9 /9^xf(1-x) = 9/3.9^x+9 = 3/3+9^xadding f(x) + f(1-x) = 1..f(1/10)+f(9/10) = 1 so will be other four terms...f(1/2) =1/2so ans is 4+1/2 =9/2
Not sure about the cyclic order or notBt just tried putting x = 1 and x = 0 so got it . Baad me yaad aya ki kaha ki pada tha but not able to recall where.. will tag you if i find anything P.S : with this post, i am now certified pagal
i got the same question in this year cat bt there was a slight difference in thatf(1/11) + f(2/11) +.....+ f(10/11) i got the ans. as 5, 16th october morning slotP.S. i hope i am not violating NDA as this years cat window is long over
buddy not sure of this year's CAT but this was in one of the previous papers as i remember....
@sumeet1489 ,can't it be solve by AM>GM,how can it be 2?12x+14y/2>(12x*14y)~1/2
i tried using the same at first but cudn't find a way out..coz there's no constraint given on the values of x and y..or even they are integers or not....so jus went by options in this case.
Shyama and Vyom walk up an escalator (moving stairway). The escalator moves at a constant speed. Shyama takes three steps for every two of Vyom €™s steps. Shyama gets to the top of the escalator after having taken 25 steps, while Vyom (because his slower pace lets the escalator do a little more of the work) takes only 20 steps to reach the top. If the escalator were turned off, how many steps would they have to take to walk up? a) 40 b) 50 c) 60 d) 80 e) None of these
Shyama and Vyom walk up an escalator (moving stairway). The escalator moves at a constant speed. Shyama takes three steps for every two of Vyom €™s steps. Shyama gets to the top of the escalator after having taken 25 steps, while Vyom (because his slower pace lets the escalator do a little more of the work) takes only 20 steps to reach the top. If the escalator were turned off, how many steps would they have to take to walk up?a) 40b) 50c) 60d) 80e) None of these
e- escalator speed, s - no. of steps , x - shyama, vyom's speed
25/3x=(s-25)/e ---- (i) 20/2x=(s-20)/e ---- (ii)
dividing (i) by (ii) =>5/6=(s-25)/(s-20) =>5s-100=6s-150 =>s=50
Shyama and Vyom walk up an escalator (moving stairway). The escalator moves at a constant speed. Shyama takes three steps for every two of Vyom €™s steps. Shyama gets to the top of the escalator after having taken 25 steps, while Vyom (because his slower pace lets the escalator do a little more of the work) takes only 20 steps to reach the top. If the escalator were turned off, how many steps would they have to take to walk up?a) 40b) 50c) 60d) 80e) None of these
50..
let the escalator move t steps in the time shayam moves 25 steps.
in the same time vyom would have moved 50/3 steps
so vyom would move (20-50/3) =10/3steps after shyam gets down/
if vyom takes 10/3 steps
in the same time escalator would have taken t/5 steps