Official Quant thread for CAT 2013

@vijay_chandola said:
Is |x €“ 3| 2II. |x €“ 1| a) if the question can be answered using statement I alone but not using II aloneb) if the question can be answered using statement II alone but not using I alonec) if the question can be answered using either statement aloned) if the question can be answered using statements I and II together but not using eitheralonee) if the question cannot be answered even by using both statements I and II together@krum: for the second question's solution XAT mai hi possible h iska aana
d
@vijay_chandola said:
Is |x €“ 3| 2II. |x €“ 1| a) if the question can be answered using statement I alone but not using II aloneb) if the question can be answered using statement II alone but not using I alonec) if the question can be answered using either statement aloned) if the question can be answered using statements I and II together but not using eitheralonee) if the question cannot be answered even by using both statements I and II together@krum: for the second question's solution XAT mai hi possible h iska aana
|x-3|
=>1
I. x > 2 or x

II. -2

d)

edited
@vijay_chandola said:
Is |x €“ 3| 2II. |x €“ 1| a) if the question can be answered using statement I alone but not using II aloneb) if the question can be answered using statement II alone but not using I alonec) if the question can be answered using either statement aloned) if the question can be answered using statements I and II together but not using eitheralonee) if the question cannot be answered even by using both statements I and II together@krum: for the second question's solution XAT mai hi possible h iska aana
E ?
@krum said:
|x-3|=>-2 =>1 I. -2 II. -2 c)either?
: either how??? 😲
@vijay_chandola said:
Is |x €“ 3| 2II. |x €“ 1| a) if the question can be answered using statement I alone but not using II aloneb) if the question can be answered using statement II alone but not using I alonec) if the question can be answered using either statement aloned) if the question can be answered using statements I and II together but not using eitheralonee) if the question cannot be answered even by using both statements I and II together@krum: for the second question's solution XAT mai hi possible h iska aana
C?
@Brooklyn said:
d
@rkshtsurana said:
E ?
@krum said:
|x-3|=>-2 =>1 I. -2 II. -2 c)either?
OA: D
@krum :thumbsup: sorry D h :splat: sahi se dekha nahi :P
@Brooklyn : __/\__ join the show 😛 😁
@vijay_chandola said:
OA: C@krum@Brooklyn : __/\__ join the show
yea !! have been busy !! free now 😁 __/\__
@vijay_chandola mene bhi yr c likha tha chnge hi nhi hua
@vijay_chandola said:
OA: C@krum@Brooklyn : __/\__ join the show
Can you please explain how the statement |x|>2 can determine the given condition?
@vijay_chandola said:
OA: D@krum sorry D h sahi se dekha nahi @Brooklyn : __/\__ join the show
: how c yar??! you dont get a clear value of x if x>-2 and x-1 it is statisfied !!
@krum said:
Consider the increasing sequence - 1, 3, 4, 9, 10, 12, 13 €Ś and so on. The sequence consists of all those positive integers which are powers of 3 or sum of distinct powers of 3.Find the 100th term of the sequence.OPTIONS1) 978 2) 981 3) 932 4) 987 5) None of these
Is it 981 boss ???
@staaalinnn said:
Is it 981 boss ???
logic???

@soumitrabengeri said:
Can you please explain how the statement |x|>2 can determine the given condition?
Answer is D.
Book k options are different. So, posted incorrectly C :splat:


@Brooklyn said:
: how c yar??! you dont get a clear value of x if x>-2 and x-1 it is statisfied !!
Arey darao mat yar! :P
Edited the previous post. check it again
@vijay_chandola Option E becuse ques ki range 1 se 5 tak ani chayie + hone k liye baki sab m - h. aur 1 aur 2 dono k combined region se sirf |x-3|

@Brooklyn said:
logic???
bhai..I thought on these lines..it's just a base problem which can be done on base 3.
1,10,11,...... 1100100 is the 100th term.
@staaalinnn said:
bhai..I thought on these lines..it's just a base problem which can be done on base 3.1,10,11,...... 1100100 is the 100th term.
1100100 yeh kese aaya 100 term..he toh nyc approach
@staaalinnn said:
bhai..I thought on these lines..it's just a base problem which can be done on base 3.1,10,11,...... 1100100 is the 100th term.
but i thot:

each even term = multiple of 3

eg 2nd term= (2-1)*3

4th term=(4-1)*3

so on so 100th term= 99*3 koi option nhi tha, laga glat hoga. So y is this wrong??
@rkshtsurana said:
1100100 yeh kese aaya 100 term..he toh nyc approach
@Brooklyn said:
but i thot: each even term = multiple of 3eg 2nd term= (2-1)*34th term=(4-1)*3so on so 100th term= 99*3 koi option nhi tha, laga glat hoga. So y is this wrong??
Each number is sum of distinct powers of 3.

Hence, these numbers consists of 0 and 1 €™s in base three, because, if there is 2 in their representation, then that number is not a sum of distinct powers of three.

Hence, the problem reduces to finding the hundredth number in base three which can be formed by using digits 0 and 1 only.

Now, 100 th number formed by using 0 and 1 only is simply the binary representation of 100.

As, 100 = (1100100)2

Hence, the required number = (1100100)3 = 981
There are 100 transistors in a box of which some are defective. At random, two transistors are consecutively taken out without replacement. A scientist wants to know the chances of exactly one of them being good and the other being defective. What number of defective transistors takes this chance below 30%?
OPTIONS

1) 19
2) 37
3) 71
4) 82
@vijay_chandola said:
Answer is D. Book k options are different. So, posted incorrectly C Arey darao mat yar! Edited the previous post. check it again
did not check the edited post earlier..thanks for posting the correct option..2 min ke liye dara diya tha aapne