|x – 3| 1
From |x| > 2 x > 2 or x
From |x – 1| –3 –2
As it is clear, neither of the statements is sufficient to answer the query.
Combining statements I and II:
x > 2 and –2 2 ?)
Hence, option D
Explanation of the previous Question:
@rkshtsurana said:1100100 yeh kese aaya 100 term..he toh nyc approach
@Brooklyn said:but i thot: each even term = multiple of 3eg 2nd term= (2-1)*34th term=(4-1)*3so on so 100th term= 99*3 koi option nhi tha, laga glat hoga. So y is this wrong??
@krum said:There are 100 transistors in a box of which some are defective. At random, two transistors are consecutively taken out without replacement. A scientist wants to know the chances of exactly one of them being good and the other being defective. What number of defective transistors takes this chance below 30%?OPTIONS1) 19 2) 37 3) 71 4) 82
82 ?
82*18/ 100c2 = 29.xx %
@soumitrabengeri said:37?
@rkshtsurana said:82 ?
let x defective
case -1 - p(first defective, other ok)
=>x/100*(100-x)/99
case 2 - p(first ok, 2nd defective)
=>(100-x)/100*x/99
total probability= x/100*(100-x)/99+(100-x)/100*x/99
put x=82
=>0.29 or 29%
case -1 - p(first defective, other ok)
=>x/100*(100-x)/99
case 2 - p(first ok, 2nd defective)
=>(100-x)/100*x/99
total probability= x/100*(100-x)/99+(100-x)/100*x/99
put x=82
=>0.29 or 29%
@krum said:There are 100 transistors in a box of which some are defective. At random, two transistors are consecutively taken out without replacement. A scientist wants to know the chances of exactly one of them being good and the other being defective. What number of defective transistors takes this chance below 30%?OPTIONS1) 19 2) 37 3) 71 4) 82
Let n be the number of defective pieces
required probability= n/100*(100-n)/99+(100-n)/100*n/99=2*n(100-n)/100*99
now, maximum probability can be 30%
=> 2*n(100-n)/100*99
=> n^2-100*n+1485
ab ise solve kr lo :P
82 h kya..?
How many pairs of positive integers m,n satisfy the equation 1/m+4/n = 1/12
Where n is an odd integer less than 60?
1) 6
2) 5
3) 3
4) 4
Please explain with approach
@soumitrabengeri said:How many pairs of positive integers m,n satisfy the equation 1/m+4/n = 1/12Where n is an odd integer less than 60?1) 62) 53) 34) 4Please explain with approach
is it 3 ? getting n as 49 51 and 57
@soumitrabengeri said:How many pairs of positive integers m,n satisfy the equation 1/m+4/n = 1/12Where n is an odd integer less than 60?1) 62) 53) 34) 4Please explain with approach
(n-48)(m-12)=48*12
=>1*576=>n=49
=>3*192=>n=51
=>9*64=>n=57
so 3?
=>1*576=>n=49
=>3*192=>n=51
=>9*64=>n=57
so 3?
@soumitrabengeri said:How many pairs of positive integers m,n satisfy the equation 1/m+4/n = 1/12Where n is an odd integer less than 60?1) 62) 53) 34) 4Please explain with approach
Answer is 3...
Approach::
the above equation reduces to 12n - mn + 48m = 0
as n is odd and less than 60, n cannot be less than 49..I mean n cannot be 47..as n=47 would mean m is negative..
Hence check for values 59, 57, 55, 53, 51 and 49.. and those who satisfy are 57, 51 and 49 
@soumitrabengeri said:correct hai bhai..approach bata na please
1/m + 4/n = 1/12
12n + 48 n = mn
12n = m(n-48)
12(n-48) + 12*48 = m(n-48)
(m-12)(n-48) = 12.48
now n >48
n = 49 , 51 , 57 pe m ki integers values aayegi
@krum said:(n-48)(m-12)=48*12=>1*576=>n=49=>3*192=>n=51=>9*64=>n=57so 3?
Got the equation wrong while solving..
3 is correct..thanks
@soumitrabengeri said:How many pairs of positive integers m,n satisfy the equation 1/m+4/n = 1/12Where n is an odd integer less than 60?1) 62) 53) 34) 4Please explain with approach
m = 12n / n-48
only 3 values of n satisfy => 49,51,57
only 3 values of n satisfy => 49,51,57
in how many ways 720 can be represented as a product of two NATURAL NO.S?
@99_or_nothing said:in how many ways 720 can be represented as a product of two NATURAL NO.S?
720=2^4*3^2*5
no of factors=5*3*2=30
so 30/2=15 ways
no of factors=5*3*2=30
so 30/2=15 ways
@99_or_nothing said:in how many ways 720 can be represented as a product of two NATURAL NO.S?
15 ways
@Anivesh90 IS DERE ADEFINITE PATTENR FOR EVERY NO.??
i mean does it hv anythng to do with the no. of factors??
i mean does it hv anythng to do with the no. of factors??
@99_or_nothing said:@Anivesh90 IS DERE ADEFINITE PATTENR FOR EVERY NO.??i mean does it hv anythng to do with the no. of factors??
Yes its-->
No. of factors/2